我如何在Python中获得给定目录中的所有文件(和目录)的列表?


当前回答

供参考添加扩展或ext文件的过滤器 进口操作系统

path = '.'
for dirname, dirnames, filenames in os.walk(path):
    # print path to all filenames with extension py.
    for filename in filenames:
        fname_path = os.path.join(dirname, filename)
        fext = os.path.splitext(fname_path)[1]
        if fext == '.py':
            print fname_path
        else:
            continue

其他回答

对于Python 2

#!/bin/python2

import os

def scan_dir(path):
    print map(os.path.abspath, os.listdir(pwd))

对于Python 3

对于filter和map,你需要用list()来包装它们

#!/bin/python3

import os

def scan_dir(path):
    print(list(map(os.path.abspath, os.listdir(pwd))))

现在的建议是用生成器表达式或列表推导式替换map和filter的使用:

#!/bin/python

import os

def scan_dir(path):
    print([os.path.abspath(f) for f in os.listdir(path)])

试试这个:

import os
for top, dirs, files in os.walk('./'):
    for nm in files:       
        print os.path.join(top, nm)
import os

for filename in os.listdir("C:\\temp"):
    print  filename

如果我觉得我会把这个扔进去。简单和肮脏的方式进行通配符搜索。

import re
import os

[a for a in os.listdir(".") if re.search("^.*\.py$",a)]

供参考添加扩展或ext文件的过滤器 进口操作系统

path = '.'
for dirname, dirnames, filenames in os.walk(path):
    # print path to all filenames with extension py.
    for filename in filenames:
        fname_path = os.path.join(dirname, filename)
        fext = os.path.splitext(fname_path)[1]
        if fext == '.py':
            print fname_path
        else:
            continue