我有字符串名称= "admin"; 然后我做String charValue = name.substring(0,1);/ / charValue = " "

我想将charValue转换为它的ASCII值(97),我如何在java中做到这一点?


当前回答

将char型转换为int型。

    String name = "admin";
    int ascii = name.toCharArray()[0];

另外:

int ascii = name.charAt(0);

其他回答

使用Java 9 => String.chars()

String input = "stackoverflow";
System.out.println(input.chars().boxed().collect(Collectors.toList()));

输出- [115,116,97,99,107,111,118,101,114,102,108,111,119]

这很简单,获取你想要的字符,并将其转换为int。

String name = "admin";
int ascii = name.charAt(0);

将char型转换为int型。

    String name = "admin";
    int ascii = name.toCharArray()[0];

另外:

int ascii = name.charAt(0);

你可以用这段代码检查ASCII的数字。

String name = "admin";
char a1 = a.charAt(0);
int a2 = a1;
System.out.println("The number is : "+a2); // the value is 97

如果我错了,我道歉。

String str = "abc";  // or anything else

// Stores strings of integer representations in sequence
StringBuilder sb = new StringBuilder();
for (char c : str.toCharArray())
    sb.append((int)c);

 // store ascii integer string array in large integer
BigInteger mInt = new BigInteger(sb.toString());
System.out.println(mInt);