下面的异常是什么意思;我该怎么解决呢?
这是代码:
Toast toast = Toast.makeText(mContext, "Something", Toast.LENGTH_SHORT);
这是例外:
java.lang.RuntimeException: Can't create handler inside thread that has not called Looper.prepare()
at android.os.Handler.<init>(Handler.java:121)
at android.widget.Toast.<init>(Toast.java:68)
at android.widget.Toast.makeText(Toast.java:231)
当前回答
我也有同样的问题，我只是把吐司放在Asynctask<>的onPostExecute()覆盖函数中，它起作用了。
其他回答
要在线程中显示对话框或烤面包机，最简洁的方法是使用Activity对象。
例如:
new Thread(new Runnable() {
@Override
public void run() {
myActivity.runOnUiThread(new Runnable() {
public void run() {
myActivity.this.processingWaitDialog = new ProgressDialog(myActivity.this.getContext());
myActivity.this.processingWaitDialog.setProgressStyle(ProgressDialog.STYLE_SPINNER);
myActivity.this.processingWaitDialog.setMessage("abc");
myActivity.this.processingWaitDialog.setIndeterminate(true);
myActivity.this.processingWaitDialog.show();
}
});
expenseClassify.serverPost(
new AsyncOperationCallback() {
public void operationCompleted(Object sender) {
myActivity.runOnUiThread(new Runnable() {
public void run() {
if (myActivity.this.processingWaitDialog != null
&& myActivity.this.processingWaitDialog.isShowing()) {
myActivity.this.processingWaitDialog.dismiss();
myActivity.this.processingWaitDialog = null;
}
}
}); // .runOnUiThread(new Runnable()
...
我使用下面的代码来显示来自非主线程“context”的消息，
@FunctionalInterface
public interface IShowMessage {
Context getContext();
default void showMessage(String message) {
final Thread mThread = new Thread() {
@Override
public void run() {
try {
Looper.prepare();
Toast.makeText(getContext(), message, Toast.LENGTH_LONG).show();
Looper.loop();
} catch (Exception error) {
error.printStackTrace();
Log.e("IShowMessage", error.getMessage());
}
}
};
mThread.start();
}
}
然后使用如下:
class myClass implements IShowMessage{
showMessage("your message!");
@Override
public Context getContext() {
return getApplicationContext();
}
}
Rxjava和RxAndroid用户:
public static void shortToast(String msg) {
Observable.just(msg)
.observeOn(AndroidSchedulers.mainThread())
.subscribe(message -> {
Toast.makeText(App.getInstance(), message, Toast.LENGTH_SHORT).show();
});
}
我得到了同样的问题，这段代码为我工作很好。 作为一个例子，这是我的代码做一个任务在后台和UI线程。 观察如何使用套筒:
new Thread(new Runnable() {
@Override
public void run() {
Looper.prepare();
// your Background Task here
runOnUiThread(new Runnable() {
@Override
public void run() {
// update your UI here
Looper.loop();
}
});
}
}).start();
当我的回调函数试图显示一个对话框时，我也遇到了同样的问题。
我用活动中的专用方法解决了这个问题-在活动实例成员级别-使用runOnUiThread(..)
public void showAuthProgressDialog() {
runOnUiThread(new Runnable() {
@Override
public void run() {
mAuthProgressDialog = DialogUtil.getVisibleProgressDialog(SignInActivity.this, "Loading ...");
}
});
}
public void dismissAuthProgressDialog() {
runOnUiThread(new Runnable() {
@Override
public void run() {
if (mAuthProgressDialog == null || ! mAuthProgressDialog.isShowing()) {
return;
}
mAuthProgressDialog.dismiss();
}
});
}
