在Java中,数组可以这样初始化:
int numbers[] = new int[] {10, 20, 30, 40, 50}
Kotlin的数组初始化是怎样的?
在Java中,数组可以这样初始化:
int numbers[] = new int[] {10, 20, 30, 40, 50}
Kotlin的数组初始化是怎样的?
当前回答
通过这种方式,可以在koltin中初始化int数组。
val values: IntArray = intArrayOf(1, 2, 3, 4, 5,6,7)
其他回答
你可以像这样创建一个Int数组:
val numbers = IntArray(5, { 10 * (it + 1) })
5是Int数组的大小。函数是元素init函数。“it”范围在[0,4],加上1 make范围在[1,5]
原点函数为:
/**
* An array of ints. When targeting the JVM, instances of this class are
* represented as `int[]`.
* @constructor Creates a new array of the specified [size], with all elements
* initialized to zero.
*/
public class IntArray(size: Int) {
/**
* Creates a new array of the specified [size], where each element is
* calculated by calling the specified
* [init] function. The [init] function returns an array element given
* its index.
*/
public inline constructor(size: Int, init: (Int) -> Int)
...
}
定义在Arrays.kt中的IntArray类
在全局声明int array
var numbers= intArrayOf()
方法用value初始化数组
override fun onCreate(savedInstanceState: Bundle?) {
super.onCreate(savedInstanceState)
setContentView(R.layout.activity_main)
//create your int array here
numbers= intArrayOf(10,20,30,40,50)
}
你可以这样做:
val numbers = intArrayOf(10, 20, 30, 40, 50)
or
val numbers = arrayOf<Int>(10, 20, 30, 40, 50)
also
val numbers = arrayOf(10, 20, 30, 40, 50)
初始化数组:val paramValueList: array <String?> = arrayOfNulls<String>(5)
简单的方法:
整数:
var number = arrayOf< Int> (10,20,30,40,50)
保持所有数据类型
var number = arrayOf(10, "string value", 10.5)