<?php
        $table = 'orders';
        $query = "SHOW COLUMNS FROM $table";
        if($output = mysql_query($query)):
            $columns = array();
            while($result = mysql_fetch_assoc($output)):
                $columns[] = $result['Field'];
            endwhile;
        endif;
        echo '<pre>';
        print_r($columns);
        echo '</pre>';
?>

<?php
        $table = 'orders';
        $query = "SHOW COLUMNS FROM $table";
        if($output = mysql_query($query)):
            $columns = array();
            while($result = mysql_fetch_assoc($output)):
                $columns[] = $result['Field'];
            endwhile;
        endif;
        echo '<pre>';
        print_r($columns);
        echo '</pre>';
?>

列出MySQL表中的所有字段:

select * 
  from information_schema.columns 
 where table_schema = 'your_DB_name' 
   and table_name = 'Your_tablename'

我很久以前写了这个愚蠢的东西，现在仍然时不时地使用它:

https://gist.github.com/kphretiq/e2f924416a326895233d

基本上，它先执行“SHOW TABLES”，然后对每个表执行“DESCRIBE”，然后将其作为markdown输出。

只要在“if name”下面编辑，就可以了。您需要安装pymysql。

select column_name from information_schema.columns
where table_schema = 'your_db'
order by table_name,ordinal_position

问题是:

是否有一个快速的方法，从MySQL所有表中获得所有的列名，而不必列出所有的表?

SQL来获取每列的所有信息

select * from information_schema.columns
where table_schema = 'your_db'
order by table_name,ordinal_position

获取所有的列名

select COLUMN_NAME from information_schema.columns
where table_schema = 'your_db'
order by table_name,ordinal_position