由于眼睛的问题,我不得不将控制台背景色改为白色,但字体是灰色的,它使消息无法阅读。我怎样才能改变呢?


当前回答

var colorSet = {
    Reset: "\x1b[0m",
    Red: "\x1b[31m",
    Green: "\x1b[32m",
    Yellow: "\x1b[33m",
    Blue: "\x1b[34m",
    Magenta: "\x1b[35m"
};

var funcNames = ["info", "log", "warn", "error"];
var colors = [colorSet.Green, colorSet.Blue, colorSet.Yellow, colorSet.Red];

for (var i = 0; i < funcNames.length; i++) {
    let funcName = funcNames[i];
    let color = colors[i];
    let oldFunc = console[funcName];
    console[funcName] = function () {
        var args = Array.prototype.slice.call(arguments);
        if (args.length) {
            args = [color + args[0]].concat(args.slice(1), colorSet.Reset);
        }
        oldFunc.apply(null, args);
    };
}

// Test:
console.info("Info is green.");
console.log("Log is blue.");
console.warn("Warn is orange.");
console.error("Error is red.");
console.info("--------------------");
console.info("Formatting works as well. The number = %d", 123);

其他回答

我发现上面的答案(https://stackoverflow.com/a/41407246/4808079)非常有用,但不完整。如果你只想给某样东西上色一次,我想这没问题,但我认为以可运行的函数形式共享它更适用于现实生活中的用例。

const Color = {
  Reset: "\x1b[0m",
  Bright: "\x1b[1m",
  Dim: "\x1b[2m",
  Underscore: "\x1b[4m",
  Blink: "\x1b[5m",
  Reverse: "\x1b[7m",
  Hidden: "\x1b[8m",
  
  FgBlack: "\x1b[30m",
  FgRed: "\x1b[31m",
  FgGreen: "\x1b[32m",
  FgYellow: "\x1b[33m",
  FgBlue: "\x1b[34m",
  FgMagenta: "\x1b[35m",
  FgCyan: "\x1b[36m",
  FgWhite: "\x1b[37m",
  FgGray: "\x1b[90m",
  
  BgBlack: "\x1b[40m",
  BgRed: "\x1b[41m",
  BgGreen: "\x1b[42m",
  BgYellow: "\x1b[43m",
  BgBlue: "\x1b[44m",
  BgMagenta: "\x1b[45m",
  BgCyan: "\x1b[46m",
  BgWhite: "\x1b[47m"
  BgGray: "\x1b[100m",
}

function colorString(color, string) {
  return `${color}${string}${Color.Reset}`;
}

function colorLog(color, ...args) {
  console.log(...args.map(
   (it) => typeof it === "string" ? colorString(color, string) : it
  ));
}

像这样使用它:

colorLog(Color.FgYellow, "Some Yellow text to console log", { someObj: true });

console.log([
  colorString(Color.FgRed, "red"),
  colorString(Color.FgGreen, "green"),
  colorString(Color.FgBlue, "blue"),
].join(", "));

对于一个不影响String对象的内置方法的流行替代颜色,我推荐使用cli-color。

包括颜色和可链接样式,如粗体、斜体和下划线。

有关此类别中各个模块的比较,请参见这里。

另一种方法是使用一个简单的ANSI代码生成器。

您不需要安装软件包 不需要搜索颜色代码,只需点击按钮

GIF演示

你可以在https://console-colors.vercel.app/上使用它

公共存储库:https://github.com/alecshoppe/console-colors

最小的别名:

{
  const f = (color) => (...args) => {
    for (const x of [color, ...args, "\33[0m"]) console.log(x);
  };

  Object.assign(console, {
    black: f("\33[30m"),
    red: f("\33[31m"),
    green: f("\33[32m"),
    yellow: f("\33[33m"),
    blue: f("\33[34m"),
    magenta: f("\33[35m"),
    cyan: f("\33[36m"),
    white: f("\33[37m"),
  });
}

// Usage
console.blue("Blue world");

如果你想改变颜色直接自己没有模块尝试

console.log('\x1b[36m', 'sometext' ,'\x1b[0m');

先\x1b[36m改变颜色为36,然后回到终端颜色0。

下面是ANSI颜色代码列表