我正在使用Firebase并测试在应用程序处于后台时从服务器发送通知到我的应用程序。通知发送成功,它甚至出现在设备的通知中心,但当通知出现或即使我点击它,我的FCMessagingService中的onmessagerreceived方法永远不会被调用。

当我测试这个,而我的应用程序是在前台,onmessagerreceived方法被调用,一切工作正常。问题发生在应用程序在后台运行时。

这是我有意为之的行为吗,或者我有办法解决这个问题吗?

这是我的FBMessagingService:

import android.util.Log;

import com.google.firebase.messaging.FirebaseMessagingService;
import com.google.firebase.messaging.RemoteMessage;

public class FBMessagingService extends FirebaseMessagingService {

    @Override
    public void onMessageReceived(RemoteMessage remoteMessage) {
        Log.i("PVL", "MESSAGE RECEIVED!!");
        if (remoteMessage.getNotification().getBody() != null) {
            Log.i("PVL", "RECEIVED MESSAGE: " + remoteMessage.getNotification().getBody());
        } else {
            Log.i("PVL", "RECEIVED MESSAGE: " + remoteMessage.getData().get("message"));
        }
    }
}

当前回答

看看@Mahesh Kavathiya的答案。对于我的情况,在服务器代码中只有这样:

{
"notification": {
  "body": "here is body",
  "title": "Title",
 },
 "to": "sdfjsdfonsdofoiewj9230idsjkfmnkdsfm"
}

您需要更改为:

{
 "data": {
  "body": "here is body",
  "title": "Title",
  "click_action": "YOUR_ACTION"
 },
"notification": {
  "body": "here is body",
  "title": "Title"
 },
 "to": "sdfjsdfonsdofoiewj9230idsjkfmnkdsfm"
}

然后,如果app在后台,默认的活动意图extra会得到"data"

好运!

其他回答

根据t3h Exi的解决方案,我想在这里发布干净的代码。只要把它放入MyFirebaseMessagingService,如果应用程序处于后台模式,一切都可以正常工作。您至少需要编译com.google.firebase:firebase-messaging:10.2.1

 @Override
public void handleIntent(Intent intent)
{
    try
    {
        if (intent.getExtras() != null)
        {
            RemoteMessage.Builder builder = new RemoteMessage.Builder("MyFirebaseMessagingService");

            for (String key : intent.getExtras().keySet())
            {
                builder.addData(key, intent.getExtras().get(key).toString());
            }



           onMessageReceived(builder.build());
        }
        else
        {
            super.handleIntent(intent);
        }
    }
    catch (Exception e)
    {
        super.handleIntent(intent);
    }
}

根据Firebase云消息文档-如果Activity在前台,那么onmessagerecreceived将被调用。如果Activity处于后台或关闭,则通知消息将显示在应用程序启动器活动的通知中心。 你可以调用你的自定义活动点击通知,如果你的应用程序是在后台调用rest服务api为firebase消息:

URL-https: / / fcm.googleapis.com/fcm/send

方法类型- POST

Header- Content-Type:application/json
Authorization:key=your api key

车身/有效载荷:

{ "notification": {
    "title": "Your Title",
    "text": "Your Text",
     "click_action": "OPEN_ACTIVITY_1" // should match to your intent filter
  },
    "data": {
    "keyname": "any value " //you can get this data as extras in your activity and this data is optional
    },
  "to" : "to_id(firebase refreshedToken)"
} 

在你的应用程序中,你可以添加以下代码在你的活动中被调用:

<intent-filter>
                <action android:name="OPEN_ACTIVITY_1" />
                <category android:name="android.intent.category.DEFAULT" />
            </intent-filter>

如果你的问题与显示大图有关,例如,如果你从firebase控制台发送带有图像的推送通知,它只在应用程序在前台时显示图像。这个问题的解决方案是发送一个只有数据字段的推送消息。就像这样:

{ "data": { "image": "https://static.pexels.com/photos/4825/red-love-romantic-flowers.jpg", "message": "Firebase Push Message Using API" "AnotherActivity": "True" }, "to" : "device id Or Device token" }

重写FirebaseMessageService的handleIntent方法对我有用。

下面是c#代码(Xamarin)

public override void HandleIntent(Intent intent)
{
    try
    {
        if (intent.Extras != null)
        {
            var builder = new RemoteMessage.Builder("MyFirebaseMessagingService");

            foreach (string key in intent.Extras.KeySet())
            {
                builder.AddData(key, intent.Extras.Get(key).ToString());
            }

            this.OnMessageReceived(builder.Build());
        }
        else
        {
            base.HandleIntent(intent);
        }
    }
    catch (Exception)
    {
        base.HandleIntent(intent);
    }
}

这就是Java代码

public void handleIntent(Intent intent)
{
    try
    {
        if (intent.getExtras() != null)
        {
            RemoteMessage.Builder builder = new RemoteMessage.Builder("MyFirebaseMessagingService");

            for (String key : intent.getExtras().keySet())
            {
                builder.addData(key, intent.getExtras().get(key).toString());
            }

            onMessageReceived(builder.build());
        }
        else
        {
            super.handleIntent(intent);
        }
    }
    catch (Exception e)
    {
        super.handleIntent(intent);
    }
}

消息有两种类型:通知消息和数据消息。 如果你只发送数据消息,那就是在你的消息字符串中没有通知对象。它会在应用程序在后台时被调用。