就像上面的回答中所说的那样，我的2分:copy()方法不应该在没有轻微调整的情况下原样用于复制文件:

function copy(callback) {
    var readStream = fs.createReadStream(oldPath);
    var writeStream = fs.createWriteStream(newPath);

    readStream.on('error', callback);
    writeStream.on('error', callback);

    // Do not callback() upon "close" event on the readStream
    // readStream.on('close', function () {
    // Do instead upon "close" on the writeStream
    writeStream.on('close', function () {
        callback();
    });

    readStream.pipe(writeStream);
}

复制函数封装在Promise中:

function copy(oldPath, newPath) {
  return new Promise((resolve, reject) => {
    const readStream = fs.createReadStream(oldPath);
    const writeStream = fs.createWriteStream(newPath);

    readStream.on('error', err => reject(err));
    writeStream.on('error', err => reject(err));

    writeStream.on('close', function() {
      resolve();
    });

    readStream.pipe(writeStream);
  })

但是，请记住，如果目标文件夹不存在，文件系统可能会崩溃。

如果您试图移动或重命名一个node.js源文件，请尝试https://github.com/viruschidai/node-mv。它将更新所有其他文件中对该文件的引用。

我将把所有涉及的函数(即重命名，复制，断开链接)彼此分离，以获得灵活性，并承诺一切，当然:

const renameFile = (path, newPath) => 
  new Promise((res, rej) => {
    fs.rename(path, newPath, (err, data) =>
      err
        ? rej(err)
        : res(data));
  });

const copyFile = (path, newPath, flags) =>
  new Promise((res, rej) => {
    const readStream = fs.createReadStream(path),
      writeStream = fs.createWriteStream(newPath, {flags});

    readStream.on("error", rej);
    writeStream.on("error", rej);
    writeStream.on("finish", res);
    readStream.pipe(writeStream);
  });

const unlinkFile = path => 
  new Promise((res, rej) => {
    fs.unlink(path, (err, data) =>
      err
        ? rej(err)
        : res(data));
  });

const moveFile = (path, newPath, flags) =>
  renameFile(path, newPath)
    .catch(e => {
      if (e.code !== "EXDEV")
        throw new e;

      else
        return copyFile(path, newPath, flags)
          .then(() => unlinkFile(path));
    });

moveFile只是一个方便的函数，我们可以分别应用这些函数，例如，当我们需要更细粒度的异常处理时。

fs-extra模块允许你用它的move()方法来做这件事。我已经实现了它，它工作得很好，如果你想完全移动一个文件从一个目录到另一个-即。从源目录中删除文件。应该适用于大多数基本情况。

var fs = require('fs-extra')

fs.move('/tmp/somefile', '/tmp/does/not/exist/yet/somefile', function (err) {
 if (err) return console.error(err)
 console.log("success!")
})

跑龙套。节点0.10弃用Pump，产生警告信息

 util.pump() is deprecated. Use readableStream.pipe() instead

因此，使用流复制文件的解决方案是:

var source = fs.createReadStream('/path/to/source');
var dest = fs.createWriteStream('/path/to/dest');

source.pipe(dest);
source.on('end', function() { /* copied */ });
source.on('error', function(err) { /* error */ });

这个例子摘自:Node.js in Action

move()函数，如果可能，将重命名或返回到复制

var fs = require('fs');

module.exports = function move(oldPath, newPath, callback) {

    fs.rename(oldPath, newPath, function (err) {
        if (err) {
            if (err.code === 'EXDEV') {
                copy();
            } else {
                callback(err);
            }
            return;
        }
        callback();
    });

    function copy() {
        var readStream = fs.createReadStream(oldPath);
        var writeStream = fs.createWriteStream(newPath);

        readStream.on('error', callback);
        writeStream.on('error', callback);

        readStream.on('close', function () {
            fs.unlink(oldPath, callback);
        });

        readStream.pipe(writeStream);
    }
}