简单易行。您可以像下面这样从URI执行此操作!

public void getContents(Uri uri)
{
    Cursor vidCursor = getActivity.getContentResolver().query(uri, null, null,
                                                              null, null);
    if (vidCursor.moveToFirst())
    {
        int column_index =
        vidCursor .getColumnIndexOrThrow(MediaStore.Images.Media.DATA);
        Uri filePathUri = Uri.parse(vidCursor .getString(column_index));
        String video_name =  filePathUri.getLastPathSegment().toString();
        String file_path=filePathUri.getPath();
        Log.i("TAG", video_name + "\b" file_path);
    }
}

从图库中获取图像后，只需要在下面的方法中传递URI，仅适用于Android 4.4 (KitKat):

public String getPath(Uri contentUri) {// Will return "image:x*"

    String wholeID = DocumentsContract.getDocumentId(contentUri);

    // Split at colon, use second item in the array
    String id = wholeID.split(":")[1];

    String[] column = { MediaStore.Images.Media.DATA };

    // Where id is equal to
    String sel = MediaStore.Images.Media._ID + "=?";

    Cursor cursor = getContentResolver().query(
            MediaStore.Images.Media.EXTERNAL_CONTENT_URI, column, sel,
            new String[] { id }, null);

    String filePath = "";

    int columnIndex = cursor.getColumnIndex(column[0]);

    if (cursor.moveToFirst()) {
        filePath = cursor.getString(columnIndex);
    }

    cursor.close();
    return filePath;
}

这些答案在所有情况下都不适用。我必须直接去谷歌的文档https://developer.android.com/guide/topics/providers/document-provider.html关于这个主题，并发现这个有用的方法:

private Bitmap getBitmapFromUri(Uri uri) throws IOException {
    ParcelFileDescriptor parcelFileDescriptor =
    getContentResolver().openFileDescriptor(uri, "r");
    FileDescriptor fileDescriptor = parcelFileDescriptor.getFileDescriptor();
    Bitmap image = BitmapFactory.decodeFileDescriptor(fileDescriptor);
    parcelFileDescriptor.close();
    return image;
}

您可以使用此位图在图像视图中显示它。

对奥利奥

Uri uri = data.getData(); 
File file = new File(uri.getPath());//create path from uri
final String[] split = file.getPath().split(":");//split the path.
filePath = split[1];//assign it to a string(your choice).

对于Oreo以下的所有版本，我已经做了这个方法，从uri中获取真实路径

 @SuppressLint("NewApi")
    public static String getFilePath(Context context, Uri uri) throws URISyntaxException {
        String selection = null;
        String[] selectionArgs = null;
        // Uri is different in versions after KITKAT (Android 4.4), we need to
        if (Build.VERSION.SDK_INT >= 19 && DocumentsContract.isDocumentUri(context.getApplicationContext(), uri)) {
            if (isExternalStorageDocument(uri)) {
                final String docId = DocumentsContract.getDocumentId(uri);
                final String[] split = docId.split(":");
                return Environment.getExternalStorageDirectory() + "/" + split[1];
            } else if (isDownloadsDocument(uri)) {
                final String id = DocumentsContract.getDocumentId(uri);
                uri = ContentUris.withAppendedId(
                        Uri.parse("content://downloads/public_downloads"), Long.valueOf(id));
            } else if (isMediaDocument(uri)) {
                final String docId = DocumentsContract.getDocumentId(uri);
                final String[] split = docId.split(":");
                final String type = split[0];
                if ("image".equals(type)) {
                    uri = MediaStore.Images.Media.EXTERNAL_CONTENT_URI;
                } else if ("video".equals(type)) {
                    uri = MediaStore.Video.Media.EXTERNAL_CONTENT_URI;
                } else if ("audio".equals(type)) {
                    uri = MediaStore.Audio.Media.EXTERNAL_CONTENT_URI;
                }
                selection = "_id=?";
                selectionArgs = new String[]{
                        split[1]
                };
            }
        }
        if ("content".equalsIgnoreCase(uri.getScheme())) {


          if (isGooglePhotosUri(uri)) {
              return uri.getLastPathSegment();
           }

            String[] projection = {
                    MediaStore.Images.Media.DATA
            };
            Cursor cursor = null;
            try {
                cursor = context.getContentResolver()
                        .query(uri, projection, selection, selectionArgs, null);
                int column_index = cursor.getColumnIndexOrThrow(MediaStore.Images.Media.DATA);
                if (cursor.moveToFirst()) {
                    return cursor.getString(column_index);
                }
            } catch (Exception e) {
                e.printStackTrace();
            }
        } else if ("file".equalsIgnoreCase(uri.getScheme())) {
            return uri.getPath();
        }
        return null;
    }

    public static boolean isExternalStorageDocument(Uri uri) {
        return "com.android.externalstorage.documents".equals(uri.getAuthority());
    }

    public static boolean isDownloadsDocument(Uri uri) {
        return "com.android.providers.downloads.documents".equals(uri.getAuthority());
    }

    public static boolean isMediaDocument(Uri uri) {
        return "com.android.providers.media.documents".equals(uri.getAuthority());
    }

  public static boolean isGooglePhotosUri(Uri uri) {
    return "com.google.android.apps.photos.content".equals(uri.getAuthority());
}

下面API 19使用这段代码从URI中获取文件路径:

public String getRealPathFromURI(Context context, Uri contentUri) {
  Cursor cursor = null;
  try { 
    String[] proj = { MediaStore.Images.Media.DATA };
    cursor = context.getContentResolver().query(contentUri,  proj, null, null, null);
    int column_index = cursor.getColumnIndexOrThrow(MediaStore.Images.Media.DATA);
    cursor.moveToFirst();
    return cursor.getString(column_index);
  } finally {
    if (cursor != null) {
      cursor.close();
    }
  }
}

我用一行代码做到这一点:

val bitmap = MediaStore.Images.Media。getBitmap (contentResolver uri)

在onActivityResult中看起来是这样的:

override fun onActivityResult(requestCode: Int, resultCode: Int, data: Intent?) {
    if (resultCode == Activity.RESULT_OK && requestCode == REQUEST_CODE_IMAGE_PICKER ) {
        data?.data?.let { imgUri: Uri ->
            val bitmap = MediaStore.Images.Media.getBitmap(contentResolver, imgUri)
        }
    }
}