关于使用fs.readdir进行异步目录搜索有什么想法吗?我意识到我们可以引入递归,并调用read目录函数来读取下一个目录,但我有点担心它不是异步的…
什么好主意吗?我已经看了node-walk,它很棒,但它不能像readdir那样只给我数组中的文件。虽然
寻找这样的输出…
['file1.txt', 'file2.txt', 'dir/file3.txt']
关于使用fs.readdir进行异步目录搜索有什么想法吗?我意识到我们可以引入递归,并调用read目录函数来读取下一个目录,但我有点担心它不是异步的…
什么好主意吗?我已经看了node-walk,它很棒,但它不能像readdir那样只给我数组中的文件。虽然
寻找这样的输出…
['file1.txt', 'file2.txt', 'dir/file3.txt']
当前回答
下面是完整的工作代码。按您的要求。您可以递归地获取所有文件和文件夹。
var recur = function(dir) {
fs.readdir(dir,function(err,list){
list.forEach(function(file){
var file2 = path.resolve(dir, file);
fs.stat(file2,function(err,stats){
if(stats.isDirectory()) {
recur(file2);
}
else {
console.log(file2);
}
})
})
});
};
recur(path);
在路径中给出你想要搜索的目录路径,如"c:\test"
其他回答
这就是我的答案。希望它能帮助到一些人。
我的重点是使搜索例程可以停在任何地方,对于找到的文件,告诉原始路径的相对深度。
var _fs = require('fs');
var _path = require('path');
var _defer = process.nextTick;
// next() will pop the first element from an array and return it, together with
// the recursive depth and the container array of the element. i.e. If the first
// element is an array, it'll be dug into recursively. But if the first element is
// an empty array, it'll be simply popped and ignored.
// e.g. If the original array is [1,[2],3], next() will return [1,0,[[2],3]], and
// the array becomes [[2],3]. If the array is [[[],[1,2],3],4], next() will return
// [1,2,[2]], and the array becomes [[[2],3],4].
// There is an infinity loop `while(true) {...}`, because I optimized the code to
// make it a non-recursive version.
var next = function(c) {
var a = c;
var n = 0;
while (true) {
if (a.length == 0) return null;
var x = a[0];
if (x.constructor == Array) {
if (x.length > 0) {
a = x;
++n;
} else {
a.shift();
a = c;
n = 0;
}
} else {
a.shift();
return [x, n, a];
}
}
}
// cb is the callback function, it have four arguments:
// 1) an error object if any exception happens;
// 2) a path name, may be a directory or a file;
// 3) a flag, `true` means directory, and `false` means file;
// 4) a zero-based number indicates the depth relative to the original path.
// cb should return a state value to tell whether the searching routine should
// continue: `true` means it should continue; `false` means it should stop here;
// but for a directory, there is a third state `null`, means it should do not
// dig into the directory and continue searching the next file.
var ls = function(path, cb) {
// use `_path.resolve()` to correctly handle '.' and '..'.
var c = [ _path.resolve(path) ];
var f = function() {
var p = next(c);
p && s(p);
};
var s = function(p) {
_fs.stat(p[0], function(err, ss) {
if (err) {
// use `_defer()` to turn a recursive call into a non-recursive call.
cb(err, p[0], null, p[1]) && _defer(f);
} else if (ss.isDirectory()) {
var y = cb(null, p[0], true, p[1]);
if (y) r(p);
else if (y == null) _defer(f);
} else {
cb(null, p[0], false, p[1]) && _defer(f);
}
});
};
var r = function(p) {
_fs.readdir(p[0], function(err, files) {
if (err) {
cb(err, p[0], true, p[1]) && _defer(f);
} else {
// not use `Array.prototype.map()` because we can make each change on site.
for (var i = 0; i < files.length; i++) {
files[i] = _path.join(p[0], files[i]);
}
p[2].unshift(files);
_defer(f);
}
});
}
_defer(f);
};
var printfile = function(err, file, isdir, n) {
if (err) {
console.log('--> ' + ('[' + n + '] ') + file + ': ' + err);
return true;
} else {
console.log('... ' + ('[' + n + '] ') + (isdir ? 'D' : 'F') + ' ' + file);
return true;
}
};
var path = process.argv[2];
ls(path, printfile);
如果你想使用npm包,扳手是很好的选择。
var wrench = require("wrench");
var files = wrench.readdirSyncRecursive("directory");
wrench.readdirRecursive("directory", function (error, files) {
// live your dreams
});
编辑(2018): 作者在2015年弃用了这个包:
扳手.js已弃用,并且在相当长的一段时间内没有更新。我强烈建议使用fs-extra来执行任何额外的文件系统操作。
还有一种方法。我把它放在这里。也许将来它会对某人有用。
const fs = require("fs");
const { promisify } = require("util");
const p = require("path");
const readdir = promisify(fs.readdir);
async function getFiles(path) {
try {
const entries = await readdir(path, { withFileTypes: true });
const files = entries
.filter((file) => !file.isDirectory())
.map((file) => ({
path: `${path}/${file.name}`,
ext: p.extname(`${path}/${file.name}`),
pathDir: path,
}));
const folders = entries.filter((folder) => folder.isDirectory());
for (const folder of folders) {
files.push(...(await getFiles(`${path}/${folder.name}`)));
}
return files;
} catch (error) {
return error;
}
}
用法:
getFiles(rootFolderPath)
.then()
.catch()
对于Node 10.3+,这里是一个For -await解决方案:
#!/usr/bin/env node
const FS = require('fs');
const Util = require('util');
const readDir = Util.promisify(FS.readdir);
const Path = require('path');
async function* readDirR(path) {
const entries = await readDir(path,{withFileTypes:true});
for(let entry of entries) {
const fullPath = Path.join(path,entry.name);
if(entry.isDirectory()) {
yield* readDirR(fullPath);
} else {
yield fullPath;
}
}
}
async function main() {
const start = process.hrtime.bigint();
for await(const file of readDirR('/mnt/home/media/Unsorted')) {
console.log(file);
}
console.log((process.hrtime.bigint()-start)/1000000n);
}
main().catch(err => {
console.error(err);
});
这种解决方案的好处是,您可以立即开始处理结果;例如,读取媒体目录中的所有文件需要12秒,但如果我这样做,我可以在几毫秒内得到第一个结果。
用递归
var fs = require('fs')
var path = process.cwd()
var files = []
var getFiles = function(path, files){
fs.readdirSync(path).forEach(function(file){
var subpath = path + '/' + file;
if(fs.lstatSync(subpath).isDirectory()){
getFiles(subpath, files);
} else {
files.push(path + '/' + file);
}
});
}
调用
getFiles(path, files)
console.log(files) // will log all files in directory