正确的一个在这里(当我们在一个表上有多个索引时，以上所有帖子都会给出笛卡尔积结果)

select s.name, t.name, i.name, c.name from sys.tables t
inner join sys.schemas s on t.schema_id = s.schema_id
inner join sys.indexes i on i.object_id = t.object_id
inner join sys.index_columns ic on ic.object_id = t.object_id 
                                  AND i.index_id = ic.index_id
inner join sys.columns c on c.object_id = t.object_id 
                                  and  ic.column_id = c.column_id
where i.index_id > 0    
 and i.type in (1, 2) -- clustered & nonclustered only
 and i.is_primary_key = 0 -- do not include PK indexes
 and i.is_unique_constraint = 0 -- do not include UQ
 and i.is_disabled = 0
 and i.is_hypothetical = 0
 and ic.key_ordinal > 0
 AND  t.name = 'DimCustomer'
order by ic.key_ordinal

我更新了KFD9的答案。

我调整了他们的版本，以支持include-specification，而不使用已弃用的indexkey_property

这为索引和约束提供了create和drop语句。

with indexes as (
    SELECT
      schema_name(schema_id) as SchemaName, OBJECT_NAME(si.object_id) as TableName, si.name as IndexName,
      (CASE is_primary_key WHEN 1 THEN 'PK' ELSE '' END) as PK,
      (CASE is_unique WHEN 1 THEN '1' ELSE '0' END)+' '+
      (CASE si.type WHEN 1 THEN 'C' WHEN 3 THEN 'X' ELSE 'B' END)+' ' as 'Type',  -- B=basic, C=Clustered, X=XML
      (select string_agg(CAST('[' + c.name + ']' + case when is_descending_key = 1 then ' DESC' else '' end AS NVARCHAR(MAX)), ',') within group (order by index_column_id) 
         from sys.index_columns ic JOIN sys.columns c on ic.column_id = c.column_id and ic.object_id = c.object_id where ic.index_id = si.index_id and ic.object_id = si.object_id and ic.is_included_column = 0) Cols,
      (select string_agg(CAST('[' + c.name + ']' + case when is_descending_key = 1 then ' DESC' else '' end AS NVARCHAR(MAX)), ',') within group (order by index_column_id) 
         from sys.index_columns ic JOIN sys.columns c on ic.column_id = c.column_id and ic.object_id = c.object_id where ic.index_id = si.index_id and ic.object_id = si.object_id and ic.is_included_column = 1) IncludedCols,
      (select count(*) from sys.index_columns ic where ic.index_id = si.index_id and ic.object_id = si.object_id) IndexColsCount
    FROM sys.indexes as si
    LEFT JOIN sys.objects as so on so.object_id=si.object_id
    WHERE index_id>0 -- omit the default heap
      and OBJECTPROPERTY(si.object_id,'IsMsShipped')=0 -- omit system tables
      and not (schema_name(schema_id)='dbo' and OBJECT_NAME(si.object_id)='sysdiagrams') -- omit sysdiagrams
)
SELECT SchemaName, TableName, IndexName,
  (CASE pk
    WHEN 'PK' THEN 'ALTER '+
     'TABLE ['+SchemaName+'].['+TableName+'] ADD CONSTRAINT ['+IndexName+'] PRIMARY KEY'+
     (CASE substring(Type,3,1) WHEN 'C' THEN ' CLUSTERED' ELSE '' END)
    ELSE 'CREATE '+
     (CASE substring(Type,1,1) WHEN '1' THEN 'UNIQUE ' ELSE '' END)+
     (CASE substring(Type,3,1) WHEN 'C' THEN 'CLUSTERED ' ELSE '' END)+
     'INDEX ['+IndexName+'] ON ['+SchemaName+'].['+TableName+']'
    END)+
  ' ('+Cols+')'+
  isnull(' include ('+IncludedCols+')', '')+
  '' as CreateIndex,
    CASE pk
    WHEN 'PK' THEN 'ALTER '+
     'TABLE ['+SchemaName+'].['+TableName+'] DROP CONSTRAINT ['+IndexName+'] '
    ELSE 'DROP INDEX ['+IndexName+'] ON ['+SchemaName+'].['+TableName + ']'
    END AS DropIndex,
    IndexColsCount
FROM indexes
ORDER BY SchemaName,TableName,IndexName

