删除重复记录

在这种情况下，大于操作符删除除第一条记录以外的所有记录

u1 FROM users u1 JOIN users u2 u1的地方。Id > u2.id 和u1.email = u2.email

<小于操作符在这种情况下删除除最后一条记录以外的所有记录

u1 FROM users u1 JOIN users u2 u1的地方。Id < u2.id 和u1.email = u2.email

通过使用下面的查询，我们可以基于单列或多列删除重复的记录。下面的查询是基于两列进行删除。表名为:testing，列名为empno,empname

DELETE FROM testing WHERE empno not IN (SELECT empno FROM (SELECT empno, ROW_NUMBER() OVER (PARTITION BY empno ORDER BY empno) 
AS [ItemNumber] FROM testing) a WHERE ItemNumber > 1)
or empname not in
(select empname from (select empname,row_number() over(PARTITION BY empno ORDER BY empno) 
AS [ItemNumber] FROM testing) a WHERE ItemNumber > 1)

对于表结构

MyTable

RowID int not null identity(1,1) primary key,
Col1 varchar(20) not null,
Col2 varchar(2048) not null,
Col3 tinyint not null

删除重复项的查询:

DELETE t1
FROM MyTable t1
INNER JOIN MyTable t2
WHERE t1.RowID > t2.RowID
  AND t1.Col1 = t2.Col1
  AND t1.Col2=t2.Col2
  AND t1.Col3=t2.Col3;

我假设RowID是一种自动递增，其余列有重复的值。

DELETE
FROM
    table_name T1
WHERE
    rowid > (
        SELECT
            min(rowid)
        FROM
            table_name T2
        WHERE
            T1.column_name = T2.column_name
    );

DELETE LU 
FROM   (SELECT *, 
               Row_number() 
                 OVER ( 
                   partition BY col1, col1, col3 
                   ORDER BY rowid DESC) [Row] 
        FROM   mytable) LU 
WHERE  [row] > 1 

我想我应该分享我的解决方案，因为它在特殊情况下是有效的。 在我的例子中，有重复值的表没有外键(因为这些值是从另一个db复制的)。

begin transaction
-- create temp table with identical structure as source table
Select * Into #temp From tableName Where 1 = 2

-- insert distinct values into temp
insert into #temp 
select distinct * 
from  tableName

-- delete from source
delete from tableName 

-- insert into source from temp
insert into tableName 
select * 
from #temp

rollback transaction
-- if this works, change rollback to commit and execute again to keep you changes!!

PS:在处理这样的事情时，我总是使用事务，这不仅确保了所有事情都作为一个整体执行，而且还允许我在没有任何风险的情况下进行测试。但是当然你应该做个备份，以防万一……