我遇到了用LINQ和Lambda编写的查询的麻烦。到目前为止,我得到了很多错误,这是我的代码:
int id = 1;
var query = database.Posts.Join(database.Post_Metas,
post => database.Posts.Where(x => x.ID == id),
meta => database.Post_Metas.Where(x => x.Post_ID == id),
(post, meta) => new { Post = post, Meta = meta });
我不确定这个问题是否正确。
我做过类似的事情;
var certificationClass = _db.INDIVIDUALLICENSEs
.Join(_db.INDLICENSECLAsses,
IL => IL.LICENSE_CLASS,
ILC => ILC.NAME,
(IL, ILC) => new { INDIVIDUALLICENSE = IL, INDLICENSECLAsse = ILC })
.Where(o =>
o.INDIVIDUALLICENSE.GLOBALENTITYID == "ABC" &&
o.INDIVIDUALLICENSE.LICENSE_TYPE == "ABC")
.Select(t => new
{
value = t.PSP_INDLICENSECLAsse.ID,
name = t.PSP_INDIVIDUALLICENSE.LICENSE_CLASS,
})
.OrderBy(x => x.name);
这个linq查询应该为您工作。它会得到所有有post meta的帖子。
var query = database.Posts.Join(database.Post_Metas,
post => post.postId, // Primary Key
meta => meat.postId, // Foreign Key
(post, meta) => new { Post = post, Meta = meta });
等价SQL查询
Select * FROM Posts P
INNER JOIN Post_Metas pm ON pm.postId=p.postId
我做过类似的事情;
var certificationClass = _db.INDIVIDUALLICENSEs
.Join(_db.INDLICENSECLAsses,
IL => IL.LICENSE_CLASS,
ILC => ILC.NAME,
(IL, ILC) => new { INDIVIDUALLICENSE = IL, INDLICENSECLAsse = ILC })
.Where(o =>
o.INDIVIDUALLICENSE.GLOBALENTITYID == "ABC" &&
o.INDIVIDUALLICENSE.LICENSE_TYPE == "ABC")
.Select(t => new
{
value = t.PSP_INDLICENSECLAsse.ID,
name = t.PSP_INDIVIDUALLICENSE.LICENSE_CLASS,
})
.OrderBy(x => x.name);
我发现如果你熟悉SQL语法,使用LINQ查询语法会更清晰、更自然,并且更容易发现错误:
var id = 1;
var query =
from post in database.Posts
join meta in database.Post_Metas on post.ID equals meta.Post_ID
where post.ID == id
select new { Post = post, Meta = meta };
如果您真的坚持使用lambdas,那么您的语法就有很大的问题。下面是相同的查询,使用LINQ扩展方法:
var id = 1;
var query = database.Posts // your starting point - table in the "from" statement
.Join(database.Post_Metas, // the source table of the inner join
post => post.ID, // Select the primary key (the first part of the "on" clause in an sql "join" statement)
meta => meta.Post_ID, // Select the foreign key (the second part of the "on" clause)
(post, meta) => new { Post = post, Meta = meta }) // selection
.Where(postAndMeta => postAndMeta.Post.ID == id); // where statement