我有两个JavaScript数组:
var array1 = ["Vijendra","Singh"];
var array2 = ["Singh", "Shakya"];
我希望输出为:
var array3 = ["Vijendra","Singh","Shakya"];
输出数组应删除重复的单词。
如何在JavaScript中合并两个数组,以便从每个数组中只获得唯一的项目,其顺序与它们插入原始数组的顺序相同?
我有两个JavaScript数组:
var array1 = ["Vijendra","Singh"];
var array2 = ["Singh", "Shakya"];
我希望输出为:
var array3 = ["Vijendra","Singh","Shakya"];
输出数组应删除重复的单词。
如何在JavaScript中合并两个数组,以便从每个数组中只获得唯一的项目,其顺序与它们插入原始数组的顺序相同?
当前回答
var MergeArrays=function(arrayOne, arrayTwo, equalityField) {
var mergeDictionary = {};
for (var i = 0; i < arrayOne.length; i++) {
mergeDictionary[arrayOne[i][equalityField]] = arrayOne[i];
}
for (var i = 0; i < arrayTwo.length; i++) {
mergeDictionary[arrayTwo[i][equalityField]] = arrayTwo[i];
}
return $.map(mergeDictionary, function (value, key) { return value });
}
利用字典和Jquery,您可以合并这两个数组,而不会得到重复项。在我的示例中,我在对象上使用给定的字段,但可能只是对象本身。
其他回答
在Dojo 1.6中+
var unique = [];
var array1 = ["Vijendra","Singh"];
var array2 = ["Singh", "Shakya"];
var array3 = array1.concat(array2); // Merged both arrays
dojo.forEach(array3, function(item) {
if (dojo.indexOf(unique, item) > -1) return;
unique.push(item);
});
使现代化
参见工作代码。
http://jsfiddle.net/UAxJa/1/
var array1=[“一”,“二”];var array2=[“two”,“three”];var collectionOfTwoArrays=[…array1,…array2];var uniqueList=array=>[…new Set(array)];console.log('集合:');console.log(collectionOfTwoArrays);console.log('没有重复项的集合:');console.log(uniqueList(collectionOfTwoArrays));
取两个数组a和b
var a = ['a','b','c'];
var b = ['d','e','f'];
var c = a.concat(b);
//c is now an an array with: ['a','b','c','d','e','f']
var MergeArrays=function(arrayOne, arrayTwo, equalityField) {
var mergeDictionary = {};
for (var i = 0; i < arrayOne.length; i++) {
mergeDictionary[arrayOne[i][equalityField]] = arrayOne[i];
}
for (var i = 0; i < arrayTwo.length; i++) {
mergeDictionary[arrayTwo[i][equalityField]] = arrayTwo[i];
}
return $.map(mergeDictionary, function (value, key) { return value });
}
利用字典和Jquery,您可以合并这两个数组,而不会得到重复项。在我的示例中,我在对象上使用给定的字段,但可能只是对象本身。
[...array1,...array2] // => don't remove duplication
OR
[...new Set([...array1 ,...array2])]; // => remove duplication