我如何在Python中获得给定目录中的所有文件(和目录)的列表?


当前回答

对于当前工作目录中的文件,无需指定路径

Python 2.7:

import os
os.listdir('.')

Python 3. x:

import os
os.listdir()

其他回答

这是另一种选择。

os.scandir(path='.')

它返回os的迭代器。对应于path指定目录中的条目(以及文件属性信息)的DirEntry对象。

例子:

with os.scandir(path) as it:
    for entry in it:
        if not entry.name.startswith('.'):
            print(entry.name)

Using scandir() instead of listdir() can significantly increase the performance of code that also needs file type or file attribute information, because os.DirEntry objects expose this information if the operating system provides it when scanning a directory. All os.DirEntry methods may perform a system call, but is_dir() and is_file() usually only require a system call for symbolic links; os.DirEntry.stat() always requires a system call on Unix but only requires one for symbolic links on Windows.

Python文档

#import modules
import os

_CURRENT_DIR = '.'


def rec_tree_traverse(curr_dir, indent):
    "recurcive function to traverse the directory"
    #print "[traverse_tree]"

    try :
        dfList = [os.path.join(curr_dir, f_or_d) for f_or_d in os.listdir(curr_dir)]
    except:
        print "wrong path name/directory name"
        return

    for file_or_dir in dfList:

        if os.path.isdir(file_or_dir):
            #print "dir  : ",
            print indent, file_or_dir,"\\"
            rec_tree_traverse(file_or_dir, indent*2)

        if os.path.isfile(file_or_dir):
            #print "file : ",
            print indent, file_or_dir

    #end if for loop
#end of traverse_tree()

def main():

    base_dir = _CURRENT_DIR

    rec_tree_traverse(base_dir," ")

    raw_input("enter any key to exit....")
#end of main()


if __name__ == '__main__':
    main()
import os

for filename in os.listdir("C:\\temp"):
    print  filename

这是一种遍历目录树中每个文件和目录的方法:

import os

for dirname, dirnames, filenames in os.walk('.'):
    # print path to all subdirectories first.
    for subdirname in dirnames:
        print(os.path.join(dirname, subdirname))

    # print path to all filenames.
    for filename in filenames:
        print(os.path.join(dirname, filename))

    # Advanced usage:
    # editing the 'dirnames' list will stop os.walk() from recursing into there.
    if '.git' in dirnames:
        # don't go into any .git directories.
        dirnames.remove('.git')

我知道这是一个老问题。如果你在linux机器上,这是我遇到的一种简洁的方法。

import subprocess
print(subprocess.check_output(["ls", "/"]).decode("utf8"))