我想用H:MM:SS这样的模式以秒为单位格式化持续时间。java中当前的实用程序设计用于格式化时间,而不是持续时间。


当前回答

long duration = 4 * 60 * 60 * 1000;
SimpleDateFormat sdf = new SimpleDateFormat("HH:mm:ss.SSS", Locale.getDefault());
log.info("Duration: " + sdf.format(new Date(duration - TimeZone.getDefault().getRawOffset())));

其他回答

String duration(Temporal from, Temporal to) {
    final StringBuilder builder = new StringBuilder();
    for (ChronoUnit unit : new ChronoUnit[]{YEARS, MONTHS, WEEKS, DAYS, HOURS, MINUTES, SECONDS}) {
        long amount = unit.between(from, to);
        if (amount == 0) {
            continue;
        }
        builder.append(' ')
                .append(amount)
                .append(' ')
                .append(unit.name().toLowerCase());
        from = from.plus(amount, unit);
    }
    return builder.toString().trim();
}

我的库Time4J提供了一个基于模式的解决方案(类似于Apache DurationFormatUtils,但更灵活):

Duration<ClockUnit> duration =
    Duration.of(-573421, ClockUnit.SECONDS) // input in seconds only
    .with(Duration.STD_CLOCK_PERIOD); // performs normalization to h:mm:ss-structure
String fs = Duration.formatter(ClockUnit.class, "+##h:mm:ss").format(duration);
System.out.println(fs); // output => -159:17:01

这段代码演示了处理小时溢出和符号处理的功能,请参见基于模式的持续时间格式化程序的API。

在java8中还有另一种方法。但如果持续时间不超过24小时,则有效

public String formatDuration(Duration duration) {
    DateTimeFormatter formatter = DateTimeFormatter.ofPattern("h:mm.SSS");
    return LocalTime.ofNanoOfDay(duration.toNanos()).format(formatter);
}

那么下面的函数呢 + H: MM: SS 或 + H: MM: SS.sss

public static String formatInterval(final long interval, boolean millisecs )
{
    final long hr = TimeUnit.MILLISECONDS.toHours(interval);
    final long min = TimeUnit.MILLISECONDS.toMinutes(interval) %60;
    final long sec = TimeUnit.MILLISECONDS.toSeconds(interval) %60;
    final long ms = TimeUnit.MILLISECONDS.toMillis(interval) %1000;
    if( millisecs ) {
        return String.format("%02d:%02d:%02d.%03d", hr, min, sec, ms);
    } else {
        return String.format("%02d:%02d:%02d", hr, min, sec );
    }
}

在scala中,不需要库:

def prettyDuration(str:List[String],seconds:Long):List[String]={
  seconds match {
    case t if t < 60 => str:::List(s"${t} seconds")
    case t if (t >= 60 && t< 3600 ) => List(s"${t / 60} minutes"):::prettyDuration(str, t%60)
    case t if (t >= 3600 && t< 3600*24 ) => List(s"${t / 3600} hours"):::prettyDuration(str, t%3600)
    case t if (t>= 3600*24 ) => List(s"${t / (3600*24)} days"):::prettyDuration(str, t%(3600*24))
  }
}
val dur = prettyDuration(List.empty[String], 12345).mkString("")