关于使用fs.readdir进行异步目录搜索有什么想法吗?我意识到我们可以引入递归,并调用read目录函数来读取下一个目录,但我有点担心它不是异步的…
什么好主意吗?我已经看了node-walk,它很棒,但它不能像readdir那样只给我数组中的文件。虽然
寻找这样的输出…
['file1.txt', 'file2.txt', 'dir/file3.txt']
关于使用fs.readdir进行异步目录搜索有什么想法吗?我意识到我们可以引入递归,并调用read目录函数来读取下一个目录,但我有点担心它不是异步的…
什么好主意吗?我已经看了node-walk,它很棒,但它不能像readdir那样只给我数组中的文件。虽然
寻找这样的输出…
['file1.txt', 'file2.txt', 'dir/file3.txt']
当前回答
为了好玩,这里有一个基于流的版本,它与highland.js streams库一起工作。作者之一是维克多·伍。
###
directory >---m------> dirFilesStream >---------o----> out
| |
| |
+--------< returnPipe <-----------+
legend: (m)erge (o)bserve
+ directory has the initial file
+ dirListStream does a directory listing
+ out prints out the full path of the file
+ returnPipe runs stat and filters on directories
###
_ = require('highland')
fs = require('fs')
fsPath = require('path')
directory = _(['someDirectory'])
mergePoint = _()
dirFilesStream = mergePoint.merge().flatMap((parentPath) ->
_.wrapCallback(fs.readdir)(parentPath).sequence().map (path) ->
fsPath.join parentPath, path
)
out = dirFilesStream
# Create the return pipe
returnPipe = dirFilesStream.observe().flatFilter((path) ->
_.wrapCallback(fs.stat)(path).map (v) ->
v.isDirectory()
)
# Connect up the merge point now that we have all of our streams.
mergePoint.write directory
mergePoint.write returnPipe
mergePoint.end()
# Release backpressure. This will print files as they are discovered
out.each H.log
# Another way would be to queue them all up and then print them all out at once.
# out.toArray((files)-> console.log(files))
其他回答
使用bluebird promise.coroutine:
let promise = require('bluebird'),
PC = promise.coroutine,
fs = promise.promisifyAll(require('fs'));
let getFiles = PC(function*(dir){
let files = [];
let contents = yield fs.readdirAsync(dir);
for (let i = 0, l = contents.length; i < l; i ++) {
//to remove dot(hidden) files on MAC
if (/^\..*/.test(contents[i])) contents.splice(i, 1);
}
for (let i = 0, l = contents.length; i < l; i ++) {
let content = path.resolve(dir, contents[i]);
let contentStat = yield fs.statAsync(content);
if (contentStat && contentStat.isDirectory()) {
let subFiles = yield getFiles(content);
files = files.concat(subFiles);
} else {
files.push(content);
}
}
return files;
});
//how to use
//easy error handling in one place
getFiles(your_dir).then(console.log).catch(err => console.log(err));
有一个名为cup-readdir的新模块,可以快速递归地搜索目录。它使用异步承诺,在处理深层目录结构时性能优于许多流行的模块。
它可以返回数组中的所有文件,并根据它们的属性对它们进行排序,但缺乏文件过滤和进入符号链接目录等功能。这对于只想从目录中获取每个文件的大型项目非常有用。这里是他们项目主页的链接。
qwtel的答案变体,在TypeScript中
import { resolve } from 'path';
import { readdir } from 'fs/promises';
async function* getFiles(dir: string): AsyncGenerator<string> {
const entries = await readdir(dir, { withFileTypes: true });
for (const entry of entries) {
const res = resolve(dir, entry.name);
if (entry.isDirectory()) {
yield* getFiles(res);
} else {
yield res;
}
}
}
我喜欢上面chjj的答案,如果没有那个开始,我就无法创建我的并行循环版本。
var fs = require("fs");
var tree = function(dir, done) {
var results = {
"path": dir
,"children": []
};
fs.readdir(dir, function(err, list) {
if (err) { return done(err); }
var pending = list.length;
if (!pending) { return done(null, results); }
list.forEach(function(file) {
fs.stat(dir + '/' + file, function(err, stat) {
if (stat && stat.isDirectory()) {
tree(dir + '/' + file, function(err, res) {
results.children.push(res);
if (!--pending){ done(null, results); }
});
} else {
results.children.push({"path": dir + "/" + file});
if (!--pending) { done(null, results); }
}
});
});
});
};
module.exports = tree;
我也创建了一个Gist。欢迎评论。我仍然在NodeJS领域起步,所以这是我希望学到更多的一种方式。
只是简单的散步
let pending = [baseFolderPath]
function walk () {
pending.shift();
// do stuffs width pending[0] and change pending items
if (pending[0]) walk(pending[0])
}
walk(pending[0])