经过大量的搜索，我无法找到如何使用smtplib。发送邮件到多个收件人。问题是每次发送邮件时，邮件标题似乎包含多个地址，但实际上只有第一个收件人会收到电子邮件。
问题似乎出在邮件上。Message模块期望与smtplb .sendmail()函数不同的内容。
简而言之，要发送给多个收件人，您应该将标题设置为一串以逗号分隔的电子邮件地址。sendmail()参数to_addr应该是一个电子邮件地址列表。
from email.MIMEMultipart import MIMEMultipart
from email.MIMEText import MIMEText
import smtplib
msg = MIMEMultipart()
msg["Subject"] = "Example"
msg["From"] = "me@example.com"
msg["To"] = "malcom@example.com,reynolds@example.com,firefly@example.com"
msg["Cc"] = "serenity@example.com,inara@example.com"
body = MIMEText("example email body")
msg.attach(body)
smtp = smtplib.SMTP("mailhost.example.com", 25)
smtp.sendmail(msg["From"], msg["To"].split(",") + msg["Cc"].split(","), msg.as_string())
smtp.quit()
msg['To']需要是一个字符串:
msg['To'] = "a@b.com, b@b.com, c@b.com"
而sendmail中的收件人(sender，收件人，message)需要是一个列表:
sendmail("a@a.com", ["a@b.com", "b@b.com", "c@b.com"], "Howdy")
msg['To']需要是一个字符串:
msg['To'] = "a@b.com, b@b.com, c@b.com"
而sendmail中的收件人(sender，收件人，message)需要是一个列表:
sendmail("a@a.com", ["a@b.com", "b@b.com", "c@b.com"], "Howdy")
您可以在将收件人电子邮件写入文本文件时尝试此操作
from email.mime.text import MIMEText
from email.header import Header
import smtplib
f = open('emails.txt', 'r').readlines()
for n in f:
emails = n.rstrip()
server = smtplib.SMTP('smtp.uk.xensource.com')
server.ehlo()
server.starttls()
body = "Test Email"
subject = "Test"
from = "me@example.com"
to = emails
msg = MIMEText(body,'plain','utf-8')
msg['Subject'] = Header(subject, 'utf-8')
msg['From'] = Header(from, 'utf-8')
msg['To'] = Header(to, 'utf-8')
text = msg.as_string()
try:
server.send(from, emails, text)
print('Message Sent Succesfully')
except:
print('There Was An Error While Sending The Message')