在Oracle中

select CONNECYBY.SCHEMA_NAME,CONNECYBY.TABLE_NAME,CONNECYBY.INDEX_NAME,CONNECYBY.COLUMN_NAME
from (  select TABLE_OWNER SCHEMA_NAME,TABLE_NAME,INDEX_NAME,COLUMN_POSITION,trim(',' from sys_connect_by_path(COLUMN_NAME,',')) COLUMN_NAME
        from DBA_IND_COLUMNS
        start with COLUMN_POSITION = 1
        connect by TABLE_OWNER = prior TABLE_OWNER
        and TABLE_NAME = prior TABLE_NAME
        and INDEX_NAME = prior INDEX_NAME
        and COLUMN_POSITION = prior COLUMN_POSITION + 1) CONNECYBY
join (  select TABLE_OWNER SCHEMA_NAME,TABLE_NAME,INDEX_NAME,max(COLUMN_POSITION) COLUMN_POSITION
        from DBA_IND_COLUMNS
        group by TABLE_OWNER,TABLE_NAME,INDEX_NAME) MAX_CONNECYBY
on (    CONNECYBY.SCHEMA_NAME = MAX_CONNECYBY.SCHEMA_NAME
        and CONNECYBY.TABLE_NAME = MAX_CONNECYBY.TABLE_NAME
        and CONNECYBY.INDEX_NAME = MAX_CONNECYBY.INDEX_NAME
        and CONNECYBY.COLUMN_POSITION = MAX_CONNECYBY.COLUMN_POSITION)
order by CONNECYBY.SCHEMA_NAME,CONNECYBY.TABLE_NAME,CONNECYBY.INDEX_NAME

SQL Server 与

CONNECTBY(SCHEMA_NAME,TABLE_NAME,INDEX_NAME,INDEX_COLUMN_ID,COLUMN_NAME) 
as 
    (   select SCHEMAS.NAME SCHEMA_NAME
            , TABLES.NAME TABLE_NAME
            , INDEXES.NAME INDEX_NAME
            , INDEX_COLUMNS.INDEX_COLUMN_ID INDEX_COLUMN_ID
            , cast(COLUMNS.NAME AS VARCHAR(MAX)) COLUMN_NAME
        from SYS.INDEXES
        join SYS.TABLES on (INDEXES.OBJECT_ID = TABLES.OBJECT_ID)
        join SYS.SCHEMAS on (TABLES.SCHEMA_ID = SCHEMAS.SCHEMA_ID)
        join SYS.INDEX_COLUMNS on ( INDEXES.OBJECT_ID = INDEX_COLUMNS.OBJECT_ID 
                                    and INDEX_COLUMNS.INDEX_ID = INDEXES.INDEX_ID)
        join SYS.COLUMNS on (   INDEXES.OBJECT_ID = COLUMNS.OBJECT_ID 
                                and INDEX_COLUMNS.COLUMN_ID = COLUMNS.COLUMN_ID)
        where INDEX_COLUMNS.INDEX_COLUMN_ID = 1
        union all
        select SCHEMAS.NAME SCHEMA_NAME
            , TABLES.NAME TABLE_NAME
            , INDEXES.NAME INDEX_NAME
            , INDEX_COLUMNS.INDEX_COLUMN_ID INDEX_COLUMN_ID
            , cast(PRIOR.COLUMN_NAME + ',' + COLUMNS.NAME AS VARCHAR(MAX)) COLUMN_NAME
        from SYS.INDEXES
        join SYS.TABLES on (INDEXES.OBJECT_ID = TABLES.OBJECT_ID)
        join SYS.SCHEMAS on (TABLES.SCHEMA_ID = SCHEMAS.SCHEMA_ID)
        join SYS.INDEX_COLUMNS on ( INDEXES.OBJECT_ID = INDEX_COLUMNS.OBJECT_ID 
                                    and INDEX_COLUMNS.INDEX_ID = INDEXES.INDEX_ID)
        join SYS.COLUMNS on (   INDEXES.OBJECT_ID = COLUMNS.OBJECT_ID 
                                and INDEX_COLUMNS.COLUMN_ID = COLUMNS.COLUMN_ID)
        join CONNECTBY as PRIOR on (SCHEMAS.NAME = PRIOR.SCHEMA_NAME 
                                    and TABLES.NAME = PRIOR.TABLE_NAME 
                                    and INDEXES.NAME = PRIOR.INDEX_NAME 
                                    and INDEX_COLUMNS.INDEX_COLUMN_ID = PRIOR.INDEX_COLUMN_ID + 1))
select CONNECTBY.SCHEMA_NAME,CONNECTBY.TABLE_NAME,CONNECTBY.INDEX_NAME,CONNECTBY.COLUMN_NAME
from CONNECTBY
join (  select  SCHEMA_NAME
                , TABLE_NAME
                , INDEX_NAME
                , MAX(INDEX_COLUMN_ID) INDEX_COLUMN_ID
        from CONNECTBY 
        group by SCHEMA_NAME,TABLE_NAME,INDEX_NAME) MAX_CONNECTBY
        on (CONNECTBY.SCHEMA_NAME = MAX_CONNECTBY.SCHEMA_NAME
            and CONNECTBY.TABLE_NAME = MAX_CONNECTBY.TABLE_NAME
            and CONNECTBY.INDEX_NAME = MAX_CONNECTBY.INDEX_NAME
            and CONNECTBY.INDEX_COLUMN_ID = MAX_CONNECTBY.INDEX_COLUMN_ID)
order by CONNECTBY.SCHEMA_NAME,CONNECTBY.TABLE_NAME,CONNECTBY.INDEX_NAME

