我想用H:MM:SS这样的模式以秒为单位格式化持续时间。java中当前的实用程序设计用于格式化时间,而不是持续时间。


当前回答

下面是在Kotlin中将java.time.Duration转换为一个漂亮的字符串的一行代码:

duration.run {
   "%d:%02d:%02d.%03d".format(toHours(), toMinutesPart(), toSecondsPart(), toMillisPart())
}

示例输出: 120:56:03.004

其他回答

下面是另一个如何格式化持续时间的示例。 注意,这个示例将正持续时间和负持续时间都显示为正持续时间。

import static java.time.temporal.ChronoUnit.DAYS;
import static java.time.temporal.ChronoUnit.HOURS;
import static java.time.temporal.ChronoUnit.MINUTES;
import static java.time.temporal.ChronoUnit.SECONDS;

import java.time.Duration;

public class DurationSample {
    public static void main(String[] args) {
        //Let's say duration of 2days 3hours 12minutes and 46seconds
        Duration d = Duration.ZERO.plus(2, DAYS).plus(3, HOURS).plus(12, MINUTES).plus(46, SECONDS);

        //in case of negative duration
        if(d.isNegative()) d = d.negated();

        //format DAYS HOURS MINUTES SECONDS 
        System.out.printf("Total duration is %sdays %shrs %smin %ssec.\n", d.toDays(), d.toHours() % 24, d.toMinutes() % 60, d.getSeconds() % 60);

        //or format HOURS MINUTES SECONDS 
        System.out.printf("Or total duration is %shrs %smin %sec.\n", d.toHours(), d.toMinutes() % 60, d.getSeconds() % 60);

        //or format MINUTES SECONDS 
        System.out.printf("Or total duration is %smin %ssec.\n", d.toMinutes(), d.getSeconds() % 60);

        //or format SECONDS only 
        System.out.printf("Or total duration is %ssec.\n", d.getSeconds());
    }
}
String duration(Temporal from, Temporal to) {
    final StringBuilder builder = new StringBuilder();
    for (ChronoUnit unit : new ChronoUnit[]{YEARS, MONTHS, WEEKS, DAYS, HOURS, MINUTES, SECONDS}) {
        long amount = unit.between(from, to);
        if (amount == 0) {
            continue;
        }
        builder.append(' ')
                .append(amount)
                .append(' ')
                .append(unit.name().toLowerCase());
        from = from.plus(amount, unit);
    }
    return builder.toString().trim();
}
long duration = 4 * 60 * 60 * 1000;
SimpleDateFormat sdf = new SimpleDateFormat("HH:mm:ss.SSS", Locale.getDefault());
log.info("Duration: " + sdf.format(new Date(duration - TimeZone.getDefault().getRawOffset())));

在Scala中,构建YourBestBet的解决方案,但简化了:

def prettyDuration(seconds: Long): List[String] = seconds match {
  case t if t < 60      => List(s"${t} seconds")
  case t if t < 3600    => s"${t / 60} minutes" :: prettyDuration(t % 60)
  case t if t < 3600*24 => s"${t / 3600} hours" :: prettyDuration(t % 3600)
  case t                => s"${t / (3600*24)} days" :: prettyDuration(t % (3600*24))
}

val dur = prettyDuration(12345).mkString(", ") // => 3 hours, 25 minutes, 45 seconds

这是一个可行的选择。

public static String showDuration(LocalTime otherTime){          
    DateTimeFormatter df = DateTimeFormatter.ISO_LOCAL_TIME;
    LocalTime now = LocalTime.now();
    System.out.println("now: " + now);
    System.out.println("otherTime: " + otherTime);
    System.out.println("otherTime: " + otherTime.format(df));

    Duration span = Duration.between(otherTime, now);
    LocalTime fTime = LocalTime.ofNanoOfDay(span.toNanos());
    String output = fTime.format(df);

    System.out.println(output);
    return output;
}

使用

System.out.println(showDuration(LocalTime.of(9, 30, 0, 0)));

产生如下内容:

otherTime: 09:30
otherTime: 09:30:00
11:31:27.463
11:31:27.463