是否有一种快速的方法从MySQL中所有表中获得所有列名,而不必列出所有表?
当前回答
select column_name from information_schema.columns
where table_schema = 'your_db'
order by table_name,ordinal_position
其他回答
在Nicola的回答上加上一些可读的php
$a = mysqli_query($conn,"select * from information_schema.columns
where table_schema = 'your_db'
order by table_name,ordinal_position");
$b = mysqli_fetch_all($a,MYSQLI_ASSOC);
$d = array();
foreach($b as $c){
if(!is_array($d[$c['TABLE_NAME']])){
$d[$c['TABLE_NAME']] = array();
}
$d[$c['TABLE_NAME']][] = $c['COLUMN_NAME'];
}
echo "<pre>",print_r($d),"</pre>";
您可以使用information_schema简单地获取一个表的所有列。列只需添加group_concat以获得逗号分隔的列列表。
select group_concat( column_name ) as ColumnNames from information_schema.columns where table_schema = 'ur_db_name' and table_name = 'ur_tbl_name'
select column_name from information_schema.columns
where table_schema = 'your_db'
order by table_name,ordinal_position
列出MySQL表中的所有字段:
select *
from information_schema.columns
where table_schema = 'your_DB_name'
and table_name = 'Your_tablename'
我很久以前写了这个愚蠢的东西,现在仍然时不时地使用它:
https://gist.github.com/kphretiq/e2f924416a326895233d
基本上,它先执行“SHOW TABLES”,然后对每个表执行“DESCRIBE”,然后将其作为markdown输出。
只要在“if name”下面编辑,就可以了。您需要安装pymysql。