实际上,我想读取搜索查询之后的内容,当它完成时。问题是URL只接受POST方法,它不采取任何行动与GET方法…
我必须在domdocument或file_get_contents()的帮助下读取所有内容。有没有什么方法可以让我用POST方法发送参数,然后通过PHP读取内容?
实际上,我想读取搜索查询之后的内容,当它完成时。问题是URL只接受POST方法,它不采取任何行动与GET方法…
我必须在domdocument或file_get_contents()的帮助下读取所有内容。有没有什么方法可以让我用POST方法发送参数,然后通过PHP读取内容?
当前回答
我更喜欢这个:
function curlPost($url, $data = NULL, $headers = []) {
$ch = curl_init($url);
curl_setopt($ch, CURLOPT_USERAGENT, 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/63.0.3239.132 Safari/537.36');
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, true);
curl_setopt($ch, CURLOPT_TIMEOUT, 5); //timeout in seconds
curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, 0);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, 0);
curl_setopt($ch, CURLOPT_ENCODING, 'identity');
if (!empty($data)) {
curl_setopt($ch, CURLOPT_POSTFIELDS, $data);
}
if (!empty($headers)) {
curl_setopt($ch, CURLOPT_HTTPHEADER, $headers);
}
$response = curl_exec($ch);
if (curl_error($ch)) {
trigger_error('Curl Error:' . curl_error($ch));
}
curl_close($ch);
return $response;
}
使用的例子:
$response=curlPost("http://my.url.com", ["myField1"=>"myValue1"], ["myFitstHeaderName"=>"myFirstHeaderValue"]);
其他回答
PHP5的无卷曲方法:
$url = 'http://server.com/path';
$data = array('key1' => 'value1', 'key2' => 'value2');
// use key 'http' even if you send the request to https://...
$options = array(
'http' => array(
'header' => "Content-type: application/x-www-form-urlencoded\r\n",
'method' => 'POST',
'content' => http_build_query($data)
)
);
$context = stream_context_create($options);
$result = file_get_contents($url, false, $context);
if ($result === FALSE) { /* Handle error */ }
var_dump($result);
有关该方法和如何添加头的更多信息,请参阅PHP手册,例如:
stream_context_create: http://php.net/manual/en/function.stream-context-create.php
上面的答案对我不起作用。这是第一个完美运行的解决方案:
$sPD = "name=Jacob&bench=150"; // The POST Data
$aHTTP = array(
'http' => // The wrapper to be used
array(
'method' => 'POST', // Request Method
// Request Headers Below
'header' => 'Content-type: application/x-www-form-urlencoded',
'content' => $sPD
)
);
$context = stream_context_create($aHTTP);
$contents = file_get_contents($sURL, false, $context);
echo $contents;
你可以使用cURL:
<?php
//The url you wish to send the POST request to
$url = $file_name;
//The data you want to send via POST
$fields = [
'__VIEWSTATE ' => $state,
'__EVENTVALIDATION' => $valid,
'btnSubmit' => 'Submit'
];
//url-ify the data for the POST
$fields_string = http_build_query($fields);
//open connection
$ch = curl_init();
//set the url, number of POST vars, POST data
curl_setopt($ch,CURLOPT_URL, $url);
curl_setopt($ch,CURLOPT_POST, true);
curl_setopt($ch,CURLOPT_POSTFIELDS, $fields_string);
//So that curl_exec returns the contents of the cURL; rather than echoing it
curl_setopt($ch,CURLOPT_RETURNTRANSFER, true);
//execute post
$result = curl_exec($ch);
echo $result;
?>
用PHP发送GET或POST请求的更好方法如下:
<?php
$r = new HttpRequest('http://example.com/form.php', HttpRequest::METH_POST);
$r->setOptions(array('cookies' => array('lang' => 'de')));
$r->addPostFields(array('user' => 'mike', 'pass' => 's3c|r3t'));
try {
echo $r->send()->getBody();
} catch (HttpException $ex) {
echo $ex;
}
?>
代码摘自官方文档http://docs.php.net/manual/da/httprequest.send.php
我使用下面的函数来使用curl发布数据。$data是一个要发布的字段数组(将使用http_build_query()正确编码)。
function httpPost($url, $data)
{
$curl = curl_init($url);
curl_setopt($curl, CURLOPT_POST, true);
curl_setopt($curl, CURLOPT_POSTFIELDS, http_build_query($data));
curl_setopt($curl, CURLOPT_RETURNTRANSFER, true);
$response = curl_exec($curl);
curl_close($curl);
return $response;
}
@Edward提到http_build_query()可能被省略,因为curl将正确编码传递给CURLOPT_POSTFIELDS参数的数组,这是正确的,但请注意,在这种情况下,数据将使用multipart/form-data进行编码,这可能不可取,因为一些端点希望数据使用application/x-www-form-urlencoded进行编码。当像上面的函数一样使用http_build_query()时,数据将使用application/x-www-form-urlencoded进行编码。