我没有经过，但是我在原作者发布的查询中得到了我想要的东西。

我使用它(没有条件/过滤器)来满足我的需求，但它给出了不正确的结果

主要问题是在index_id上没有连接条件的情况下得到叉乘

SELECT S.NAME SCHEMA_NAME,T.NAME TABLE_NAME,I.NAME INDEX_NAME,C.NAME COLUMN_NAME
  FROM SYS.TABLES T
       INNER JOIN SYS.SCHEMAS S
    ON T.SCHEMA_ID = S.SCHEMA_ID
       INNER JOIN SYS.INDEXES I
    ON I.OBJECT_ID = T.OBJECT_ID
       INNER JOIN SYS.INDEX_COLUMNS IC
    ON IC.OBJECT_ID = T.OBJECT_ID
       INNER JOIN SYS.COLUMNS C
    ON C.OBJECT_ID  = T.OBJECT_ID
   **AND IC.INDEX_ID    = I.INDEX_ID**
   AND IC.COLUMN_ID = C.COLUMN_ID
 WHERE 1=1

ORDER BY I.NAME,I.INDEX_ID,IC.KEY_ORDINAL

以下工作在SQL Server 2014/2016以及任何Microsoft Azure SQL数据库。

生成一个全面的结果集，可以很容易地导出到Notepad/Excel中进行切片和切块

表名 索引名称 指数描述 索引列-按顺序 包括列-按顺序

 SELECT '[' + s.NAME + '].[' + o.NAME + ']' AS 'table_name'
    ,+ i.NAME AS 'index_name'
    ,LOWER(i.type_desc) + CASE 
        WHEN i.is_unique = 1
            THEN ', unique'
        ELSE ''
        END + CASE 
        WHEN i.is_primary_key = 1
            THEN ', primary key'
        ELSE ''
        END AS 'index_description'
    ,STUFF((
            SELECT ', [' + sc.NAME + ']' AS "text()"
            FROM syscolumns AS sc
            INNER JOIN sys.index_columns AS ic ON ic.object_id = sc.id
                AND ic.column_id = sc.colid
            WHERE sc.id = so.object_id
                AND ic.index_id = i1.indid
                AND ic.is_included_column = 0
            ORDER BY key_ordinal
            FOR XML PATH('')
            ), 1, 2, '') AS 'indexed_columns'
    ,STUFF((
            SELECT ', [' + sc.NAME + ']' AS "text()"
            FROM syscolumns AS sc
            INNER JOIN sys.index_columns AS ic ON ic.object_id = sc.id
                AND ic.column_id = sc.colid
            WHERE sc.id = so.object_id
                AND ic.index_id = i1.indid
                AND ic.is_included_column = 1
            FOR XML PATH('')
            ), 1, 2, '') AS 'included_columns'
FROM sysindexes AS i1
INNER JOIN sys.indexes AS i ON i.object_id = i1.id
    AND i.index_id = i1.indid
INNER JOIN sysobjects AS o ON o.id = i1.id
INNER JOIN sys.objects AS so ON so.object_id = o.id
    AND is_ms_shipped = 0
INNER JOIN sys.schemas AS s ON s.schema_id = so.schema_id
WHERE so.type = 'U'
    AND i1.indid < 255
    AND i1.STATUS & 64 = 0 --index with duplicates
    AND i1.STATUS & 8388608 = 0 --auto created index
    AND i1.STATUS & 16777216 = 0 --stats no recompute
    AND i.type_desc <> 'heap'
    AND so.NAME <> 'sysdiagrams'
ORDER BY table_name
    ,index_name;

使用SQL Server 2016，这给出了所有索引的完整列表，并包含每个表的转储，以便您可以查看表之间的关系。它还显示包含在覆盖索引中的列:

select t.name TableName, i.name IdxName, c.name ColName
    , ic.index_column_id ColPosition
    , i.type_desc Type
    , case when i.is_primary_key = 1 then 'Yes' else '' end [Primary?]
    , case when i.is_unique = 1 then 'Yes' else '' end [Unique?]
    , case when ic.is_included_column = 0 then '' else 'Yes - Included' end [CoveredColumn?]
    , 'indexes >>>>' [*indexes*], i.*, 'index_columns >>>>' [*index_columns*]
    , ic.*, 'tables >>>>' [*tables*]
    , t.*, 'columns >>>>' [*columns*], c.*
from sys.index_columns ic
join sys.tables t on t.object_id = ic.object_id
join sys.columns c on c.object_id = t.object_id and c.column_id = ic.column_id
join sys.indexes i on i.object_id = t.object_id and i.index_id = ic.index_id
order by TableName, IdxName, ColPosition