同样在python3中，你可能会发现使用Extended Iterable Unpacking来处理可选的位置参数很方便，没有额外的依赖关系:

try:
   _, arg1, arg2, arg3, *_ = sys.argv + [None] * 2
except ValueError:
   print("Not enough arguments", file=sys.stderr) # unhandled exception traceback is meaningful enough also
   exit(-1)

上面的argv解包使arg2和arg3成为“可选的”——如果在argv中没有指定它们，它们将是None，而如果没有指定第一个，ValueError将被解析:

Traceback (most recent call last):
  File "test.py", line 3, in <module>
    _, arg1, arg2, arg3, *_ = sys.argv + [None] * 2
ValueError: not enough values to unpack (expected at least 4, got 3)

还有一个选项是argh。它建立在argparse的基础上，让你可以写这样的东西:

import argh

# declaring:

def echo(text):
    "Returns given word as is."
    return text

def greet(name, greeting='Hello'):
    "Greets the user with given name. The greeting is customizable."
    return greeting + ', ' + name

# assembling:

parser = argh.ArghParser()
parser.add_commands([echo, greet])

# dispatching:

if __name__ == '__main__':
    parser.dispatch()

它将自动生成帮助等等，您可以使用装饰器来提供关于参数解析应该如何工作的额外指导。

import sys

print("\n".join(sys.argv))

sys。Argv是一个列表，它包含在命令行上传递给脚本的所有参数。sys。Argv[0]为脚本名称。

基本上,

import sys
print(sys.argv[1:])

正如你所看到的，optparse模块已被弃用，不会再进一步开发;argparse模块将继续开发。”

我的解是入口点2。例子:

from entrypoint2 import entrypoint
@entrypoint
def add(file, quiet=True): 
    ''' This function writes report.

    :param file: write report to FILE
    :param quiet: don't print status messages to stdout
    '''
    print file,quiet

帮助文本:

usage: report.py [-h] [-q] [--debug] file

This function writes report.

positional arguments:
  file         write report to FILE

optional arguments:
  -h, --help   show this help message and exit
  -q, --quiet  don't print status messages to stdout
  --debug      set logging level to DEBUG

import argparse

parser = argparse.ArgumentParser(description='Process some integers.')
parser.add_argument('integers', metavar='N', type=int, nargs='+',
                   help='an integer for the accumulator')
parser.add_argument('--sum', dest='accumulate', action='store_const',
                   const=sum, default=max,
                   help='sum the integers (default: find the max)')

args = parser.parse_args()
print(args.accumulate(args.integers))

Assuming the Python code above is saved into a file called prog.py
$ python prog.py -h

Ref-link: https://docs.python.org/3.3/library/argparse.html