试试这个库

http://sugarjs.com/api/String/titleize

'man from the boondocks'.titleize()>"Man from the Boondocks"
'x-men: the last stand'.titleize()>"X Men: The Last Stand"
'TheManWithoutAPast'.titleize()>"The Man Without a Past"
'raiders_of_the_lost_ark'.titleize()>"Raiders of the Lost Ark"

上面的答案对我来说都不完美，所以我不得不带着自己的自行车:

function camelCaseToTitle(camelCase) {
    if (!camelCase) {
        return '';
    }

    var pascalCase = camelCase.charAt(0).toUpperCase() + camelCase.substr(1);
    return pascalCase
        .replace(/([a-z])([A-Z])/g, '$1 $2')
        .replace(/([A-Z])([A-Z][a-z])/g, '$1 $2')
        .replace(/([a-z])([0-9])/gi, '$1 $2')
        .replace(/([0-9])([a-z])/gi, '$1 $2');
}

测试用例:

null => ''
'' => ''
'simpleString' => 'Simple String'
'stringWithABBREVIATIONInside => 'String With ABBREVIATION Inside'
'stringWithNumber123' => 'String With Number 123'
'complexExampleWith123ABBR890Etc' => 'Complex Example With 123 ABBR 890 Etc'

这个对我有用看看这个

CamelcaseToWord(“名字”);//返回我的名字

    function CamelcaseToWord(string){
      return string.replace(/([A-Z]+)/g, " $1").replace(/([A-Z][a-z])/g, " $1");
    }

如果你处理的是大写骆驼的情况，这个片段可以帮助你，它还包含一些规格，所以你可以确保它适合你的情况。

export const fromCamelCaseToSentence = (word) =>
  word
    .replace(/([A-Z][a-z]+)/g, ' $1')
    .replace(/([A-Z]{2,})/g, ' $1')
    .replace(/\s{2,}/g, ' ')
    .trim();

和规格:

describe('fromCamelCaseToSentence', () => {
 test('does not fall with a single word', () => {
   expect(fromCamelCaseToSentence('Approved')).toContain('Approved')
   expect(fromCamelCaseToSentence('MDA')).toContain('MDA')
 })

 test('does not fall with an empty string', () => {
   expect(fromCamelCaseToSentence('')).toContain('')
 })

 test('returns the separated by space words', () => {
   expect(fromCamelCaseToSentence('NotApprovedStatus')).toContain('Not Approved Status')
   expect(fromCamelCaseToSentence('GDBState')).toContain('GDB State')
   expect(fromCamelCaseToSentence('StatusDGG')).toContain('Status DGG')
 })
})

基于上面的一个例子，我想出了这个:

const camelToTitle = (camelCase) => camelCase
  .replace(/([A-Z])/g, (match) => ` ${match}`)
  .replace(/^./, (match) => match.toUpperCase())
  .trim()

它适用于我，因为它使用.trim()来处理边缘情况，其中第一个字母是大写的，并且您最终有一个额外的前导空格。

参考: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/Trim

添加了另一个ES6解决方案，我更喜欢上面的一些想法。

https://codepen.io/902Labs/pen/mxdxRv?editors=0010#0

const camelize = (str) => str
    .split(' ')
    .map(([first, ...theRest]) => (
        `${first.toUpperCase()}${theRest.join('').toLowerCase()}`)
    )
    .join(' ');