如何在SQL Server 2005+中获得所有索引和索引列的列表?我能想到的最接近的是:
select s.name, t.name, i.name, c.name from sys.tables t
inner join sys.schemas s on t.schema_id = s.schema_id
inner join sys.indexes i on i.object_id = t.object_id
inner join sys.index_columns ic on ic.object_id = t.object_id
inner join sys.columns c on c.object_id = t.object_id and
ic.column_id = c.column_id
where i.index_id > 0
and i.type in (1, 2) -- clustered & nonclustered only
and i.is_primary_key = 0 -- do not include PK indexes
and i.is_unique_constraint = 0 -- do not include UQ
and i.is_disabled = 0
and i.is_hypothetical = 0
and ic.key_ordinal > 0
order by ic.key_ordinal
这可不是我想要的。
我想要的是，列出所有用户定义的索引，(这意味着不支持唯一约束和主键的索引)与所有列(按它们在索引定义中的出现方式排序)以及尽可能多的元数据。
以下工作在SQL Server 2014/2016以及任何Microsoft Azure SQL数据库。
生成一个全面的结果集，可以很容易地导出到Notepad/Excel中进行切片和切块
表名
索引名称
指数描述
索引列-按顺序
包括列-按顺序
SELECT '[' + s.NAME + '].[' + o.NAME + ']' AS 'table_name'
,+ i.NAME AS 'index_name'
,LOWER(i.type_desc) + CASE
WHEN i.is_unique = 1
THEN ', unique'
ELSE ''
END + CASE
WHEN i.is_primary_key = 1
THEN ', primary key'
ELSE ''
END AS 'index_description'
,STUFF((
SELECT ', [' + sc.NAME + ']' AS "text()"
FROM syscolumns AS sc
INNER JOIN sys.index_columns AS ic ON ic.object_id = sc.id
AND ic.column_id = sc.colid
WHERE sc.id = so.object_id
AND ic.index_id = i1.indid
AND ic.is_included_column = 0
ORDER BY key_ordinal
FOR XML PATH('')
), 1, 2, '') AS 'indexed_columns'
,STUFF((
SELECT ', [' + sc.NAME + ']' AS "text()"
FROM syscolumns AS sc
INNER JOIN sys.index_columns AS ic ON ic.object_id = sc.id
AND ic.column_id = sc.colid
WHERE sc.id = so.object_id
AND ic.index_id = i1.indid
AND ic.is_included_column = 1
FOR XML PATH('')
), 1, 2, '') AS 'included_columns'
FROM sysindexes AS i1
INNER JOIN sys.indexes AS i ON i.object_id = i1.id
AND i.index_id = i1.indid
INNER JOIN sysobjects AS o ON o.id = i1.id
INNER JOIN sys.objects AS so ON so.object_id = o.id
AND is_ms_shipped = 0
INNER JOIN sys.schemas AS s ON s.schema_id = so.schema_id
WHERE so.type = 'U'
AND i1.indid < 255
AND i1.STATUS & 64 = 0 --index with duplicates
AND i1.STATUS & 8388608 = 0 --auto created index
AND i1.STATUS & 16777216 = 0 --stats no recompute
AND i.type_desc <> 'heap'
AND so.NAME <> 'sysdiagrams'
ORDER BY table_name
,index_name;
以下工作在SQL Server 2014/2016以及任何Microsoft Azure SQL数据库。
生成一个全面的结果集，可以很容易地导出到Notepad/Excel中进行切片和切块
表名
索引名称
指数描述
索引列-按顺序
包括列-按顺序
SELECT '[' + s.NAME + '].[' + o.NAME + ']' AS 'table_name'
,+ i.NAME AS 'index_name'
,LOWER(i.type_desc) + CASE
WHEN i.is_unique = 1
THEN ', unique'
ELSE ''
END + CASE
WHEN i.is_primary_key = 1
THEN ', primary key'
ELSE ''
END AS 'index_description'
,STUFF((
SELECT ', [' + sc.NAME + ']' AS "text()"
FROM syscolumns AS sc
INNER JOIN sys.index_columns AS ic ON ic.object_id = sc.id
AND ic.column_id = sc.colid
WHERE sc.id = so.object_id
AND ic.index_id = i1.indid
AND ic.is_included_column = 0
ORDER BY key_ordinal
FOR XML PATH('')
), 1, 2, '') AS 'indexed_columns'
,STUFF((
SELECT ', [' + sc.NAME + ']' AS "text()"
FROM syscolumns AS sc
INNER JOIN sys.index_columns AS ic ON ic.object_id = sc.id
AND ic.column_id = sc.colid
WHERE sc.id = so.object_id
AND ic.index_id = i1.indid
AND ic.is_included_column = 1
FOR XML PATH('')
), 1, 2, '') AS 'included_columns'
FROM sysindexes AS i1
INNER JOIN sys.indexes AS i ON i.object_id = i1.id
AND i.index_id = i1.indid
INNER JOIN sysobjects AS o ON o.id = i1.id
