在Java中,数组可以这样初始化:
int numbers[] = new int[] {10, 20, 30, 40, 50}
Kotlin的数组初始化是怎样的?
在Java中,数组可以这样初始化:
int numbers[] = new int[] {10, 20, 30, 40, 50}
Kotlin的数组初始化是怎样的?
当前回答
初始化数组:val paramValueList: array <String?> = arrayOfNulls<String>(5)
其他回答
在Java中,数组可以这样初始化:
int numbers[] = new int[] {10, 20, 30, 40, 50}
但是在Kotlin中,数组初始化的方式有很多,比如:
任何泛型类型的数组都可以使用arrayOf()函数:
val arr = arrayOf(10, 20, 30, 40, 50)
val genericArray = arrayOf(10, "Stack", 30.00, 40, "Fifty")
使用Kotlin的实用函数可以初始化数组
val intArray = intArrayOf(10, 20, 30, 40, 50)
在全局声明int array
var numbers= intArrayOf()
方法用value初始化数组
override fun onCreate(savedInstanceState: Bundle?) {
super.onCreate(savedInstanceState)
setContentView(R.layout.activity_main)
//create your int array here
numbers= intArrayOf(10,20,30,40,50)
}
这里有一个例子:
fun main(args: Array<String>) {
val arr = arrayOf(1, 2, 3);
for (item in arr) {
println(item);
}
}
您还可以使用游乐场来测试语言特性。
I think one thing that is worth mentioning and isn't intuitive enough from the documentation is that, when you use a factory function to create an array and you specify it's size, the array is initialized with values that are equal to their index values. For example, in an array such as this: val array = Array(5, { i -> i }), the initial values assigned are [0,1,2,3,4] and not say, [0,0,0,0,0]. That is why from the documentation, val asc = Array(5, { i -> (i * i).toString() }) produces an answer of ["0", "1", "4", "9", "16"]
对于二维数组:
val rows = 3
val cols = 3
val value = 0
val array = Array(rows) { Array<Int>(cols) { value } }
您可以将元素类型更改为您想要的任何类型(String, Class,…),并将值更改为相应的默认值。