我想写一个循环15个字符串的脚本(可能是数组?)这可能吗?
类似于:
for databaseName in listOfNames
then
# Do something
end
我想写一个循环15个字符串的脚本(可能是数组?)这可能吗?
类似于:
for databaseName in listOfNames
then
# Do something
end
当前回答
listOfNames="db_one db_two db_three"
for databaseName in $listOfNames
do
echo $databaseName
done
或者只是
for databaseName in db_one db_two db_three
do
echo $databaseName
done
其他回答
listOfNames="db_one db_two db_three"
for databaseName in $listOfNames
do
echo $databaseName
done
或者只是
for databaseName in db_one db_two db_three
do
echo $databaseName
done
这也很容易阅读:
FilePath=(
"/tmp/path1/" #FilePath[0]
"/tmp/path2/" #FilePath[1]
)
#Loop
for Path in "${FilePath[@]}"
do
echo "$Path"
done
很惊讶还没有人发布这个消息——如果在遍历数组时需要元素的索引,可以这样做:
arr=(foo bar baz)
for i in ${!arr[@]}
do
echo $i "${arr[i]}"
done
输出:
0 foo
1 bar
2 baz
我发现这比“传统”for循环样式(for((I=0;I<${#arr[@]};I++))要优雅得多。
(${!arr[@]}和$i不需要引用,因为它们只是数字;有些人会建议引用它们,但这只是个人偏好。)
这些答案中没有一个包含计数器。。。
#!/bin/bash
## declare an array variable
declare -a array=("one" "two" "three")
# get length of an array
arraylength=${#array[@]}
# use for loop to read all values and indexes
for (( i=0; i<${arraylength}; i++ ));
do
echo "index: $i, value: ${array[$i]}"
done
输出:
index: 0, value: one
index: 1, value: two
index: 2, value: three
您可以使用${arrayName[@]}的语法
#!/bin/bash
# declare an array called files, that contains 3 values
files=( "/etc/passwd" "/etc/group" "/etc/hosts" )
for i in "${files[@]}"
do
echo "$i"
done