我有两个JavaScript数组:
var array1 = ["Vijendra","Singh"];
var array2 = ["Singh", "Shakya"];
我希望输出为:
var array3 = ["Vijendra","Singh","Shakya"];
输出数组应删除重复的单词。
如何在JavaScript中合并两个数组,以便从每个数组中只获得唯一的项目,其顺序与它们插入原始数组的顺序相同?
我有两个JavaScript数组:
var array1 = ["Vijendra","Singh"];
var array2 = ["Singh", "Shakya"];
我希望输出为:
var array3 = ["Vijendra","Singh","Shakya"];
输出数组应删除重复的单词。
如何在JavaScript中合并两个数组,以便从每个数组中只获得唯一的项目,其顺序与它们插入原始数组的顺序相同?
当前回答
假设原始阵列不需要重复数据消除,这应该非常快,保持原始顺序,并且不会修改原始阵列。。。
function arrayMerge(base, addendum){
var out = [].concat(base);
for(var i=0,len=addendum.length;i<len;i++){
if(base.indexOf(addendum[i])<0){
out.push(addendum[i]);
}
}
return out;
}
用法:
var array1 = ["Vijendra","Singh"];
var array2 = ["Singh", "Shakya"];
var array3 = arrayMerge(array1, array2);
console.log(array3);
//-> [ 'Vijendra', 'Singh', 'Shakya' ]
其他回答
只需避开嵌套循环(O(n^2))和.indexOf()(+O(n))。
函数合并(a,b){var哈希={};变量i;对于(i=0;i<a.length;i++){hash[a[i]=真;}对于(i=0;i<b.length;i++){hash[b[i]]=真;}return Object.keys(哈希);}var array1=[“Vijendra”,“Singh”];var array2=[“Singh”,“Shakya”];var array3=合并(array1,array2);console.log(array3);
使用集合(ECMAScript 2015),将非常简单:
const array1=[“Vijendra”,“Singh”];const array2=[“Singh”,“Shakya”];console.log(Array.from(new Set(array1.concat(array2))));
下面是一个简单的例子:
var unique = function(array) {
var unique = []
for (var i = 0; i < array.length; i += 1) {
if (unique.indexOf(array[i]) == -1) {
unique.push(array[i])
}
}
return unique
}
var uniqueList = unique(["AAPL", "MSFT"].concat(["MSFT", "BBEP", "GE"]));
我们定义unique(array)来删除冗余元素,并使用concat函数来组合两个数组。
DeDuplicate单个或Merge和DeDupliplicate多个数组输入。示例如下。
使用ES6-设置,用于,销毁
我编写了一个接受多个数组参数的简单函数。与上面的解决方案几乎相同,只是有更实际的用例。此函数不会将重复的值连接到一个数组中,以便在稍后阶段删除它们。
短功能定义(仅9行)
/**
* This function merging only arrays unique values. It does not merges arrays in to array with duplicate values at any stage.
*
* @params ...args Function accept multiple array input (merges them to single array with no duplicates)
* it also can be used to filter duplicates in single array
*/
function arrayDeDuplicate(...args){
let set = new Set(); // init Set object (available as of ES6)
for(let arr of args){ // for of loops through values
arr.map((value) => { // map adds each value to Set object
set.add(value); // set.add method adds only unique values
});
}
return [...set]; // destructuring set object back to array object
// alternativly we culd use: return Array.from(set);
}
使用示例代码笔:
// SCENARIO
let a = [1,2,3,4,5,6];
let b = [4,5,6,7,8,9,10,10,10];
let c = [43,23,1,2,3];
let d = ['a','b','c','d'];
let e = ['b','c','d','e'];
// USEAGE
let uniqueArrayAll = arrayDeDuplicate(a, b, c, d, e);
let uniqueArraySingle = arrayDeDuplicate(b);
// OUTPUT
console.log(uniqueArrayAll); // [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 43, 23, "a", "b", "c", "d", "e"]
console.log(uniqueArraySingle); // [4, 5, 6, 7, 8, 9, 10]
这是我需要合并(或返回两个数组的并集)时使用的函数。
var union = function (a, b) {
for (var i = 0; i < b.length; i++)
if (a.indexOf(b[i]) === -1)
a.push(b[i]);
return a;
};
var a = [1, 2, 3, 'a', 'b', 'c'];
var b = [2, 3, 4, 'b', 'c', 'd'];
a = union(a, b);
//> [1, 2, 3, "a", "b", "c", 4, "d"]
var array1 = ["Vijendra", "Singh"];
var array2 = ["Singh", "Shakya"];
var array3 = union(array1, array2);
//> ["Vijendra", "Singh", "Shakya"]