关于使用fs.readdir进行异步目录搜索有什么想法吗?我意识到我们可以引入递归,并调用read目录函数来读取下一个目录,但我有点担心它不是异步的…
什么好主意吗?我已经看了node-walk,它很棒,但它不能像readdir那样只给我数组中的文件。虽然
寻找这样的输出…
['file1.txt', 'file2.txt', 'dir/file3.txt']
关于使用fs.readdir进行异步目录搜索有什么想法吗?我意识到我们可以引入递归,并调用read目录函数来读取下一个目录,但我有点担心它不是异步的…
什么好主意吗?我已经看了node-walk,它很棒,但它不能像readdir那样只给我数组中的文件。虽然
寻找这样的输出…
['file1.txt', 'file2.txt', 'dir/file3.txt']
当前回答
使用bluebird promise.coroutine:
let promise = require('bluebird'),
PC = promise.coroutine,
fs = promise.promisifyAll(require('fs'));
let getFiles = PC(function*(dir){
let files = [];
let contents = yield fs.readdirAsync(dir);
for (let i = 0, l = contents.length; i < l; i ++) {
//to remove dot(hidden) files on MAC
if (/^\..*/.test(contents[i])) contents.splice(i, 1);
}
for (let i = 0, l = contents.length; i < l; i ++) {
let content = path.resolve(dir, contents[i]);
let contentStat = yield fs.statAsync(content);
if (contentStat && contentStat.isDirectory()) {
let subFiles = yield getFiles(content);
files = files.concat(subFiles);
} else {
files.push(content);
}
}
return files;
});
//how to use
//easy error handling in one place
getFiles(your_dir).then(console.log).catch(err => console.log(err));
其他回答
使用承诺(Q)以函数式风格解决此问题:
var fs = require('fs'),
fsPath = require('path'),
Q = require('q');
var walk = function (dir) {
return Q.ninvoke(fs, 'readdir', dir).then(function (files) {
return Q.all(files.map(function (file) {
file = fsPath.join(dir, file);
return Q.ninvoke(fs, 'lstat', file).then(function (stat) {
if (stat.isDirectory()) {
return walk(file);
} else {
return [file];
}
});
}));
}).then(function (files) {
return files.reduce(function (pre, cur) {
return pre.concat(cur);
});
});
};
它返回一个数组的promise,所以你可以这样使用它:
walk('/home/mypath').then(function (files) { console.log(files); });
短小、现代、高效:
import {readdir} from 'node:fs/promises'
import {join} from 'node:path'
const deepReadDir = async (dirPath) => await Promise.all(
(await readdir(dirPath, {withFileTypes: true})).map(async (dirent) => {
const path = join(dirPath, dirent.name)
return dirent.isDirectory() ? await deepReadDir(path) : path
}),
)
特别感谢函数提示使用{withFileTypes: true}。
这将自动将每个嵌套路径折叠成一个新的嵌套数组。例如,如果:
await deepReadDir('src')
返回如下内容:
[
[
'src/client/api.js',
'src/client/http-constants.js',
'src/client/index.html',
'src/client/index.js',
[ 'src/client/res/favicon.ico' ],
'src/client/storage.js'
],
[ 'src/crypto/keygen.js' ],
'src/discover.js',
[
'src/mutations/createNewMutation.js',
'src/mutations/newAccount.js',
'src/mutations/transferCredit.js',
'src/mutations/updateApp.js'
],
[
'src/server/authentication.js',
'src/server/handlers.js',
'src/server/quick-response.js',
'src/server/server.js',
'src/server/static-resources.js'
],
[ 'src/util/prompt.js', 'src/util/safeWriteFile.js' ],
'src/util.js'
]
但如果你想,你可以很容易地把它压平:
(await deepReadDir('src')).flat(Number.POSITIVE_INFINITY)
[
'src/client/api.js',
'src/client/http-constants.js',
'src/client/index.html',
'src/client/index.js',
'src/client/res/favicon.ico',
'src/client/storage.js',
'src/crypto/keygen.js',
'src/discover.js',
'src/mutations/createNewMutation.js',
'src/mutations/newAccount.js',
'src/mutations/transferCredit.js',
'src/mutations/updateApp.js',
'src/server/authentication.js',
'src/server/handlers.js',
'src/server/quick-response.js',
'src/server/server.js',
'src/server/static-resources.js',
'src/util/prompt.js',
'src/util/safeWriteFile.js',
'src/util.js'
]
递归-readdir模块具有此功能。
我修改了老特雷弗的承诺为蓝鸟工作的基础上的答案
var fs = require('fs'),
path = require('path'),
Promise = require('bluebird');
var readdirAsync = Promise.promisify(fs.readdir);
var statAsync = Promise.promisify(fs.stat);
function walkFiles (directory) {
var results = [];
return readdirAsync(directory).map(function(file) {
file = path.join(directory, file);
return statAsync(file).then(function(stat) {
if (stat.isFile()) {
return results.push(file);
}
return walkFiles(file).then(function(filesInDir) {
results = results.concat(filesInDir);
});
});
}).then(function() {
return results;
});
}
//use
walkDir(__dirname).then(function(files) {
console.log(files);
}).catch(function(e) {
console.error(e); {
});
TypeScript中基于承诺的递归解决方案,使用Array.flat()处理嵌套返回。
import { resolve } from 'path'
import { Dirent } from 'fs'
import * as fs from 'fs'
function getFiles(root: string): Promise<string[]> {
return fs.promises
.readdir(root, { withFileTypes: true })
.then(dirents => {
const mapToPath = (r: string) => (dirent: Dirent): string => resolve(r, dirent.name)
const directoryPaths = dirents.filter(a => a.isDirectory()).map(mapToPath(root))
const filePaths = dirents.filter(a => a.isFile()).map(mapToPath(root))
return Promise.all<string>([
...directoryPaths.map(a => getFiles(a, include)).flat(),
...filePaths.map(a => Promise.resolve(a))
]).then(a => a.flat())
})
}