这是对teoman shipahi的回答的重新讨论，使用了一个稍微不那么模糊的名称，并遵循了在尝试调用代码之前定义代码的设计原则。(虽然node允许您做其他事情，但本末倒置并不是一个好的实践。)

function rename_or_copy_and_delete (oldPath, newPath, callback) {

    function copy_and_delete () {
        var readStream = fs.createReadStream(oldPath);
        var writeStream = fs.createWriteStream(newPath);

        readStream.on('error', callback);
        writeStream.on('error', callback);
        readStream.on('close', 
              function () {
                fs.unlink(oldPath, callback);
              }
        );

        readStream.pipe(writeStream);
    }

    fs.rename(oldPath, newPath, 
        function (err) {
          if (err) {
              if (err.code === 'EXDEV') {
                  copy_and_delete();
              } else {
                  callback(err);
              }
              return;// << both cases (err/copy_and_delete)
          }
          callback();
        }
    );
}

下面是一个使用util的例子。我如何移动文件a到不同的分区或设备在Node.js?

var fs = require('fs'),
    util = require('util');

var is = fs.createReadStream('source_file')
var os = fs.createWriteStream('destination_file');

util.pump(is, os, function() {
    fs.unlinkSync('source_file');
});

我将把所有涉及的函数(即重命名，复制，断开链接)彼此分离，以获得灵活性，并承诺一切，当然:

const renameFile = (path, newPath) => 
  new Promise((res, rej) => {
    fs.rename(path, newPath, (err, data) =>
      err
        ? rej(err)
        : res(data));
  });

const copyFile = (path, newPath, flags) =>
  new Promise((res, rej) => {
    const readStream = fs.createReadStream(path),
      writeStream = fs.createWriteStream(newPath, {flags});

    readStream.on("error", rej);
    writeStream.on("error", rej);
    writeStream.on("finish", res);
    readStream.pipe(writeStream);
  });

const unlinkFile = path => 
  new Promise((res, rej) => {
    fs.unlink(path, (err, data) =>
      err
        ? rej(err)
        : res(data));
  });

const moveFile = (path, newPath, flags) =>
  renameFile(path, newPath)
    .catch(e => {
      if (e.code !== "EXDEV")
        throw new e;

      else
        return copyFile(path, newPath, flags)
          .then(() => unlinkFile(path));
    });

moveFile只是一个方便的函数，我们可以分别应用这些函数，例如，当我们需要更细粒度的异常处理时。

fs-extra模块允许你用它的move()方法来做这件事。我已经实现了它，它工作得很好，如果你想完全移动一个文件从一个目录到另一个-即。从源目录中删除文件。应该适用于大多数基本情况。

var fs = require('fs-extra')

fs.move('/tmp/somefile', '/tmp/does/not/exist/yet/somefile', function (err) {
 if (err) return console.error(err)
 console.log("success!")
})

如果你喜欢使用外部库，Shelljs是一个非常方便的解决方案。

命令: Mv ([options，] source, destination)

可用的选项:

-f: force(默认行为)

-n:防止覆盖

const shell = require('shelljs');
const status = shell.mv('README.md', '/home/my-dir');
if(status.stderr)  console.log(status.stderr);
else console.log('File moved!');

这是对teoman shipahi的回答的重新讨论，使用了一个稍微不那么模糊的名称，并遵循了在尝试调用代码之前定义代码的设计原则。(虽然node允许您做其他事情，但本末倒置并不是一个好的实践。)

function rename_or_copy_and_delete (oldPath, newPath, callback) {

    function copy_and_delete () {
        var readStream = fs.createReadStream(oldPath);
        var writeStream = fs.createWriteStream(newPath);

        readStream.on('error', callback);
        writeStream.on('error', callback);
        readStream.on('close', 
              function () {
                fs.unlink(oldPath, callback);
              }
        );

        readStream.pipe(writeStream);
    }

    fs.rename(oldPath, newPath, 
        function (err) {
          if (err) {
              if (err.code === 'EXDEV') {
                  copy_and_delete();
              } else {
                  callback(err);
              }
              return;// << both cases (err/copy_and_delete)
          }
          callback();
        }
    );
}