如何在SQL Server 2005+中获得所有索引和索引列的列表?我能想到的最接近的是:
select s.name, t.name, i.name, c.name from sys.tables t
inner join sys.schemas s on t.schema_id = s.schema_id
inner join sys.indexes i on i.object_id = t.object_id
inner join sys.index_columns ic on ic.object_id = t.object_id
inner join sys.columns c on c.object_id = t.object_id and
ic.column_id = c.column_id
where i.index_id > 0
and i.type in (1, 2) -- clustered & nonclustered only
and i.is_primary_key = 0 -- do not include PK indexes
and i.is_unique_constraint = 0 -- do not include UQ
and i.is_disabled = 0
and i.is_hypothetical = 0
and ic.key_ordinal > 0
order by ic.key_ordinal
这可不是我想要的。
我想要的是,列出所有用户定义的索引,(这意味着不支持唯一约束和主键的索引)与所有列(按它们在索引定义中的出现方式排序)以及尽可能多的元数据。
这是我的,工作在一个默认模式,但它可以很容易地改进
它提供了3列SQLQueries -创建/删除/重建(没有重组)
查询:
SELECT
'CREATE ' +
CASE WHEN is_primary_key=1 THEN 'CLUSTERED'
WHEN is_primary_key=0 and is_unique_constraint=0 THEN 'NONCLUSTERED'
WHEN is_primary_key=0 and is_unique_constraint=1 THEN 'UNIQUE' END
+ ' INDEX ' +
QUOTENAME(i.name) + ' ON ' +
QUOTENAME(t.name) + ' ( ' +
STUFF(REPLACE(REPLACE((
SELECT QUOTENAME(c.name) + CASE WHEN ic.is_descending_key = 1 THEN ' DESC' ELSE '' END AS [data()]
FROM sys.index_columns AS ic
INNER JOIN sys.columns AS c ON ic.object_id = c.object_id AND ic.column_id = c.column_id
WHERE ic.object_id = i.object_id AND ic.index_id = i.index_id AND ic.is_included_column = 0
ORDER BY ic.key_ordinal
FOR XML PATH
), '<row>', ', '), '</row>', ''), 1, 2, '') + ' ) ' -- keycols
+ COALESCE(' INCLUDE ( ' +
STUFF(REPLACE(REPLACE((
SELECT QUOTENAME(c.name) AS [data()]
FROM sys.index_columns AS ic
INNER JOIN sys.columns AS c ON ic.object_id = c.object_id AND ic.column_id = c.column_id
WHERE ic.object_id = i.object_id AND ic.index_id = i.index_id AND ic.is_included_column = 1
ORDER BY ic.index_column_id
FOR XML PATH
), '<row>', ', '), '</row>', ''), 1, 2, '') + ' ) ', -- included cols
'') as [Create],
'DROP INDEX ' + QUOTENAME(i.name) + ' ON ' + QUOTENAME(t.name) as [Drop],
'ALTER INDEX ' + QUOTENAME(i.name) + ' ON ' +QUOTENAME(t.name) + ' REBUILD ' as [Rebuild]
FROM sys.tables AS t
INNER JOIN sys.indexes AS i ON t.object_id = i.object_id
LEFT JOIN sys.dm_db_index_usage_stats AS u ON i.object_id = u.object_id AND i.index_id = u.index_id
WHERE t.is_ms_shipped = 0
AND i.type <> 0
order by QUOTENAME(t.name), is_primary_key desc
输出
Create Drop Rebuild
-----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
CREATE CLUSTERED INDEX [PK_Table1] ON [Table1] ( [Tab1_ID] ) DROP INDEX [PK_Table1] ON [Table1] ALTER INDEX [PK_Table1] ON [Table1] REBUILD
CREATE UNIQUE INDEX [IX_Table1_Name] ON [Table1] ( [Tab1_Name] ) DROP INDEX [IX_Table1_Name] ON [Table1] ALTER INDEX [IX_Table1_Name] ON [Table1] REBUILD
CREATE NONCLUSTERED INDEX [IX_Table2] ON [Table2] ( [Tab2_Name], [Tab2_City] ) INCLUDE ( [Tab2_PhoneNo] ) DROP INDEX [IX_Table2] ON [Table2] ALTER INDEX [IX_Table2] ON [Table2] REBUILD
sELECT
TableName = t.name,
IndexName = ind.name,
--IndexId = ind.index_id,
ColumnId = ic.index_column_id,
ColumnName = col.name,
key_ordinal,
ind.type_desc
--ind.*,
--ic.*,
--col.*
FROM
sys.indexes ind
INNER JOIN
sys.index_columns ic ON ind.object_id = ic.object_id and ind.index_id = ic.index_id
INNER JOIN
sys.columns col ON ic.object_id = col.object_id and ic.column_id = col.column_id
INNER JOIN
sys.tables t ON ind.object_id = t.object_id
WHERE
ind.is_primary_key = 0
