如何将NSRange转换为Range<String。索引>在Swift?

我想使用以下UITextFieldDelegate方法:

    func textField(textField: UITextField!,
        shouldChangeCharactersInRange range: NSRange,
        replacementString string: String!) -> Bool {

textField.text.stringByReplacingCharactersInRange(???, withString: string)


当前回答

NSString版本(相对于Swift String)的replacingCharacters(in: NSRange, with: NSString)接受NSRange,所以一个简单的解决方案是先将String转换为NSString。在Swift 3和2中,委托和替换方法的名称略有不同,所以这取决于你使用的Swift:

斯威夫特3.0

func textField(_ textField: UITextField,
               shouldChangeCharactersIn range: NSRange,
               replacementString string: String) -> Bool {

  let nsString = textField.text as NSString?
  let newString = nsString?.replacingCharacters(in: range, with: string)
}

快2.倍

func textField(textField: UITextField,
               shouldChangeCharactersInRange range: NSRange,
               replacementString string: String) -> Bool {

    let nsString = textField.text as NSString?
    let newString = nsString?.stringByReplacingCharactersInRange(range, withString: string)
}

其他回答

在Swift 2.0中假设func textField(textField: UITextField, shouldChangeCharactersInRange range: NSRange, replacementString string: string) -> Bool {:

var oldString = textfield.text!
let newRange = oldString.startIndex.advancedBy(range.location)..<oldString.startIndex.advancedBy(range.location + range.length)
let newString = oldString.stringByReplacingCharactersInRange(newRange, withString: string)

Martin R的回答似乎是正确的,因为它代表了Unicode。

然而,在发布这篇文章(Swift 1)时,他的代码不能在Swift 2.0 (Xcode 7)中编译,因为他们删除了advance()函数。更新版本如下:

斯威夫特2

extension String {
    func rangeFromNSRange(nsRange : NSRange) -> Range<String.Index>? {
        let from16 = utf16.startIndex.advancedBy(nsRange.location, limit: utf16.endIndex)
        let to16 = from16.advancedBy(nsRange.length, limit: utf16.endIndex)
        if let from = String.Index(from16, within: self),
            let to = String.Index(to16, within: self) {
                return from ..< to
        }
        return nil
    }
}

斯威夫特3

extension String {
    func rangeFromNSRange(nsRange : NSRange) -> Range<String.Index>? {
        if let from16 = utf16.index(utf16.startIndex, offsetBy: nsRange.location, limitedBy: utf16.endIndex),
            let to16 = utf16.index(from16, offsetBy: nsRange.length, limitedBy: utf16.endIndex),
            let from = String.Index(from16, within: self),
            let to = String.Index(to16, within: self) {
                return from ..< to
        }
        return nil
    }
}

斯威夫特4

extension String {
    func rangeFromNSRange(nsRange : NSRange) -> Range<String.Index>? {
        return Range(nsRange, in: self)
    }
}
extension StringProtocol where Index == String.Index {

    func nsRange(of string: String) -> NSRange? {
        guard let range = self.range(of: string) else {  return nil }
        return NSRange(range, in: self)
    }
}

在公认的答案中,我发现可选选项很麻烦。这适用于Swift 3,似乎对表情符号没有问题。

func textField(_ textField: UITextField, 
      shouldChangeCharactersIn range: NSRange, 
      replacementString string: String) -> Bool {

  guard let value = textField.text else {return false} // there may be a reason for returning true in this case but I can't think of it
  // now value is a String, not an optional String

  let valueAfterChange = (value as NSString).replacingCharacters(in: range, with: string)
  // valueAfterChange is a String, not an optional String

  // now do whatever processing is required

  return true  // or false, as required
}

Swift 3.0 beta版官方文档在标题String下为这种情况提供了标准解决方案。UTF16View中的UTF16View元素匹配NSString字符标题