由于眼睛的问题,我不得不将控制台背景色改为白色,但字体是灰色的,它使消息无法阅读。我怎样才能改变呢?


当前回答

Sindre Sorhus设计的这个图书馆是目前最好的:

粉笔

高性能 不扩展String.prototype 富有表现力的API 嵌套样式的能力 干净和专注 自动检测颜色支持 积极维护 5500+模块使用

其他回答

var to_rgb = function (_text, _r, _g, _b) {
    return "\x1b[38;2;" + _r + ";" + _g + ";" + _b + "m" + _text + "\x1b[0m";
};

此代码帮助设置前景色:\x1b[38;2;R;G;Bm

这在某些地方可能行不通

如果你想改变颜色直接自己没有模块尝试

console.log('\x1b[36m', 'sometext' ,'\x1b[0m');

先\x1b[36m改变颜色为36,然后回到终端颜色0。

下面是ANSI颜色代码列表

If you are using Windows CMD then go to the terminal Properties/Colors (CMD top left) and then redefine the RGB value of the offensive color. In my case I believe it's the fifth color square from the left, which I changed to (222,222,222). It does not matter if the currently selected radio button shows Screen Text or Screen Background as you just redefine that specific "system" color. Once you changed the color don't forget to select back the preferred color for the background or text before clicking OK.

更改后,所有来自Node(在我的情况下是Ember)的红色消息都清晰可见。

我不想要任何依赖于此,只有这些在OS x上为我工作。所有其他示例从这里的答案给了我八进制文字错误。

Reset = "\x1b[0m"
Bright = "\x1b[1m"
Dim = "\x1b[2m"
Underscore = "\x1b[4m"
Blink = "\x1b[5m"
Reverse = "\x1b[7m"
Hidden = "\x1b[8m"

FgBlack = "\x1b[30m"
FgRed = "\x1b[31m"
FgGreen = "\x1b[32m"
FgYellow = "\x1b[33m"
FgBlue = "\x1b[34m"
FgMagenta = "\x1b[35m"
FgCyan = "\x1b[36m"
FgWhite = "\x1b[37m"
FgGray = "\x1b[90m"

BgBlack = "\x1b[40m"
BgRed = "\x1b[41m"
BgGreen = "\x1b[42m"
BgYellow = "\x1b[43m"
BgBlue = "\x1b[44m"
BgMagenta = "\x1b[45m"
BgCyan = "\x1b[46m"
BgWhite = "\x1b[47m"
BgGray = "\x1b[100m"

来源:https://coderwall.com/p/yphywg/printing-colorful-text-in-terminal-when-run-node-js-script

如果你想保持简单,而不使用任何外部模块/学习新的api /破解核心控制台功能:

const LCERROR = '\x1b[31m%s\x1b[0m'; //red
const LCWARN = '\x1b[33m%s\x1b[0m'; //yellow
const LCINFO = '\x1b[36m%s\x1b[0m'; //cyan
const LCSUCCESS = '\x1b[32m%s\x1b[0m'; //green

const logger = class {
  static error(message, ...optionalParams) { console.error(LCERROR, message, ...optionalParams) }
  static warn(message, ...optionalParams) { console.warn(LCWARN, message, ...optionalParams) }
  static info(message, ...optionalParams) { console.info(LCINFO, message, ...optionalParams) }
  static success(message, ...optionalParams) { console.info(LCSUCCESS, message, ...optionalParams) }
}

// then instead (as presented in the accepted answer)
// console.error(LCERROR, 'Error message in red.');
// you write:

logger.error('Error message in red.');

// or with multiple parameters (only the message will be red):

logger.error('Error message in red.', 1, false, null, {someKey: 'whatever'});

// or use backticks (template literal) instead multiple params:

logger.error(`This will be red as ${foo} and ${bar} too.`);

现在您可以像使用控制台一样使用记录器。没有新的API需要记住……通常你会把它放到一个模块(logger.js)中,并导出类,以便在你的应用程序中随处使用它,因为const logger = require('./logger');