我继承了一个相当大的SQL Server数据库。考虑到它包含的数据,它似乎比我预期的要占用更多的空间。

是否有一种简单的方法来确定每个表占用的磁盘空间?


当前回答

下面是另一种方法:使用SQLServerManagementStudio,在对象资源管理器中,转到数据库并选择表

然后打开“对象浏览器详细信息”(按F7或转到“查看”->“对象浏览器详情”)。在对象资源管理器详细信息页面中,右键单击列标题并启用您希望在页面中看到的列。您也可以按任何列对数据进行排序。

其他回答

从使用OSQL的命令提示符:

OSQL -E -d <*databasename*> -Q "exec sp_msforeachtable 'sp_spaceused [?]'" > result.txt

如果您使用的是SQL Server Management Studio(SSMS),则可以运行标准报告,而不是运行查询(在我的情况下返回重复的行)

右键单击数据库导航到报告>标准报告>磁盘使用情况(按表)

注意:数据库兼容级别必须设置为90或更高,才能正常工作。看见http://msdn.microsoft.com/en-gb/library/bb510680.aspx

我们使用表分区,由于重复记录,上面提供的查询有一些问题。

对于需要此功能的人,您可以在下面找到SQL Server 2014在生成“磁盘使用情况(按表)”报告时运行的查询。我假设它也适用于以前版本的SQL Server。

它就像一个符咒。

SELECT
    a2.name AS [tablename],
    a1.rows as row_count,
    (a1.reserved + ISNULL(a4.reserved,0))* 8 AS reserved, 
    a1.data * 8 AS data,
    (CASE WHEN (a1.used + ISNULL(a4.used,0)) > a1.data THEN (a1.used + ISNULL(a4.used,0)) - a1.data ELSE 0 END) * 8 AS index_size,
    (CASE WHEN (a1.reserved + ISNULL(a4.reserved,0)) > a1.used THEN (a1.reserved + ISNULL(a4.reserved,0)) - a1.used ELSE 0 END) * 8 AS unused
FROM
    (SELECT 
        ps.object_id,
        SUM (
            CASE
                WHEN (ps.index_id < 2) THEN row_count
                ELSE 0
            END
            ) AS [rows],
        SUM (ps.reserved_page_count) AS reserved,
        SUM (
            CASE
                WHEN (ps.index_id < 2) THEN (ps.in_row_data_page_count + ps.lob_used_page_count + ps.row_overflow_used_page_count)
                ELSE (ps.lob_used_page_count + ps.row_overflow_used_page_count)
            END
            ) AS data,
        SUM (ps.used_page_count) AS used
    FROM sys.dm_db_partition_stats ps
        WHERE ps.object_id NOT IN (SELECT object_id FROM sys.tables WHERE is_memory_optimized = 1)
    GROUP BY ps.object_id) AS a1
LEFT OUTER JOIN 
    (SELECT 
        it.parent_id,
        SUM(ps.reserved_page_count) AS reserved,
        SUM(ps.used_page_count) AS used
     FROM sys.dm_db_partition_stats ps
     INNER JOIN sys.internal_tables it ON (it.object_id = ps.object_id)
     WHERE it.internal_type IN (202,204)
     GROUP BY it.parent_id) AS a4 ON (a4.parent_id = a1.object_id)
INNER JOIN sys.all_objects a2  ON ( a1.object_id = a2.object_id ) 
INNER JOIN sys.schemas a3 ON (a2.schema_id = a3.schema_id)
WHERE a2.type <> N'S' and a2.type <> N'IT'
ORDER BY a3.name, a2.name

经过一番搜索,我找不到一种简单的方法来获取所有表格的信息。有一个名为sp_spaceused的方便存储过程,它将返回数据库使用的所有空间。如果提供了表名,则返回该表使用的空间。但是,存储过程返回的结果不可排序,因为列是字符值。

以下脚本将生成我要查找的信息。

create table #TableSize (
    Name varchar(255),
    [rows] int,
    reserved varchar(255),
    data varchar(255),
    index_size varchar(255),
    unused varchar(255))
create table #ConvertedSizes (
    Name varchar(255),
    [rows] int,
    reservedKb int,
    dataKb int,
    reservedIndexSize int,
    reservedUnused int)

EXEC sp_MSforeachtable @command1="insert into #TableSize
EXEC sp_spaceused '?'"
insert into #ConvertedSizes (Name, [rows], reservedKb, dataKb, reservedIndexSize, reservedUnused)
select name, [rows], 
SUBSTRING(reserved, 0, LEN(reserved)-2), 
SUBSTRING(data, 0, LEN(data)-2), 
SUBSTRING(index_size, 0, LEN(index_size)-2), 
SUBSTRING(unused, 0, LEN(unused)-2)
from #TableSize

select * from #ConvertedSizes
order by reservedKb desc

drop table #TableSize
drop table #ConvertedSizes

我要感谢Greg Low先生的提问:

SELECT o.name AS ObjectName, 
       SUM(reserved_page_count) * 8.0 / 1024 AS SizeinMB
FROM sys.dm_db_partition_stats AS ps
INNER JOIN sys.sysobjects AS o
ON ps.object_id = o.id
GROUP BY o.name
ORDER BY SizeinMB DESC;