如何将NSRange转换为Range<String。索引>在Swift?
我想使用以下UITextFieldDelegate方法:
func textField(textField: UITextField!,
shouldChangeCharactersInRange range: NSRange,
replacementString string: String!) -> Bool {
textField.text.stringByReplacingCharactersInRange(???, withString: string)
这与Emilie的回答相似,但是,因为你特别问如何将NSRange转换为Range<String。索引>,你会这样做:
func textField(textField: UITextField, shouldChangeCharactersInRange range: NSRange, replacementString string: String) -> Bool {
let start = advance(textField.text.startIndex, range.location)
let end = advance(start, range.length)
let swiftRange = Range<String.Index>(start: start, end: end)
...
}
NSString版本(相对于Swift String)的replacingCharacters(in: NSRange, with: NSString)接受NSRange,所以一个简单的解决方案是先将String转换为NSString。在Swift 3和2中,委托和替换方法的名称略有不同,所以这取决于你使用的Swift:
斯威夫特3.0
func textField(_ textField: UITextField,
shouldChangeCharactersIn range: NSRange,
replacementString string: String) -> Bool {
let nsString = textField.text as NSString?
let newString = nsString?.replacingCharacters(in: range, with: string)
}
快2.倍
func textField(textField: UITextField,
shouldChangeCharactersInRange range: NSRange,
replacementString string: String) -> Bool {
let nsString = textField.text as NSString?
let newString = nsString?.stringByReplacingCharactersInRange(range, withString: string)
}
你需要使用Range<String。索引>而不是经典的NSRange。我这样做的方式(也许有一个更好的方式)是通过获取字符串的字符串。索引移动它与前进。
我不知道你要替换的范围是什么,但让我们假设你想替换前两个字符。
var start = textField.text.startIndex // Start at the string's start index
var end = advance(textField.text.startIndex, 2) // Take start index and advance 2 characters forward
var range: Range<String.Index> = Range<String.Index>(start: start,end: end)
textField.text.stringByReplacingCharactersInRange(range, withString: string)