INNER JOIN sys.objects AS so ON so.object_id = o.id
AND is_ms_shipped = 0
INNER JOIN sys.schemas AS s ON s.schema_id = so.schema_id
WHERE so.type = 'U'
AND i1.indid < 255
AND i1.STATUS & 64 = 0 --index with duplicates
AND i1.STATUS & 8388608 = 0 --auto created index
AND i1.STATUS & 16777216 = 0 --stats no recompute
AND i.type_desc <> 'heap'
AND so.NAME <> 'sysdiagrams'
ORDER BY table_name
,index_name;
正确的一个在这里(当我们在一个表上有多个索引时，以上所有帖子都会给出笛卡尔积结果)
select s.name, t.name, i.name, c.name from sys.tables t
inner join sys.schemas s on t.schema_id = s.schema_id
inner join sys.indexes i on i.object_id = t.object_id
inner join sys.index_columns ic on ic.object_id = t.object_id
AND i.index_id = ic.index_id
inner join sys.columns c on c.object_id = t.object_id
and ic.column_id = c.column_id
where i.index_id > 0
and i.type in (1, 2) -- clustered & nonclustered only
and i.is_primary_key = 0 -- do not include PK indexes
and i.is_unique_constraint = 0 -- do not include UQ
and i.is_disabled = 0
and i.is_hypothetical = 0
and ic.key_ordinal > 0
AND t.name = 'DimCustomer'
order by ic.key_ordinal
这是一种回退到索引的方法。您可以使用SHOWCONTIG来评估碎片。它将列出数据库或表的所有索引，以及统计信息。我要提醒的是，在大型数据库上，它可能是长时间运行的。对我来说，这种方法的好处之一是您不必是管理员就可以使用它。
——显示数据库中所有索引的碎片信息
SET NOCOUNT ON
USE pubs
DBCC SHOWCONTIG WITH ALL_INDEXES
GO
.．.完成后关闭NOCOUNT
——显示表中所有索引的碎片信息
SET NOCOUNT ON
USE pubs
DBCC SHOWCONTIG (authors) WITH ALL_INDEXES
GO
——显示特定索引上的碎片信息
SET NOCOUNT ON
USE pubs
DBCC SHOWCONTIG (authors,aunmind)
GO
我想到了这个，它给了我我需要的准确的概述。有帮助的是，每个索引得到一行，索引列被聚合到其中。
select
o.name as ObjectName,
i.name as IndexName,
i.is_primary_key as [PrimaryKey],
SUBSTRING(i.[type_desc],0,6) as IndexType,
i.is_unique as [Unique],
Columns.[Normal] as IndexColumns,
Columns.[Included] as IncludedColumns
from sys.indexes i
join sys.objects o on i.object_id = o.object_id
cross apply
(
select
substring
(
(
select ', ' + co.[name]
from sys.index_columns ic
join sys.columns co on co.object_id = i.object_id and co.column_id = ic.column_id
where ic.object_id = i.object_id and ic.index_id = i.index_id and ic.is_included_column = 0
order by ic.key_ordinal
for xml path('')
)
, 3
, 10000
) as [Normal]
, substring
(
(
select ', ' + co.[name]
from sys.index_columns ic
join sys.columns co on co.object_id = i.object_id and co.column_id = ic.column_id
where ic.object_id = i.object_id and ic.index_id = i.index_id and ic.is_included_column = 1
order by ic.key_ordinal
for xml path('')
)
, 3
, 10000
) as [Included]
) Columns
where o.[type] = 'U' --USER_TABLE
order by o.[name], i.[name], i.is_primary_key desc
根据Tim Ford的代码，这是正确答案:
select tab.[name] as [table_name],
idx.[name] as [index_name],
allc.[name] as [column_name],
idx.[type_desc],
idx.[is_unique],
idx.[data_space_id],
idx.[ignore_dup_key],
idx.[is_primary_key],
idx.[is_unique_constraint],
idx.[fill_factor],
idx.[is_padded],
idx.[is_disabled],
idx.[is_hypothetical],
idx.[allow_row_locks],
idx.[allow_page_locks],
idxc.[is_descending_key],
idxc.[is_included_column],
idxc.[index_column_id]
from sys.[tables] as tab
inner join sys.[indexes] idx on tab.[object_id] = idx.[object_id]
inner join sys.[index_columns] idxc on idx.[object_id] = idxc.[object_id] and idx.[index_id] = idxc.[index_id]
inner join sys.[all_columns] allc on tab.[object_id] = allc.[object_id] and idxc.[column_id] = allc.[column_id]
where tab.[name] Like '%table_name%'
and idx.[name] Like '%index_name%'
order by tab.[name], idx.[index_id], idxc.[index_column_id]
