或者你可以使用流API为一个字符或从Java 1.8开始的字符串:

public class ASCIIConversion {
    public static void main(String[] args) {
        String text = "adskjfhqewrilfgherqifvehwqfjklsdbnf";
        text.chars()
                .forEach(System.out::println);
    }
}

不使用额外int变量的一行解决方案:

String name = "admin";
System.out.println((int)name.charAt(0));

这很简单，获取你想要的字符，并将其转换为int。

String name = "admin";
int ascii = name.charAt(0);

String str = "abc";  // or anything else

// Stores strings of integer representations in sequence
StringBuilder sb = new StringBuilder();
for (char c : str.toCharArray())
    sb.append((int)c);

 // store ascii integer string array in large integer
BigInteger mInt = new BigInteger(sb.toString());
System.out.println(mInt);

最简单的方法是:

对于整个字符串转换成ASCII:

public class ConvertToAscii{
    public static void main(String args[]){
      String abc = "admin";
      int []arr = new int[abc.length()];
      System.out.println("THe asscii value of each character is: ");
      for(int i=0;i<arr.length;i++){
          arr[i] = abc.charAt(i); // assign the integer value of character i.e ascii
          System.out.print(" "+arr[i]);
      }
    }
}

输出结果为:

每个字符的asscii值为: 97 100 109 105 110 这里，abc.charAt(i)给出了String数组的单个字符: 当我们将每个字符赋值为整型时，编译器会进行类型转换，

arr[i] = (int) character //这里，每个单独的字符都是ascii值

但是，对于单个字符:

字符串名称= admin; asciiValue = (int) name.charAt(0);//字符'a' System.out.println (asciiValue);

使用Java 9 => String.chars()

String input = "stackoverflow";
System.out.println(input.chars().boxed().collect(Collectors.toList()));

输出- [115,116,97,99,107,111,118,101,114,102,108,111,119]