如何在node.js上移动文件(如mv命令shell) ?是否有任何方法,或者我应该读取一个文件,写到一个新文件,并删除旧文件?


当前回答

使用mv节点模块,它将首先尝试执行fs。重命名,然后退回到复制,然后取消链接。

其他回答

在下面URL的帮助下,您可以复制或移动您的文件CURRENT Source到Destination Source

https://coursesweb.net/nodejs/move-copy-file

/*********Moves the $file to $dir2 Start *********/ var moveFile = (file, dir2)=>{ //include the fs, path modules var fs = require('fs'); var path = require('path'); //gets file name and adds it to dir2 var f = path.basename(file); var dest = path.resolve(dir2, f); fs.rename(file, dest, (err)=>{ if(err) throw err; else console.log('Successfully moved'); }); }; //move file1.htm from 'test/' to 'test/dir_1/' moveFile('./test/file1.htm', './test/dir_1/'); /*********Moves the $file to $dir2 END *********/ /*********copy the $file to $dir2 Start *********/ var copyFile = (file, dir2)=>{ //include the fs, path modules var fs = require('fs'); var path = require('path'); //gets file name and adds it to dir2 var f = path.basename(file); var source = fs.createReadStream(file); var dest = fs.createWriteStream(path.resolve(dir2, f)); source.pipe(dest); source.on('end', function() { console.log('Succesfully copied'); }); source.on('error', function(err) { console.log(err); }); }; //example, copy file1.htm from 'test/dir_1/' to 'test/' copyFile('./test/dir_1/file1.htm', './test/'); /*********copy the $file to $dir2 END *********/

节点.js v10.0.0+

const fs = require('fs')
const { promisify } = require('util')
const pipeline = promisify(require('stream').pipeline)

await pipeline(
  fs.createReadStream('source/file/path'),
  fs.createWriteStream('destination/file/path')
).catch(err => {
  // error handling
})
fs.unlink('source/file/path')

如果你喜欢使用外部库,Shelljs是一个非常方便的解决方案。

命令: Mv ([options,] source, destination)

可用的选项:

-f: force(默认行为)

-n:防止覆盖

const shell = require('shelljs');
const status = shell.mv('README.md', '/home/my-dir');
if(status.stderr)  console.log(status.stderr);
else console.log('File moved!');

使用rename函数:

fs.rename(getFileName, __dirname + '/new_folder/' + getFileName); 

在哪里

getFilename = file.extension (old path)
__dirname + '/new_folder/' + getFileName

假设您希望保持文件名不变。

这是对teoman shipahi的回答的重新讨论,使用了一个稍微不那么模糊的名称,并遵循了在尝试调用代码之前定义代码的设计原则。(虽然node允许您做其他事情,但本末倒置并不是一个好的实践。)

function rename_or_copy_and_delete (oldPath, newPath, callback) {

    function copy_and_delete () {
        var readStream = fs.createReadStream(oldPath);
        var writeStream = fs.createWriteStream(newPath);

        readStream.on('error', callback);
        writeStream.on('error', callback);
        readStream.on('close', 
              function () {
                fs.unlink(oldPath, callback);
              }
        );

        readStream.pipe(writeStream);
    }

    fs.rename(oldPath, newPath, 
        function (err) {
          if (err) {
              if (err.code === 'EXDEV') {
                  copy_and_delete();
              } else {
                  callback(err);
              }
              return;// << both cases (err/copy_and_delete)
          }
          callback();
        }
    );
}