初始化数组:val paramValueList: array <String?> = arrayOfNulls<String>(5)

I think one thing that is worth mentioning and isn't intuitive enough from the documentation is that, when you use a factory function to create an array and you specify it's size, the array is initialized with values that are equal to their index values. For example, in an array such as this: val array = Array(5, { i -> i }), the initial values assigned are [0,1,2,3,4] and not say, [0,0,0,0,0]. That is why from the documentation, val asc = Array(5, { i -> (i * i).toString() }) produces an answer of ["0", "1", "4", "9", "16"]

值得一提的是，当使用kotlin内置程序(例如intArrayOf()， longArrayOf()， arrayOf()等)时，对于给定的大小，您不能使用默认值(或所有值为所需值)初始化数组，相反，您需要通过根据类构造函数调用来进行初始化。

// Array of integers of a size of N
val arr = IntArray(N)

// Array of integers of a size of N initialized with a default value of 2
val arr = IntArray(N) { i -> 2 }

你可以试试这个:

var a = Array<Int>(5){0}

通过这种方式，可以在koltin中初始化int数组。

 val values: IntArray = intArrayOf(1, 2, 3, 4, 5,6,7)

您可以使用这些方法

var numbers=Array<Int>(size,init)
var numbers=IntArray(size,init)
var numbers= intArrayOf(1,2,3)

例子

var numbers = Array<Int>(5, { i -> 0 })

Init表示默认值(initialize)