在Java中,数组可以这样初始化:
int numbers[] = new int[] {10, 20, 30, 40, 50}
Kotlin的数组初始化是怎样的?
在Java中,数组可以这样初始化:
int numbers[] = new int[] {10, 20, 30, 40, 50}
Kotlin的数组初始化是怎样的?
当前回答
通过这种方式,可以在koltin中初始化int数组。
val values: IntArray = intArrayOf(1, 2, 3, 4, 5,6,7)
其他回答
在全局声明int array
var numbers= intArrayOf()
方法用value初始化数组
override fun onCreate(savedInstanceState: Bundle?) {
super.onCreate(savedInstanceState)
setContentView(R.layout.activity_main)
//create your int array here
numbers= intArrayOf(10,20,30,40,50)
}
I think one thing that is worth mentioning and isn't intuitive enough from the documentation is that, when you use a factory function to create an array and you specify it's size, the array is initialized with values that are equal to their index values. For example, in an array such as this: val array = Array(5, { i -> i }), the initial values assigned are [0,1,2,3,4] and not say, [0,0,0,0,0]. That is why from the documentation, val asc = Array(5, { i -> (i * i).toString() }) produces an answer of ["0", "1", "4", "9", "16"]
简单的方法:
整数:
var number = arrayOf< Int> (10,20,30,40,50)
保持所有数据类型
var number = arrayOf(10, "string value", 10.5)
您可以使用这些方法
var numbers=Array<Int>(size,init)
var numbers=IntArray(size,init)
var numbers= intArrayOf(1,2,3)
例子
var numbers = Array<Int>(5, { i -> 0 })
Init表示默认值(initialize)
你可以像这样创建一个Int数组:
val numbers = IntArray(5, { 10 * (it + 1) })
5是Int数组的大小。函数是元素init函数。“it”范围在[0,4],加上1 make范围在[1,5]
原点函数为:
/**
* An array of ints. When targeting the JVM, instances of this class are
* represented as `int[]`.
* @constructor Creates a new array of the specified [size], with all elements
* initialized to zero.
*/
public class IntArray(size: Int) {
/**
* Creates a new array of the specified [size], where each element is
* calculated by calling the specified
* [init] function. The [init] function returns an array element given
* its index.
*/
public inline constructor(size: Int, init: (Int) -> Int)
...
}
定义在Arrays.kt中的IntArray类