如何将NSRange转换为Range<String。索引>在Swift?

我想使用以下UITextFieldDelegate方法:

    func textField(textField: UITextField!,
        shouldChangeCharactersInRange range: NSRange,
        replacementString string: String!) -> Bool {

textField.text.stringByReplacingCharactersInRange(???, withString: string)


当前回答

在公认的答案中,我发现可选选项很麻烦。这适用于Swift 3,似乎对表情符号没有问题。

func textField(_ textField: UITextField, 
      shouldChangeCharactersIn range: NSRange, 
      replacementString string: String) -> Bool {

  guard let value = textField.text else {return false} // there may be a reason for returning true in this case but I can't think of it
  // now value is a String, not an optional String

  let valueAfterChange = (value as NSString).replacingCharacters(in: range, with: string)
  // valueAfterChange is a String, not an optional String

  // now do whatever processing is required

  return true  // or false, as required
}

其他回答

在Swift 2.0中假设func textField(textField: UITextField, shouldChangeCharactersInRange range: NSRange, replacementString string: string) -> Bool {:

var oldString = textfield.text!
let newRange = oldString.startIndex.advancedBy(range.location)..<oldString.startIndex.advancedBy(range.location + range.length)
let newString = oldString.stringByReplacingCharactersInRange(newRange, withString: string)

Martin R的回答似乎是正确的,因为它代表了Unicode。

然而,在发布这篇文章(Swift 1)时,他的代码不能在Swift 2.0 (Xcode 7)中编译,因为他们删除了advance()函数。更新版本如下:

斯威夫特2

extension String {
    func rangeFromNSRange(nsRange : NSRange) -> Range<String.Index>? {
        let from16 = utf16.startIndex.advancedBy(nsRange.location, limit: utf16.endIndex)
        let to16 = from16.advancedBy(nsRange.length, limit: utf16.endIndex)
        if let from = String.Index(from16, within: self),
            let to = String.Index(to16, within: self) {
                return from ..< to
        }
        return nil
    }
}

斯威夫特3

extension String {
    func rangeFromNSRange(nsRange : NSRange) -> Range<String.Index>? {
        if let from16 = utf16.index(utf16.startIndex, offsetBy: nsRange.location, limitedBy: utf16.endIndex),
            let to16 = utf16.index(from16, offsetBy: nsRange.length, limitedBy: utf16.endIndex),
            let from = String.Index(from16, within: self),
            let to = String.Index(to16, within: self) {
                return from ..< to
        }
        return nil
    }
}

斯威夫特4

extension String {
    func rangeFromNSRange(nsRange : NSRange) -> Range<String.Index>? {
        return Range(nsRange, in: self)
    }
}

我发现最干净的swift2唯一的解决方案是在NSRange上创建一个类别:

extension NSRange {
    func stringRangeForText(string: String) -> Range<String.Index> {
        let start = string.startIndex.advancedBy(self.location)
        let end = start.advancedBy(self.length)
        return Range<String.Index>(start: start, end: end)
    }
}

然后调用它from for textfield delegate函数:

func textField(textField: UITextField, shouldChangeCharactersInRange range: NSRange, replacementString string: String) -> Bool {
    let range = range.stringRangeForText(textField.text)
    let output = textField.text.stringByReplacingCharactersInRange(range, withString: string)

    // your code goes here....

    return true
}
func textField(_ textField: UITextField, shouldChangeCharactersIn range: NSRange, replacementString string: String) -> Bool {
    
    guard let current = textField.text, let r = Range(range, in: current) else {
        return false
    }
    
    let text = current.replacingCharacters(in: r, with: string)
    // ...
    return true
}

Swift 5解决方案

简短的回答带有主要的扩展

extension NSRange {

    public init(range: Range<String.Index>, 
                originalText: String) {

        self.init(location: range.lowerBound.utf16Offset(in: originalText),
                  length: range.upperBound.utf16Offset(in: originalText) - range.lowerBound.utf16Offset(in: originalText))
    }
}

详情请看这里