根据公认的答案和另外两个问题1,2，我整理了以下问题:

SELECT
    QUOTENAME(t.name) AS TableName,
    QUOTENAME(i.name) AS IndexName,
    i.is_primary_key,
    i.is_unique,
    i.is_unique_constraint,
    STUFF(REPLACE(REPLACE((
        SELECT QUOTENAME(c.name) + CASE WHEN ic.is_descending_key = 1 THEN ' DESC' ELSE '' END AS [data()]
        FROM sys.index_columns AS ic
        INNER JOIN sys.columns AS c ON ic.object_id = c.object_id AND ic.column_id = c.column_id
        WHERE ic.object_id = i.object_id AND ic.index_id = i.index_id AND ic.is_included_column = 0
        ORDER BY ic.key_ordinal
        FOR XML PATH
    ), '<row>', ', '), '</row>', ''), 1, 2, '') AS KeyColumns,
    STUFF(REPLACE(REPLACE((
        SELECT QUOTENAME(c.name) AS [data()]
        FROM sys.index_columns AS ic
        INNER JOIN sys.columns AS c ON ic.object_id = c.object_id AND ic.column_id = c.column_id
        WHERE ic.object_id = i.object_id AND ic.index_id = i.index_id AND ic.is_included_column = 1
        ORDER BY ic.index_column_id
        FOR XML PATH
    ), '<row>', ', '), '</row>', ''), 1, 2, '') AS IncludedColumns,
    u.user_seeks,
    u.user_scans,
    u.user_lookups,
    u.user_updates
FROM sys.tables AS t
INNER JOIN sys.indexes AS i ON t.object_id = i.object_id
LEFT JOIN sys.dm_db_index_usage_stats AS u ON i.object_id = u.object_id AND i.index_id = u.index_id
WHERE t.is_ms_shipped = 0
AND i.type <> 0

该查询返回如下所示的结果，其中显示了索引的列表、它们的列和用法。非常有助于确定哪个指数比其他指数表现更好:

select i.object_id, i.name as [index] , STRING_AGG(c.name,', ') as [column], o.name as [table] from sys.indexes i
INNER join sys.index_columns ic on ic.object_id = i.object_id and ic.index_id = i.index_id
INNER join sys.columns c on c.object_id = ic.object_id and ic.column_id = c.column_id
INNER JOIN sys.objects o on o.object_id = i.object_id
where i.object_id > 100 and i.is_primary_key = 0 and i.is_unique = 0 and o.is_ms_shipped <> 1
group by i.object_id, i.name, o.name
order by i.name

将此用于sql 2016及更高级别，它会显示object_id, indexname，列和表名为非唯一的，没有主键

对于每个索引的唯一列:

select s.name, t.name, i.name, i.index_id,c.name,c.column_id
 from sys.schemas s
inner join sys.tables t on t.schema_id = s.schema_id
inner join sys.indexes i on i.object_id = t.object_id
inner join sys.index_columns ic on ic.object_id = t.object_id
    and ic.index_id=i.index_id
inner join sys.columns c on c.object_id = t.object_id 
    and ic.column_id = c.column_id
where i.object_id = object_id('previous.account_1')  
order by index_id,column_id

——简短而甜蜜:

SELECT OBJECT_SCHEMA_NAME(T.[object_id],DB_ID()) AS [Schema],  
  T.[name] AS [table_name], I.[name] AS [index_name], AC.[name] AS [column_name],  
  I.[type_desc], I.[is_unique], I.[data_space_id], I.[ignore_dup_key], I.[is_primary_key], 
  I.[is_unique_constraint], I.[fill_factor],    I.[is_padded], I.[is_disabled], I.[is_hypothetical], 
  I.[allow_row_locks], I.[allow_page_locks], IC.[is_descending_key], IC.[is_included_column] 
FROM sys.[tables] AS T  
  INNER JOIN sys.[indexes] I ON T.[object_id] = I.[object_id]  
  INNER JOIN sys.[index_columns] IC ON I.[object_id] = IC.[object_id] 
  INNER JOIN sys.[all_columns] AC ON T.[object_id] = AC.[object_id] AND IC.[column_id] = AC.[column_id] 
WHERE T.[is_ms_shipped] = 0 AND I.[type_desc] <> 'HEAP' 
ORDER BY T.[name], I.[index_id], IC.[key_ordinal]   

