我想创建一个使用互联网的应用程序,我试图创建一个功能,检查连接是否可用,如果它不是,去到一个活动,有一个重试按钮和解释。

附件是我的代码到目前为止,但我得到的错误语法错误,插入“}”来完成MethodBody。

现在我已经把这些放在试图让它工作,但到目前为止没有运气…任何帮助都将不胜感激。

public class TheEvoStikLeagueActivity extends Activity {
    private final int SPLASH_DISPLAY_LENGHT = 3000;

    /** Called when the activity is first created. */
    @Override
    public void onCreate(Bundle icicle) {
        super.onCreate(icicle);
        setContentView(R.layout.main);

        private boolean checkInternetConnection() {
            ConnectivityManager conMgr = (ConnectivityManager) getSystemService (Context.CONNECTIVITY_SERVICE);
            // ARE WE CONNECTED TO THE NET
            if (conMgr.getActiveNetworkInfo() != null
                    && conMgr.getActiveNetworkInfo().isAvailable()
                    && conMgr.getActiveNetworkInfo().isConnected()) {

                return true;

                /* New Handler to start the Menu-Activity
                 * and close this Splash-Screen after some seconds.*/
                new Handler().postDelayed(new Runnable() {
                    public void run() {
                        /* Create an Intent that will start the Menu-Activity. */
                        Intent mainIntent = new Intent(TheEvoStikLeagueActivity.this, IntroActivity.class);
                        TheEvoStikLeagueActivity.this.startActivity(mainIntent);
                        TheEvoStikLeagueActivity.this.finish();
                    }
                }, SPLASH_DISPLAY_LENGHT);
            } else {
                return false;

                Intent connectionIntent = new Intent(TheEvoStikLeagueActivity.this, HomeActivity.class);
                TheEvoStikLeagueActivity.this.startActivity(connectionIntent);
                TheEvoStikLeagueActivity.this.finish();
            }
        }
    }

当前回答

使用此代码检查网络连接

ConnectivityManager connectivityManager = (ConnectivityManager) ctx
                .getSystemService(Context.CONNECTIVITY_SERVICE);
        if ((connectivityManager
                .getNetworkInfo(ConnectivityManager.TYPE_MOBILE) != null && connectivityManager
                .getNetworkInfo(ConnectivityManager.TYPE_MOBILE).getState() == NetworkInfo.State.CONNECTED)
                || (connectivityManager
                        .getNetworkInfo(ConnectivityManager.TYPE_WIFI) != null && connectivityManager
                        .getNetworkInfo(ConnectivityManager.TYPE_WIFI)
                        .getState() == NetworkInfo.State.CONNECTED)) {
            return true;
        } else {
            return false;
        }

其他回答

我的问题是IsInternetAvailable答案没有测试蜂窝网络,而只是在连接wifi的情况下。这个答案适用于wifi和移动数据:

如何检查网络连接在WIFI和3G(数据计划)移动启用或禁用?

你可以简单地ping一个像谷歌这样的在线网站:

public boolean isConnected() throws InterruptedException, IOException {
    String command = "ping -c 1 google.com";
    return Runtime.getRuntime().exec(command).waitFor() == 0;
}

这是处理所有情况的另一个选项:

public void isNetworkAvailable() {
    ConnectivityManager connectivityManager = (ConnectivityManager) ctx.getSystemService(Context.CONNECTIVITY_SERVICE);
    NetworkInfo activeNetworkInfo = connectivityManager.getActiveNetworkInfo();
    if (activeNetworkInfo != null && activeNetworkInfo.isConnected()) {
    } else {
        Toast.makeText(ctx, "Internet Connection Is Required", Toast.LENGTH_LONG).show();

    }
}

使用这个方法:

public static boolean isOnline() {
    ConnectivityManager cm = (ConnectivityManager) context
            .getSystemService(Context.CONNECTIVITY_SERVICE);
    NetworkInfo netInfo = cm.getActiveNetworkInfo();
    return netInfo != null && netInfo.isConnectedOrConnecting();
}

这是需要的权限:

<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />

下面是一个函数,我使用作为我的Utils类的一部分:

public static boolean isNetworkConnected(Context context) {
    ConnectivityManager cm = (ConnectivityManager) context.getSystemService(Context.CONNECTIVITY_SERVICE);
    return (cm.getActiveNetworkInfo() != null) && cm.getActiveNetworkInfo().isConnectedOrConnecting();
}

像这样使用它:Utils.isNetworkConnected(MainActivity.this);