AND ind.is_unique = 0
AND ind.is_unique_constraint = 0
AND t.is_ms_shipped = 0
and t.name='CompanyReconciliation' --table name
and key_ordinal>0
ORDER BY
t.name, ind.name, ind.index_id, ic.index_column_id
SQL Server 2014工作解决方案。我在这里只包含了少量的输出字段,但您可以随意添加任何您喜欢的字段。
SELECT
o.object_id AS objectId
,o.name AS objectName
,i.index_id AS indexId
,i.name AS indexName
,i.type_desc AS typeDesc
,ic.index_column_id AS indexColumnId
,ic.key_ordinal AS keyOrdinal
,ic.is_included_column AS isIncludedColumn
,ic.column_id AS columnId
,c.name AS columnName
FROM {database}.sys.objects AS o
INNER JOIN {database}.sys.columns AS c ON
c.object_id = o.object_id
AND o.type = 'U'
INNER JOIN {database}.sys.indexes AS i ON
i.object_id = o.object_id
INNER JOIN {database}.sys.index_columns AS ic ON
ic.object_id = i.object_id
AND ic.index_id = i.index_id
AND ic.column_id = c.column_id
ORDER BY
o.object_id
,i.index_id
,ic.index_column_id
我可以大胆回答这个饱和的问题吗?
这是@marc_s答案的自由重做,混合了来自@Tim Ford的一些东西,目标是有一个更干净和更简单的结果集和最终显示和排序,以满足我当前的需要。
SELECT
OBJECT_SCHEMA_NAME(t.[object_id],DB_ID()) AS [Schema],
t.[name] AS [TableName],
ind.[name] AS [IndexName],
col.[name] AS [ColumnName],
ic.column_id AS [ColumnId],
ind.[type_desc] AS [IndexTypeDesc],
col.is_identity AS [IsIdentity],
ind.[is_unique] AS [IsUnique],
ind.[is_primary_key] AS [IsPrimaryKey],
ic.[is_descending_key] AS [IsDescendingKey],
ic.[is_included_column] AS [IsIncludedColumn]
FROM
sys.indexes ind
INNER JOIN
sys.index_columns ic
ON ind.object_id = ic.object_id AND ind.index_id = ic.index_id
INNER JOIN
sys.columns col
ON ic.object_id = col.object_id and ic.column_id = col.column_id
INNER JOIN
sys.tables t
ON ind.object_id = t.object_id
WHERE
t.is_ms_shipped = 0
--ind.is_primary_key = 1 -- include or not pks, etc
--AND ind.is_unique = 0
--AND ind.is_unique_constraint = 0
ORDER BY
[Schema],
TableName,
IndexName,
[ColumnId],
ColumnName
正确的一个在这里(当我们在一个表上有多个索引时,以上所有帖子都会给出笛卡尔积结果)
select s.name, t.name, i.name, c.name from sys.tables t
inner join sys.schemas s on t.schema_id = s.schema_id
inner join sys.indexes i on i.object_id = t.object_id
inner join sys.index_columns ic on ic.object_id = t.object_id
AND i.index_id = ic.index_id
inner join sys.columns c on c.object_id = t.object_id
and ic.column_id = c.column_id
where i.index_id > 0
and i.type in (1, 2) -- clustered & nonclustered only
and i.is_primary_key = 0 -- do not include PK indexes
and i.is_unique_constraint = 0 -- do not include UQ
and i.is_disabled = 0
and i.is_hypothetical = 0
and ic.key_ordinal > 0
AND t.name = 'DimCustomer'
order by ic.key_ordinal
使用SQL Server 2016,这给出了所有索引的完整列表,并包含每个表的转储,以便您可以查看表之间的关系。它还显示包含在覆盖索引中的列:
select t.name TableName, i.name IdxName, c.name ColName
, ic.index_column_id ColPosition
, i.type_desc Type
, case when i.is_primary_key = 1 then 'Yes' else '' end [Primary?]
, case when i.is_unique = 1 then 'Yes' else '' end [Unique?]
, case when ic.is_included_column = 0 then '' else 'Yes - Included' end [CoveredColumn?]
, 'indexes >>>>' [*indexes*], i.*, 'index_columns >>>>' [*index_columns*]
, ic.*, 'tables >>>>' [*tables*]
, t.*, 'columns >>>>' [*columns*], c.*
from sys.index_columns ic
join sys.tables t on t.object_id = ic.object_id
join sys.columns c on c.object_id = t.object_id and c.column_id = ic.column_id
join sys.indexes i on i.object_id = t.object_id and i.index_id = ic.index_id
order by TableName, IdxName, ColPosition