下面是一个(纯纯的JS)函数，它执行大量的检查，确保给定的元素对用户可见:

function isVisible(element) {
    // Check if the element is null or undefined
    if (!element) return false;

    // Get the element's bounding client rect
    const boundingRect = element.getBoundingClientRect();

    // Check if the element has a positive width and height
    if (boundingRect.width <= 0 || boundingRect.height <= 0) return false;

    // Check if the element's top and left values are within the viewport
    const top = boundingRect.top;
    const left = boundingRect.left;
    const viewportWidth = window.innerWidth || document.documentElement.clientWidth;
    const viewportHeight = window.innerHeight || document.documentElement.clientHeight;
    if (top > viewportHeight || left > viewportWidth) return false;

    // Check if the element's right and bottom values are within the viewport
    const right = boundingRect.right;
    const bottom = boundingRect.bottom;
    if (right < 0 || bottom < 0) return false;

    // Check if the element is hidden by the overflow property
    const parentNode = element.parentNode;
    if (parentNode && getComputedStyle(parentNode).overflow === 'hidden') {
        const parentRect = parentNode.getBoundingClientRect();
        if (top < parentRect.top || bottom > parentRect.bottom || left < parentRect.left || right > parentRect.right) {
            return false;
        }
    }

    const elementComputedStyle = getComputedStyle(element);

    // Check if the element has a z-index of less than 0
    const zIndex = elementComputedStyle.zIndex;
    if (zIndex < 0) return false;

    // Check if the element has a display value of 'none' or an opacity of 0
    const display = elementComputedStyle.display;
    const opacity = elementComputedStyle.opacity;
    if (display === 'none' || opacity === '0') return false;

    // Check if the element is hidden by an ancestor element with a display value of 'none' or an opacity of 0
    let ancestorElement = element.parentElement;
    while (ancestorElement) {
        const ancestorComputedStyle = getComputedStyle(ancestorElement);
        const ancestorDisplay = ancestorComputedStyle.display;
        const ancestorOpacity = ancestorComputedStyle.opacity;
        if (ancestorDisplay === 'none' || ancestorOpacity === '0') return false;
        ancestorElement = ancestorElement.parentElement;
    }

    // Initialize a variable to keep track of whether the element is obscured by another element
    let obscured = false;

    // Check if the element is obscured by another element according to its position
    if (elementComputedStyle.position === 'absolute' || elementComputedStyle.position === 'fixed' ||
        elementComputedStyle.position === 'relative' || elementComputedStyle.position === 'sticky' ||
        elementComputedStyle.position === 'static') {
        let siblingElement = element.nextElementSibling;
        while (siblingElement) {
            if (siblingElement.getBoundingClientRect().top > boundingRect.bottom || siblingElement.getBoundingClientRect().left > boundingRect.right) {
                break;
            }
            if (siblingElement.getBoundingClientRect().bottom > boundingRect.top && siblingElement.getBoundingClientRect().right > boundingRect.left) {
                obscured = true;
                break;
            }
            siblingElement = siblingElement.nextElementSibling;
        }
        if (obscured) return false;
    }

    // If all checks have passed, the element is visible
    return true;
}

使用与jQuery相同的代码:

jQuery.expr.pseudos.visible = function( elem ) {
    return !!( elem.offsetWidth || elem.offsetHeight || elem.getClientRects().length );
};

在函数中:

function isVisible(e) {
    return !!( e.offsetWidth || e.offsetHeight || e.getClientRects().length );
}

在我的Win/IE10、Linux/Firefox中工作得很好。45岁的Linux / Chrome.52……

感谢没有jQuery的jQuery!

下面是我编写的代码，用于在几个类似的元素中找到唯一可见的元素，并返回其“class”属性的值，而不使用jQuery:

  // Build a NodeList:
  var nl = document.querySelectorAll('.myCssSelector');

  // convert it to array:
  var myArray = [];for(var i = nl.length; i--; myArray.unshift(nl[i]));

  // now find the visible (= with offsetWidth more than 0) item:
  for (i =0; i < myArray.length; i++){
    var curEl = myArray[i];
    if (curEl.offsetWidth !== 0){
      return curEl.getAttribute("class");
    }
  }

2021的解决方案

根据MDN文档，交互观察器异步观察目标元素与祖先元素或顶级文档视口的交集中的变化。这意味着每当元素与视口相交时，交互观察器就会触发。

截至2021年，除IE外，目前所有浏览器都支持交集观测器。

实现

const el = document.getElementById("your-target-element");
const observer = new IntersectionObserver((entries) => {
    if(entries[0].isIntersecting){
         // el is visible
    } else {
         // el is not visible
    }
});

observer.observe(el); // Asynchronous call

The handler will fire when initially created. And then it will fire every time that it becomes slightly visible or becomes completely not visible. An element is deemed to be not-visible when it's not actually visible within the viewport. So if you scroll down and element goes off the screen, then the observer will trigger and the // el is not visible code will be triggered - even though the element is still "displayed" (i.e. doesn't have display:none or visibility:hidden). What matters is whether there are any pixels of the element that are actually visible within the viewport.

