SELECT * FROM information_schema.columns
WHERE table_schema = DATABASE()
ORDER BY table_name, ordinal_position

因为我没有足够的代表来评论，这里有一个小的改进(在我看来)尼克rulez的优秀答案:替换WHERE table_schema = 'your_db'与WHERE table_schema = DATABASE()。

您可以使用information_schema简单地获取一个表的所有列。列只需添加group_concat以获得逗号分隔的列列表。

select group_concat( column_name ) as ColumnNames from information_schema.columns where table_schema = 'ur_db_name' and table_name = 'ur_tbl_name'

<?php
        $table = 'orders';
        $query = "SHOW COLUMNS FROM $table";
        if($output = mysql_query($query)):
            $columns = array();
            while($result = mysql_fetch_assoc($output)):
                $columns[] = $result['Field'];
            endwhile;
        endif;
        echo '<pre>';
        print_r($columns);
        echo '</pre>';
?>

列出MySQL表中的所有字段:

select * 
  from information_schema.columns 
 where table_schema = 'your_DB_name' 
   and table_name = 'Your_tablename'

select column_name from information_schema.columns
where table_schema = 'your_db'
order by table_name,ordinal_position

类似于@suganya发布的答案，这并没有直接回答问题，但对于单个表来说是一个更快的选择:

DESCRIBE column_name;