是否有一种快速的方法从MySQL中所有表中获得所有列名,而不必列出所有表?
当前回答
列出MySQL表中的所有字段:
select *
from information_schema.columns
where table_schema = 'your_DB_name'
and table_name = 'Your_tablename'
其他回答
select column_name from information_schema.columns
where table_schema = 'your_db'
order by table_name,ordinal_position
最好使用以下查询来获取所有列名 很容易
显示tablename中的列
问题是:
是否有一个快速的方法,从MySQL所有表中获得所有的列名,而不必列出所有的表?
SQL来获取每列的所有信息
select * from information_schema.columns
where table_schema = 'your_db'
order by table_name,ordinal_position
获取所有的列名
select COLUMN_NAME from information_schema.columns
where table_schema = 'your_db'
order by table_name,ordinal_position
在Nicola的回答上加上一些可读的php
$a = mysqli_query($conn,"select * from information_schema.columns
where table_schema = 'your_db'
order by table_name,ordinal_position");
$b = mysqli_fetch_all($a,MYSQLI_ASSOC);
$d = array();
foreach($b as $c){
if(!is_array($d[$c['TABLE_NAME']])){
$d[$c['TABLE_NAME']] = array();
}
$d[$c['TABLE_NAME']][] = $c['COLUMN_NAME'];
}
echo "<pre>",print_r($d),"</pre>";
类似于@suganya发布的答案,这并没有直接回答问题,但对于单个表来说是一个更快的选择:
DESCRIBE column_name;