如果我们只是收集检测能见度的基本方法，让我不要忘记:

opacity > 0.01; // probably more like .1 to actually be visible, but YMMV

至于如何获取属性:

element.getAttribute(attributename);

所以，在你的例子中:

document.getElementById('snDealsPanel').getAttribute('visibility');

But wha? It doesn't work here. Look closer and you'll find that visibility is being updated not as an attribute on the element, but using the style property. This is one of many problems with trying to do what you're doing. Among others: you can't guarantee that there's actually something to see in an element, just because its visibility, display, and opacity all have the correct values. It still might lack content, or it might lack a height and width. Another object might obscure it. For more detail, a quick Google search reveals this, and even includes a library to try solving the problem. (YMMV)

看看下面的问题，它们可能是这个问题的副本，有很好的答案，包括来自强大的约翰·雷西格的一些见解。但是，您的特定用例与标准用例略有不同，因此我将避免标记:

如何判断一个DOM元素是否在当前视口中可见? 如何检查一个元素是否真的可见javascript?

(EDIT: OP SAYS HE'S SCRAPING PAGES, NOT CREATING THEM, SO BELOW ISN'T APPLICABLE) A better option? Bind the visibility of elements to model properties and always make visibility contingent on that model, much as Angular does with ng-show. You can do that using any tool you want: Angular, plain JS, whatever. Better still, you can change the DOM implementation over time, but you'll always be able to read state from the model, instead of the DOM. Reading your truth from the DOM is Bad. And slow. Much better to check the model, and trust in your implementation to ensure that the DOM state reflects the model. (And use automated testing to confirm that assumption.)

为了详细说明大家的精彩回答，下面是Mozilla Fathom项目中使用的实现:

/**
 * Yield an element and each of its ancestors.
 */
export function *ancestors(element) {
    yield element;
    let parent;
    while ((parent = element.parentNode) !== null && parent.nodeType === parent.ELEMENT_NODE) {
        yield parent;
        element = parent;
    }
}

/**
 * Return whether an element is practically visible, considering things like 0
 * size or opacity, ``visibility: hidden`` and ``overflow: hidden``.
 *
 * Merely being scrolled off the page in either horizontally or vertically
 * doesn't count as invisible; the result of this function is meant to be
 * independent of viewport size.
 *
 * @throws {Error} The element (or perhaps one of its ancestors) is not in a
 *     window, so we can't find the `getComputedStyle()` routine to call. That
 *     routine is the source of most of the information we use, so you should
 *     pick a different strategy for non-window contexts.
 */
export function isVisible(fnodeOrElement) {
    // This could be 5x more efficient if https://github.com/w3c/csswg-drafts/issues/4122 happens.
    const element = toDomElement(fnodeOrElement);
    const elementWindow = windowForElement(element);
    const elementRect = element.getBoundingClientRect();
    const elementStyle = elementWindow.getComputedStyle(element);
    // Alternative to reading ``display: none`` due to Bug 1381071.
    if (elementRect.width === 0 && elementRect.height === 0 && elementStyle.overflow !== 'hidden') {
        return false;
    }
    if (elementStyle.visibility === 'hidden') {
        return false;
    }
    // Check if the element is irrevocably off-screen:
    if (elementRect.x + elementRect.width < 0 ||
        elementRect.y + elementRect.height < 0
    ) {
        return false;
    }
    for (const ancestor of ancestors(element)) {
        const isElement = ancestor === element;
        const style = isElement ? elementStyle : elementWindow.getComputedStyle(ancestor);
        if (style.opacity === '0') {
            return false;
        }
        if (style.display === 'contents') {
            // ``display: contents`` elements have no box themselves, but children are
            // still rendered.
            continue;
        }
        const rect = isElement ? elementRect : ancestor.getBoundingClientRect();
        if ((rect.width === 0 || rect.height === 0) && elementStyle.overflow === 'hidden') {
            // Zero-sized ancestors don’t make descendants hidden unless the descendant
            // has ``overflow: hidden``.
            return false;
        }
    }
    return true;
}

它检查每个父元素的不透明度、显示和矩形。