这是可行的:

DECLARE @IndexInfo  TABLE (index_name         varchar(250)
                          ,index_description  varchar(250)
                          ,index_keys         varchar(250)
                          )

INSERT INTO @IndexInfo
exec sp_msforeachtable 'sp_helpindex ''?'''
select * from @IndexInfo

这不会返回表名，你会得到所有没有索引的表的警告，如果这是一个问题，你可以在有索引的表上创建一个循环，像这样:

DECLARE @IndexInfoTemp  TABLE (index_name         varchar(250)
                              ,index_description  varchar(250)
                              ,index_keys         varchar(250)
                              )

DECLARE @IndexInfo  TABLE (table_name         sysname
                          ,index_name         varchar(250)
                          ,index_description  varchar(250)
                          ,index_keys         varchar(250)
                          )

DECLARE @Tables Table (RowID       int not null identity(1,1)
                      ,TableName   sysname 
                      )
DECLARE @MaxRow       int
DECLARE @CurrentRow   int
DECLARE @CurrentTable sysname

INSERT INTO @Tables
    SELECT
        DISTINCT t.name 
        FROM sys.indexes i
            INNER JOIN sys.tables t ON i.object_id = t.object_id
        WHERE i.Name IS NOT NULL
SELECT @MaxRow=@@ROWCOUNT,@CurrentRow=1

WHILE @CurrentRow<=@MaxRow
BEGIN

    SELECT @CurrentTable=TableName FROM @Tables WHERE RowID=@CurrentRow

    INSERT INTO @IndexInfoTemp
    exec sp_helpindex @CurrentTable

    INSERT INTO @IndexInfo
            (table_name   , index_name , index_description , index_keys)
        SELECT
            @CurrentTable , index_name , index_description , index_keys
        FROM @IndexInfoTemp

    DELETE FROM @IndexInfoTemp

    SET @CurrentRow=@CurrentRow+1

END --WHILE
SELECT * from @IndexInfo

编辑 如果你愿意，你可以过滤数据，这里有一些例子(这两种方法都适用):

SELECT * FROM @IndexInfo WHERE index_description NOT LIKE '%primary key%'
SELECT * FROM @IndexInfo WHERE index_description NOT LIKE '%nonclustered%' AND index_description  LIKE '%clustered%'
SELECT * FROM @IndexInfo WHERE index_description LIKE '%unique%'

我没有经过，但是我在原作者发布的查询中得到了我想要的东西。

我使用它(没有条件/过滤器)来满足我的需求，但它给出了不正确的结果

主要问题是在index_id上没有连接条件的情况下得到叉乘

SELECT S.NAME SCHEMA_NAME,T.NAME TABLE_NAME,I.NAME INDEX_NAME,C.NAME COLUMN_NAME
  FROM SYS.TABLES T
       INNER JOIN SYS.SCHEMAS S
    ON T.SCHEMA_ID = S.SCHEMA_ID
       INNER JOIN SYS.INDEXES I
    ON I.OBJECT_ID = T.OBJECT_ID
       INNER JOIN SYS.INDEX_COLUMNS IC
    ON IC.OBJECT_ID = T.OBJECT_ID
       INNER JOIN SYS.COLUMNS C
    ON C.OBJECT_ID  = T.OBJECT_ID
   **AND IC.INDEX_ID    = I.INDEX_ID**
   AND IC.COLUMN_ID = C.COLUMN_ID
 WHERE 1=1

ORDER BY I.NAME,I.INDEX_ID,IC.KEY_ORDINAL