知道一个函数需要多少个参数

function add_nums(num1, num2, num3 ){
    return num1 + num2 + num3;
}
add_nums.length // 3 is the number of parameters expected.

知道函数接收了多少参数

function add_many_nums(){
    return arguments.length;
}    
add_many_nums(2,1,122,12,21,89); //returns 6

访问:

http://images.google.com/images?q=disco

将以下JavaScript代码粘贴到浏览器的地址栏:

http://amix.dk/upload/awt/spin.txt http://amix.dk/upload/awt/disco.txt

享受JavaScript的迪斯科表演:-p

要正确地从对象中删除一个属性，你应该删除该属性，而不是仅仅将其设置为undefined:

var obj = { prop1: 42, prop2: 43 };

obj.prop2 = undefined;

for (var key in obj) {
    ...

prop2属性仍然是迭代的一部分。如果你想完全摆脱prop2，你应该这样做:

delete obj.prop2;

在遍历属性时，prop2属性将不再出现。

Javascript在函数中有静态变量:

function someFunction(){
  var Static = arguments.callee;
  Static.someStaticVariable = (Static.someStaticVariable || 0) + 1;
  alert(Static.someStaticVariable);
}
someFunction() //Alerts 1
someFunction() //Alerts 2
someFunction() //Alerts 3

它在Objects内部也有静态变量:

function Obj(){
  this.Static = arguments.callee;
}
a = new Obj();
a.Static.name = "a";
b = new Obj();
alert(b.Static.name); //Alerts b

在Crockford的《Javascript: The Good Parts》中也提到过:

parseInt()是危险的。如果你给它一个字符串而不告诉它正确的进制，它可能会返回意想不到的数字。例如，parseInt('010')返回8，而不是10。传递一个base给parseInt可以使它正确工作:

parseInt('010') // returns 8! (in FF3)
parseInt('010', 10); // returns 10 because we've informed it which base to work with.

let.

与var缺乏块作用域对应的是let，在JavaScript 1.7中引入。

The let statement provides a way to associate values with variables within the scope of a block, without affecting the values of like-named variables outside the block. The let expression lets you establish variables scoped only to a single expression. The let definition defines variables whose scope is constrained to the block in which they're defined. This syntax is very much like the syntax used for var. You can also use let to establish variables that exist only within the context of a for loop.

  function varTest() {
        var x = 31;
    if (true) {
      var x = 71;  // same variable!
      alert(x);  // 71
    }
    alert(x);  // 71
  }

  function letTest() {
    let x = 31;
    if (true) {
      let x = 71;  // different variable
      alert(x);  // 71
    }
    alert(x);  // 31
  }

截至2008年，FireFox 2.0+和Safari 3.x支持JavaScript 1.7。