我已经用下面这个成语有一段时间了。这似乎是传播最广的,至少在我访问过的网站上。
在Java中有没有更好/不同的方法将文件读入字符串?
private String readFile(String file) throws IOException {
BufferedReader reader = new BufferedReader(new FileReader (file));
String line = null;
StringBuilder stringBuilder = new StringBuilder();
String ls = System.getProperty("line.separator");
try {
while((line = reader.readLine()) != null) {
stringBuilder.append(line);
stringBuilder.append(ls);
}
return stringBuilder.toString();
} finally {
reader.close();
}
}
我还不能评论其他条目,所以我就把它留在这里。
这里最好的答案之一(https://stackoverflow.com/a/326448/1521167):
private String readFile(String pathname) throws IOException {
File file = new File(pathname);
StringBuilder fileContents = new StringBuilder((int)file.length());
Scanner scanner = new Scanner(file);
String lineSeparator = System.getProperty("line.separator");
try {
while(scanner.hasNextLine()) {
fileContents.append(scanner.nextLine() + lineSeparator);
}
return fileContents.toString();
} finally {
scanner.close();
}
}
仍然有一个缺陷。它总是在字符串末尾添加换行符,这可能会导致一些奇怪的错误。我的建议是将其更改为:
private String readFile(String pathname) throws IOException {
File file = new File(pathname);
StringBuilder fileContents = new StringBuilder((int) file.length());
Scanner scanner = new Scanner(new BufferedReader(new FileReader(file)));
String lineSeparator = System.getProperty("line.separator");
try {
if (scanner.hasNextLine()) {
fileContents.append(scanner.nextLine());
}
while (scanner.hasNextLine()) {
fileContents.append(lineSeparator + scanner.nextLine());
}
return fileContents.toString();
} finally {
scanner.close();
}
}
如果您需要字符串处理(并行处理),Java8有很棒的StreamAPI。
String result = Files.lines(Paths.get("file.txt"))
.parallel() // for parallel processing
.map(String::trim) // to change line
.filter(line -> line.length() > 2) // to filter some lines by a predicate
.collect(Collectors.joining()); // to join lines
JDK示例samples/lambda/BulkDataOperations中提供了更多示例,可以从Oracle Java SE 8下载页面下载
另一个单线示例
String out = String.join("\n", Files.readAllLines(Paths.get("file.txt")));