关于使用fs.readdir进行异步目录搜索有什么想法吗?我意识到我们可以引入递归,并调用read目录函数来读取下一个目录,但我有点担心它不是异步的…
什么好主意吗?我已经看了node-walk,它很棒,但它不能像readdir那样只给我数组中的文件。虽然
寻找这样的输出…
['file1.txt', 'file2.txt', 'dir/file3.txt']
关于使用fs.readdir进行异步目录搜索有什么想法吗?我意识到我们可以引入递归,并调用read目录函数来读取下一个目录,但我有点担心它不是异步的…
什么好主意吗?我已经看了node-walk,它很棒,但它不能像readdir那样只给我数组中的文件。虽然
寻找这样的输出…
['file1.txt', 'file2.txt', 'dir/file3.txt']
当前回答
这是我如何使用nodejs的fs。递归搜索目录的Readdir函数。
const fs = require('fs');
const mime = require('mime-types');
const readdirRecursivePromise = path => {
return new Promise((resolve, reject) => {
fs.readdir(path, (err, directoriesPaths) => {
if (err) {
reject(err);
} else {
if (directoriesPaths.indexOf('.DS_Store') != -1) {
directoriesPaths.splice(directoriesPaths.indexOf('.DS_Store'), 1);
}
directoriesPaths.forEach((e, i) => {
directoriesPaths[i] = statPromise(`${path}/${e}`);
});
Promise.all(directoriesPaths).then(out => {
resolve(out);
}).catch(err => {
reject(err);
});
}
});
});
};
const statPromise = path => {
return new Promise((resolve, reject) => {
fs.stat(path, (err, stats) => {
if (err) {
reject(err);
} else {
if (stats.isDirectory()) {
readdirRecursivePromise(path).then(out => {
resolve(out);
}).catch(err => {
reject(err);
});
} else if (stats.isFile()) {
resolve({
'path': path,
'type': mime.lookup(path)
});
} else {
reject(`Error parsing path: ${path}`);
}
}
});
});
};
const flatten = (arr, result = []) => {
for (let i = 0, length = arr.length; i < length; i++) {
const value = arr[i];
if (Array.isArray(value)) {
flatten(value, result);
} else {
result.push(value);
}
}
return result;
};
假设在节点项目根目录中有一个名为“/database”的路径。一旦这个承诺被解决,它应该吐出'/database'下的每个文件的数组。
readdirRecursivePromise('database').then(out => {
console.log(flatten(out));
}).catch(err => {
console.log(err);
});
其他回答
我建议使用node-glob来完成这个任务。
var glob = require( 'glob' );
glob( 'dirname/**/*.js', function( err, files ) {
console.log( files );
});
谁想要一个公认答案的同步替代方案(我知道我做过):
var fs = require('fs');
var path = require('path');
var walk = function(dir) {
let results = [], err = null, list;
try {
list = fs.readdirSync(dir)
} catch(e) {
err = e.toString();
}
if (err) return err;
var i = 0;
return (function next() {
var file = list[i++];
if(!file) return results;
file = path.resolve(dir, file);
let stat = fs.statSync(file);
if (stat && stat.isDirectory()) {
let res = walk(file);
results = results.concat(res);
return next();
} else {
results.push(file);
return next();
}
})();
};
console.log(
walk("./")
)
我修改了老特雷弗的承诺为蓝鸟工作的基础上的答案
var fs = require('fs'),
path = require('path'),
Promise = require('bluebird');
var readdirAsync = Promise.promisify(fs.readdir);
var statAsync = Promise.promisify(fs.stat);
function walkFiles (directory) {
var results = [];
return readdirAsync(directory).map(function(file) {
file = path.join(directory, file);
return statAsync(file).then(function(stat) {
if (stat.isFile()) {
return results.push(file);
}
return walkFiles(file).then(function(filesInDir) {
results = results.concat(filesInDir);
});
});
}).then(function() {
return results;
});
}
//use
walkDir(__dirname).then(function(files) {
console.log(files);
}).catch(function(e) {
console.error(e); {
});
另一个答案,但这次使用的是TypeScript:
/** * Recursively walk a directory asynchronously and obtain all file names (with full path). * * @param dir Folder name you want to recursively process * @param done Callback function, returns all files with full path. * @param filter Optional filter to specify which files to include, * e.g. for json files: (f: string) => /.json$/.test(f) */ const walk = ( dir: string, done: (err: Error | null, results ? : string[]) => void, filter ? : (f: string) => boolean ) => { let results: string[] = []; fs.readdir(dir, (err: Error, list: string[]) => { if (err) { return done(err); } let pending = list.length; if (!pending) { return done(null, results); } list.forEach((file: string) => { file = path.resolve(dir, file); fs.stat(file, (err2, stat) => { if (stat && stat.isDirectory()) { walk(file, (err3, res) => { if (res) { results = results.concat(res); } if (!--pending) { done(null, results); } }, filter); } else { if (typeof filter === 'undefined' || (filter && filter(file))) { results.push(file); } if (!--pending) { done(null, results); } } }); }); }); };
这是一个简单的同步递归解决方案
const fs = require('fs')
const getFiles = path => {
const files = []
for (const file of fs.readdirSync(path)) {
const fullPath = path + '/' + file
if(fs.lstatSync(fullPath).isDirectory())
getFiles(fullPath).forEach(x => files.push(file + '/' + x))
else files.push(file)
}
return files
}
用法:
const files = getFiles(process.cwd())
console.log(files)
您可以异步地编写它,但是没有必要。只需确保输入目录存在并且可以访问。