如何将NSRange转换为Range<String。索引>在Swift?
我想使用以下UITextFieldDelegate方法:
func textField(textField: UITextField!,
shouldChangeCharactersInRange range: NSRange,
replacementString string: String!) -> Bool {
textField.text.stringByReplacingCharactersInRange(???, withString: string)
当前回答
NSString版本(相对于Swift String)的replacingCharacters(in: NSRange, with: NSString)接受NSRange，所以一个简单的解决方案是先将String转换为NSString。在Swift 3和2中，委托和替换方法的名称略有不同，所以这取决于你使用的Swift:
斯威夫特3.0
func textField(_ textField: UITextField,
shouldChangeCharactersIn range: NSRange,
replacementString string: String) -> Bool {
let nsString = textField.text as NSString?
let newString = nsString?.replacingCharacters(in: range, with: string)
}
快2.倍
func textField(textField: UITextField,
shouldChangeCharactersInRange range: NSRange,
replacementString string: String) -> Bool {
let nsString = textField.text as NSString?
let newString = nsString?.stringByReplacingCharactersInRange(range, withString: string)
}
其他回答
Swift 3.0 beta版官方文档在标题String下为这种情况提供了标准解决方案。UTF16View中的UTF16View元素匹配NSString字符标题
func textField(textField: UITextField, shouldChangeCharactersInRange range: NSRange, replacementString string: String) -> Bool {
let strString = ((textField.text)! as NSString).stringByReplacingCharactersInRange(range, withString: string)
}
这与Emilie的回答相似，但是，因为你特别问如何将NSRange转换为Range<String。索引>，你会这样做:
func textField(textField: UITextField, shouldChangeCharactersInRange range: NSRange, replacementString string: String) -> Bool {
let start = advance(textField.text.startIndex, range.location)
let end = advance(start, range.length)
let swiftRange = Range<String.Index>(start: start, end: end)
...
}
Martin R的回答似乎是正确的，因为它代表了Unicode。
然而，在发布这篇文章(Swift 1)时，他的代码不能在Swift 2.0 (Xcode 7)中编译，因为他们删除了advance()函数。更新版本如下:
斯威夫特2
extension String {
func rangeFromNSRange(nsRange : NSRange) -> Range<String.Index>? {
let from16 = utf16.startIndex.advancedBy(nsRange.location, limit: utf16.endIndex)
let to16 = from16.advancedBy(nsRange.length, limit: utf16.endIndex)
if let from = String.Index(from16, within: self),
let to = String.Index(to16, within: self) {
return from ..< to
}
return nil
}
}
斯威夫特3
extension String {
func rangeFromNSRange(nsRange : NSRange) -> Range<String.Index>? {
if let from16 = utf16.index(utf16.startIndex, offsetBy: nsRange.location, limitedBy: utf16.endIndex),
let to16 = utf16.index(from16, offsetBy: nsRange.length, limitedBy: utf16.endIndex),
let from = String.Index(from16, within: self),
let to = String.Index(to16, within: self) {
return from ..< to
}
return nil
}
}
斯威夫特4
extension String {
func rangeFromNSRange(nsRange : NSRange) -> Range<String.Index>? {
return Range(nsRange, in: self)
}
}
NSString版本(相对于Swift String)的replacingCharacters(in: NSRange, with: NSString)接受NSRange，所以一个简单的解决方案是先将String转换为NSString。在Swift 3和2中，委托和替换方法的名称略有不同，所以这取决于你使用的Swift:
斯威夫特3.0
func textField(_ textField: UITextField,
shouldChangeCharactersIn range: NSRange,
replacementString string: String) -> Bool {
let nsString = textField.text as NSString?
let newString = nsString?.replacingCharacters(in: range, with: string)
}
快2.倍
func textField(textField: UITextField,
shouldChangeCharactersInRange range: NSRange,
replacementString string: String) -> Bool {
let nsString = textField.text as NSString?
let newString = nsString?.stringByReplacingCharactersInRange(range, withString: string)
}
