关于使用fs.readdir进行异步目录搜索有什么想法吗?我意识到我们可以引入递归,并调用read目录函数来读取下一个目录,但我有点担心它不是异步的…

什么好主意吗?我已经看了node-walk,它很棒,但它不能像readdir那样只给我数组中的文件。虽然

寻找这样的输出…

['file1.txt', 'file2.txt', 'dir/file3.txt']

当前回答

为了好玩,这里有一个基于流的版本,它与highland.js streams库一起工作。作者之一是维克多·伍。

###
  directory >---m------> dirFilesStream >---------o----> out
                |                                 |
                |                                 |
                +--------< returnPipe <-----------+

  legend: (m)erge  (o)bserve

 + directory         has the initial file
 + dirListStream     does a directory listing
 + out               prints out the full path of the file
 + returnPipe        runs stat and filters on directories

###

_ = require('highland')
fs = require('fs')
fsPath = require('path')

directory = _(['someDirectory'])
mergePoint = _()
dirFilesStream = mergePoint.merge().flatMap((parentPath) ->
  _.wrapCallback(fs.readdir)(parentPath).sequence().map (path) ->
    fsPath.join parentPath, path
)
out = dirFilesStream
# Create the return pipe
returnPipe = dirFilesStream.observe().flatFilter((path) ->
  _.wrapCallback(fs.stat)(path).map (v) ->
    v.isDirectory()
)
# Connect up the merge point now that we have all of our streams.
mergePoint.write directory
mergePoint.write returnPipe
mergePoint.end()
# Release backpressure.  This will print files as they are discovered
out.each H.log
# Another way would be to queue them all up and then print them all out at once.
# out.toArray((files)-> console.log(files))

其他回答

使用bluebird promise.coroutine:

let promise = require('bluebird'),
    PC = promise.coroutine,
    fs = promise.promisifyAll(require('fs'));
let getFiles = PC(function*(dir){
    let files = [];
    let contents = yield fs.readdirAsync(dir);
    for (let i = 0, l = contents.length; i < l; i ++) {
        //to remove dot(hidden) files on MAC
        if (/^\..*/.test(contents[i])) contents.splice(i, 1);
    }
    for (let i = 0, l = contents.length; i < l; i ++) {
        let content = path.resolve(dir, contents[i]);
        let contentStat = yield fs.statAsync(content);
        if (contentStat && contentStat.isDirectory()) {
            let subFiles = yield getFiles(content);
            files = files.concat(subFiles);
        } else {
            files.push(content);
        }
    }
    return files;
});
//how to use
//easy error handling in one place
getFiles(your_dir).then(console.log).catch(err => console.log(err));

有一个名为cup-readdir的新模块,可以快速递归地搜索目录。它使用异步承诺,在处理深层目录结构时性能优于许多流行的模块。

它可以返回数组中的所有文件,并根据它们的属性对它们进行排序,但缺乏文件过滤和进入符号链接目录等功能。这对于只想从目录中获取每个文件的大型项目非常有用。这里是他们项目主页的链接。

qwtel的答案变体,在TypeScript中

import { resolve } from 'path';
import { readdir } from 'fs/promises';

async function* getFiles(dir: string): AsyncGenerator<string> {
    const entries = await readdir(dir, { withFileTypes: true });
    for (const entry of entries) {
        const res = resolve(dir, entry.name);
        if (entry.isDirectory()) {
            yield* getFiles(res);
        } else {
            yield res;
        }
    }
}

我喜欢上面chjj的答案,如果没有那个开始,我就无法创建我的并行循环版本。

var fs = require("fs");

var tree = function(dir, done) {
  var results = {
        "path": dir
        ,"children": []
      };
  fs.readdir(dir, function(err, list) {
    if (err) { return done(err); }
    var pending = list.length;
    if (!pending) { return done(null, results); }
    list.forEach(function(file) {
      fs.stat(dir + '/' + file, function(err, stat) {
        if (stat && stat.isDirectory()) {
          tree(dir + '/' + file, function(err, res) {
            results.children.push(res);
            if (!--pending){ done(null, results); }
          });
        } else {
          results.children.push({"path": dir + "/" + file});
          if (!--pending) { done(null, results); }
        }
      });
    });
  });
};

module.exports = tree;

我也创建了一个Gist。欢迎评论。我仍然在NodeJS领域起步,所以这是我希望学到更多的一种方式。

只是简单的散步

let pending = [baseFolderPath]
function walk () {
    pending.shift();
    // do stuffs width pending[0] and change pending items
    if (pending[0]) walk(pending[0])
}
walk(pending[0])