我认为这可以用reg exp /([a-z]|[a-z] +)([a-z])/g和替换“$1 $2”来完成。

我爱美国的毒品

试试这个库

http://sugarjs.com/api/String/titleize

'man from the boondocks'.titleize()>"Man from the Boondocks"
'x-men: the last stand'.titleize()>"X Men: The Last Stand"
'TheManWithoutAPast'.titleize()>"The Man Without a Past"
'raiders_of_the_lost_ark'.titleize()>"Raiders of the Lost Ark"

你可以使用这样的函数:

function fixStr(str) {
    var out = str.replace(/^\s*/, "");  // strip leading spaces
    out = out.replace(/^[a-z]|[^\s][A-Z]/g, function(str, offset) {
        if (offset == 0) {
            return(str.toUpperCase());
        } else {
            return(str.substr(0,1) + " " + str.substr(1).toUpperCase());
        }
    });
    return(out);
}

"hello World" ==> "Hello World"
"HelloWorld" ==> "Hello World"
"FunInTheSun" ==? "Fun In The Sun"

带有一堆测试字符串的代码:http://jsfiddle.net/jfriend00/FWLuV/。

保留前导空格的替代版本:http://jsfiddle.net/jfriend00/Uy2ac/。

连续大写单词的最兼容的答案是:

常量文本 = 'theKD'; const result = text.replace（/（[A-Z]{1，}）/g， “$1”）; const finalResult = result.charAt（0）.toUpperCase（） + result.slice（1）; 控制台.log（最终结果）;

它也与KD兼容，不会将其转换为KD。

上面的答案对我来说都不完美，所以我不得不带着自己的自行车:

function camelCaseToTitle(camelCase) {
    if (!camelCase) {
        return '';
    }

    var pascalCase = camelCase.charAt(0).toUpperCase() + camelCase.substr(1);
    return pascalCase
        .replace(/([a-z])([A-Z])/g, '$1 $2')
        .replace(/([A-Z])([A-Z][a-z])/g, '$1 $2')
        .replace(/([a-z])([0-9])/gi, '$1 $2')
        .replace(/([0-9])([a-z])/gi, '$1 $2');
}

测试用例:

null => ''
'' => ''
'simpleString' => 'Simple String'
'stringWithABBREVIATIONInside => 'String With ABBREVIATION Inside'
'stringWithNumber123' => 'String With Number 123'
'complexExampleWith123ABBR890Etc' => 'Complex Example With 123 ABBR 890 Etc'

输入 javaScript

输出 Java脚本

   var text = 'javaScript';
    text.replace(/([a-z])([A-Z][a-z])/g, "$1 $2").charAt(0).toUpperCase()+text.slice(1).replace(/([a-z])([A-Z][a-z])/g, "$1 $2");