I noticed that when I place a white or black UIImage into a UISegmentedControl it automatically color masks it to match the tint of the segmented control. I thought this was really cool, and was wondering if I could do this elsewhere as well. For example, I have a bunch of buttons that have a uniform shape but varied colors. Instead of making a PNG for each button, could I somehow use this color masking to use the same image for all of them but then set a tint color or something to change their actual color?
当前回答
在Swift中,你可以这样做:
var exampleImage = UIImage(named: "ExampleImage.png")?.imageWithRenderingMode(.AlwaysTemplate)
然后在viewDidLoad中
exampleButtonOutlet.setImage(exampleImage, forState: UIControlState.Normal)
并修改颜色
exampleButtonOutlet.tintColor = UIColor(red: 1, green: 0, blue: 0, alpha: 1) //your color
编辑Xcode 8 现在你也可以在你的.xcassets to Template image中设置图像的呈现模式,然后你就不需要在var exampleImage中特别声明它了
其他回答
为了让tintColor影响UIImage,你必须将图像渲染模式设置为UIImageRenderingModeAlwaysTemplate。以下是Swift中的解决方案:
let image = UIImage(named: "image-name")
let button = UIButton()
button.setImage(image?.imageWithRenderingMode(UIImageRenderingMode.AlwaysTemplate), forState: .Normal)
button.tintColor = UIColor.whiteColor()
快4倍
button.setImage(image.withRenderingMode(UIImage.RenderingMode.alwaysTemplate), for: .normal)
button.tintColor = UIColor.blue
如果你想手动屏蔽你的图像,这里是更新的代码,适用于视网膜屏幕
- (UIImage *)maskWithColor:(UIColor *)color
{
CGImageRef maskImage = self.CGImage;
CGFloat width = self.size.width * self.scale;
CGFloat height = self.size.height * self.scale;
CGRect bounds = CGRectMake(0,0,width,height);
CGColorSpaceRef colorSpace = CGColorSpaceCreateDeviceRGB();
CGContextRef bitmapContext = CGBitmapContextCreate(NULL, width, height, 8, 0, colorSpace, kCGBitmapAlphaInfoMask & kCGImageAlphaPremultipliedLast);
CGContextClipToMask(bitmapContext, bounds, maskImage);
CGContextSetFillColorWithColor(bitmapContext, color.CGColor);
CGContextFillRect(bitmapContext, bounds);
CGImageRef cImage = CGBitmapContextCreateImage(bitmapContext);
UIImage *coloredImage = [UIImage imageWithCGImage:cImage scale:self.scale orientation:self.imageOrientation];
CGContextRelease(bitmapContext);
CGColorSpaceRelease(colorSpace);
CGImageRelease(cImage);
return coloredImage;
}
在Swift中,你可以这样做:
var exampleImage = UIImage(named: "ExampleImage.png")?.imageWithRenderingMode(.AlwaysTemplate)
然后在viewDidLoad中
exampleButtonOutlet.setImage(exampleImage, forState: UIControlState.Normal)
并修改颜色
exampleButtonOutlet.tintColor = UIColor(red: 1, green: 0, blue: 0, alpha: 1) //your color
编辑Xcode 8 现在你也可以在你的.xcassets to Template image中设置图像的呈现模式,然后你就不需要在var exampleImage中特别声明它了
Xamarin的。iOS (c#):
UIButton messagesButton = new UIButton(UIButtonType.Custom);
UIImage icon = UIImage.FromBundle("Images/icon.png");
messagesButton.SetImage(icon.ImageWithRenderingMode(UIImageRenderingMode.AlwaysTemplate), UIControlState.Normal);
messagesButton.TintColor = UIColor.White;
messagesButton.Frame = new RectangleF(0, 0, 25, 25);
不确定你到底想要什么,但这个category方法会用指定的颜色掩盖一个UIImage,所以你可以有一个单独的图像,改变它的颜色为任何你想要的。
ImageUtils.h
- (UIImage *) maskWithColor:(UIColor *)color;
ImageUtils.m
-(UIImage *) maskWithColor:(UIColor *)color
{
CGImageRef maskImage = self.CGImage;
CGFloat width = self.size.width;
CGFloat height = self.size.height;
CGRect bounds = CGRectMake(0,0,width,height);
CGColorSpaceRef colorSpace = CGColorSpaceCreateDeviceRGB();
CGContextRef bitmapContext = CGBitmapContextCreate(NULL, width, height, 8, 0, colorSpace, kCGImageAlphaPremultipliedLast);
CGContextClipToMask(bitmapContext, bounds, maskImage);
CGContextSetFillColorWithColor(bitmapContext, color.CGColor);
CGContextFillRect(bitmapContext, bounds);
CGImageRef cImage = CGBitmapContextCreateImage(bitmapContext);
UIImage *coloredImage = [UIImage imageWithCGImage:cImage];
CGContextRelease(bitmapContext);
CGColorSpaceRelease(colorSpace);
CGImageRelease(cImage);
return coloredImage;
}
导入ImageUtils类别并执行如下操作…
#import "ImageUtils.h"
...
UIImage *icon = [UIImage imageNamed:ICON_IMAGE];
UIImage *redIcon = [icon maskWithColor:UIColor.redColor];
UIImage *blueIcon = [icon maskWithColor:UIColor.blueColor];
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