我如何转换字符串既像'helloThere'或'helloThere'到'HelloThere'在JavaScript?
当前回答
试试这个库
http://sugarjs.com/api/String/titleize
'man from the boondocks'.titleize()>"Man from the Boondocks"
'x-men: the last stand'.titleize()>"X Men: The Last Stand"
'TheManWithoutAPast'.titleize()>"The Man Without a Past"
'raiders_of_the_lost_ark'.titleize()>"Raiders of the Lost Ark"
其他回答
const text = 'helloThereMister'; const result = text.replace(/([A-Z])/g, " $1"); const finalResult = result.charAt(0).toUpperCase() + result.slice(1); console.log (finalResult);
第一个字母大写——举个例子。注意“$1”中的空格。
当然,如果第一个字母已经大写了,你就有多余的空间可以删除。
试试这个库
http://sugarjs.com/api/String/titleize
'man from the boondocks'.titleize()>"Man from the Boondocks"
'x-men: the last stand'.titleize()>"X Men: The Last Stand"
'TheManWithoutAPast'.titleize()>"The Man Without a Past"
'raiders_of_the_lost_ark'.titleize()>"Raiders of the Lost Ark"
这是我的版本。它在每个小写英文字母后面的大写英文字母之前增加一个空格,如果需要,还会将第一个字母大写:
例如: This IsCamelCase——> This IsCamelCase 这是骆驼案——>这是骆驼案 This IsCamelCase123——>
function camelCaseToTitleCase(camelCase){
if (camelCase == null || camelCase == "") {
return camelCase;
}
camelCase = camelCase.trim();
var newText = "";
for (var i = 0; i < camelCase.length; i++) {
if (/[A-Z]/.test(camelCase[i])
&& i != 0
&& /[a-z]/.test(camelCase[i-1])) {
newText += " ";
}
if (i == 0 && /[a-z]/.test(camelCase[i]))
{
newText += camelCase[i].toUpperCase();
} else {
newText += camelCase[i];
}
}
return newText;
}
HTTPRequest_ToServer-AndWaiting --> HTTP Request To Server And Waiting
function toSpaceCase(str) { return str .replace(/[-_]/g, ' ') /* * insert a space between lower & upper * HttpRequest => Http Request */ .replace(/([a-z])([A-Z])/g, '$1 $2') /* * space before last upper in a sequence followed by lower * XMLHttp => XML Http */ .replace(/\b([A-Z]+)([A-Z])([a-z])/, '$1 $2$3') // uppercase the first character .replace(/^./, str => str.toUpperCase()) .replace(/\s+/g, ' ') .trim(); } const input = 'HTTPRequest_ToServer-AndWaiting'; const result = toSpaceCase(input); console.log(input,'-->', result)
好吧,我在这个游戏上晚了几年,但我有一个类似的问题,我想为每一个可能的输入提供一个替换的解决方案。我必须把大部分功劳归功于本帖中的@ZenMaster和本帖中的@Benjamin Udink ten Cate。 代码如下:
var camelEdges = /([A-Z](?=[A-Z][a-z])|[^A-Z](?=[A-Z])|[a-zA-Z](?=[^a-zA-Z]))/g;
var textArray = ["lowercase",
"Class",
"MyClass",
"HTML",
"PDFLoader",
"AString",
"SimpleXMLParser",
"GL11Version",
"99Bottles",
"May5",
"BFG9000"];
var text;
var resultArray = [];
for (var i = 0; i < textArray.length; i++){
text = textArray[i];
text = text.replace(camelEdges,'$1 ');
text = text.charAt(0).toUpperCase() + text.slice(1);
resultArray.push(text);
}
它有三个子句,都使用了lookahead来防止正则表达式引擎消耗太多字符:
[a-z] (?=[a-z] [a-z])查找一个大写字母,后面跟着一个大写字母,然后是小写字母。这将终结像USA这样的缩写词。 [^ a - z](?=[a - z])查找一个非大写字母后跟一个大写字母。这结束了像myWord这样的单词和像99Bottles这样的符号。 [a- za -z](?=[^a- za -z])查找一个字母后面跟着一个非字母。它以像BFG9000这样的符号前的单词结尾。
这个问题在我的搜索结果的顶部,所以希望我可以为其他人节省一些时间!