我有字符串名称= "admin"; 然后我做String charValue = name.substring(0,1);/ / charValue = " "
我想将charValue转换为它的ASCII值(97),我如何在java中做到这一点?
我有字符串名称= "admin"; 然后我做String charValue = name.substring(0,1);/ / charValue = " "
我想将charValue转换为它的ASCII值(97),我如何在java中做到这一点?
当前回答
String str = "abc"; // or anything else
// Stores strings of integer representations in sequence
StringBuilder sb = new StringBuilder();
for (char c : str.toCharArray())
sb.append((int)c);
// store ascii integer string array in large integer
BigInteger mInt = new BigInteger(sb.toString());
System.out.println(mInt);
其他回答
不使用额外int变量的一行解决方案:
String name = "admin";
System.out.println((int)name.charAt(0));
而不是这样:
String char = name.substring(0,1); //char="a"
您应该使用charAt()方法。
char c = name.charAt(0); // c='a'
int ascii = (int)c;
你可以用这段代码检查ASCII的数字。
String name = "admin";
char a1 = a.charAt(0);
int a2 = a1;
System.out.println("The number is : "+a2); // the value is 97
如果我错了,我道歉。
一个简单的方法是:
int character = 'a';
如果你输入“character”,你得到97。
String str = "abc"; // or anything else
// Stores strings of integer representations in sequence
StringBuilder sb = new StringBuilder();
for (char c : str.toCharArray())
sb.append((int)c);
// store ascii integer string array in large integer
BigInteger mInt = new BigInteger(sb.toString());
System.out.println(mInt);