我知道这是一个老问题。如果你在linux机器上，这是我遇到的一种简洁的方法。

import subprocess
print(subprocess.check_output(["ls", "/"]).decode("utf8"))

供参考添加扩展或ext文件的过滤器 进口操作系统

path = '.'
for dirname, dirnames, filenames in os.walk(path):
    # print path to all filenames with extension py.
    for filename in filenames:
        fname_path = os.path.join(dirname, filename)
        fext = os.path.splitext(fname_path)[1]
        if fext == '.py':
            print fname_path
        else:
            continue

这是一种遍历目录树中每个文件和目录的方法:

import os

for dirname, dirnames, filenames in os.walk('.'):
    # print path to all subdirectories first.
    for subdirname in dirnames:
        print(os.path.join(dirname, subdirname))

    # print path to all filenames.
    for filename in filenames:
        print(os.path.join(dirname, filename))

    # Advanced usage:
    # editing the 'dirnames' list will stop os.walk() from recursing into there.
    if '.git' in dirnames:
        # don't go into any .git directories.
        dirnames.remove('.git')

递归实现

import os

def scan_dir(dir):
    for name in os.listdir(dir):
        path = os.path.join(dir, name)
        if os.path.isfile(path):
            print path
        else:
            scan_dir(path)

只递归列出文件的漂亮的一行代码。我在setup.py package_data指令中使用了这个:

import os

[os.path.join(x[0],y) for x in os.walk('<some_directory>') for y in x[2]]

我知道这不是问题的答案，但可能会派上用场

试试这个:

import os
for top, dirs, files in os.walk('./'):
    for nm in files:       
        print os.path.join(top, nm)