这个解决方案适用于所有情况:

在某些情况下，从URL中获取路径太难了。那你为什么需要路径?把文件复制到其他地方?你不需要路径。

public void SavePhotoUri (Uri imageuri, String Filename){

    File FilePath = context.getDir(Environment.DIRECTORY_PICTURES,Context.MODE_PRIVATE);
    try {
        Bitmap selectedImage = MediaStore.Images.Media.getBitmap(context.getContentResolver(), imageuri);
        String destinationImagePath = FilePath + "/" + Filename;
        FileOutputStream destination = new FileOutputStream(destinationImagePath);
        selectedImage.compress(Bitmap.CompressFormat.JPEG, 100, destination);
        destination.close();
    }
    catch (Exception e) {
        Log.e("error", e.toString());
    }
}

对于那些搬到奇巧后有问题的人:

这将从MediaProvider, DownloadsProvider和ExternalStorageProvider获取文件路径，同时回落到非官方的ContentProvider方法https://stackoverflow.com/a/20559175/690777

这里您可以得到文件的名称

String[] projection = {MediaStore.MediaColumns.DISPLAY_NAME};
                    Uri uri = data.getData();
                    String fileName = null;
                    ContentResolver cr = getActivity().getApplicationContext().getContentResolver();

                    Cursor metaCursor = cr.query(uri,
                            projection, null, null, null);
                    if (metaCursor != null) {
                        try {
                            if (metaCursor.moveToFirst()) {
                                fileName = metaCursor.getString(0);
                            }
                        } finally {
                            metaCursor.close();
                        }
                    }

既然上面的答案对我不起作用，下面是对我有效的解决方案:

对于>19和<=19 API级别。

这个方法涵盖了从uri中获取filePath的所有情况

/**
 * Get a file path from a Uri. This will get the the path for Storage Access
 * Framework Documents, as well as the _data field for the MediaStore and
 * other file-based ContentProviders.
 *
 * @param context The activity.
 * @param uri The Uri to query.
 * @author paulburke
 */
public static String getPath(final Context context, final Uri uri) {

    // DocumentProvider
    if ( Build.VERSION.SDK_INT >= Build.VERSION_CODES.KITKAT && DocumentsContract.isDocumentUri(context, uri)) {
        // ExternalStorageProvider
        if (isExternalStorageDocument(uri)) {
            final String docId = DocumentsContract.getDocumentId(uri);
            final String[] split = docId.split(":");
            final String type = split[0];

            if ("primary".equalsIgnoreCase(type)) {
                return Environment.getExternalStorageDirectory() + "/" + split[1];
            }else{
                Toast.makeText(context, "Could not get file path. Please try again", Toast.LENGTH_SHORT).show();
            }
        }
        // DownloadsProvider
        else if (isDownloadsDocument(uri)) {

            final String id = DocumentsContract.getDocumentId(uri);
            final Uri contentUri = ContentUris.withAppendedId(
                    Uri.parse("content://downloads/public_downloads"), Long.valueOf(id));

            return getDataColumn(context, contentUri, null, null);
        }
        // MediaProvider
        else if (isMediaDocument(uri)) {
            final String docId = DocumentsContract.getDocumentId(uri);
            final String[] split = docId.split(":");
            final String type = split[0];

            Uri contentUri = null;
            if ("image".equals(type)) {
                contentUri = MediaStore.Images.Media.EXTERNAL_CONTENT_URI;
            } else if ("video".equals(type)) {
                contentUri = MediaStore.Video.Media.EXTERNAL_CONTENT_URI;
            } else if ("audio".equals(type)) {
                contentUri = MediaStore.Audio.Media.EXTERNAL_CONTENT_URI;
            } else {
                contentUri = MediaStore.Files.getContentUri("external");
            }

            final String selection = "_id=?";
            final String[] selectionArgs = new String[] {
                    split[1]
            };

            return getDataColumn(context, contentUri, selection, selectionArgs);
        }
    }
    // MediaStore (and general)
    else if ("content".equalsIgnoreCase(uri.getScheme())) {
        return getDataColumn(context, uri, null, null);
    }
    // File
    else if ("file".equalsIgnoreCase(uri.getScheme())) {
        return uri.getPath();
    }

    return null;
}

这个解决方案适用于所有情况:

在某些情况下，从URL中获取路径太难了。那你为什么需要路径?把文件复制到其他地方?你不需要路径。

public void SavePhotoUri (Uri imageuri, String Filename){

    File FilePath = context.getDir(Environment.DIRECTORY_PICTURES,Context.MODE_PRIVATE);
    try {
        Bitmap selectedImage = MediaStore.Images.Media.getBitmap(context.getContentResolver(), imageuri);
        String destinationImagePath = FilePath + "/" + Filename;
        FileOutputStream destination = new FileOutputStream(destinationImagePath);
        selectedImage.compress(Bitmap.CompressFormat.JPEG, 100, destination);
        destination.close();
    }
    catch (Exception e) {
        Log.e("error", e.toString());
    }
}

尝试从Uri获取图像文件路径

public void getImageFilePath(Context context, Uri uri) {

    Cursor cursor = context.getContentResolver().query(uri, null, null, null, null);
    cursor.moveToFirst();
    String image_id = cursor.getString(0);
    image_id = image_id.substring(image_id.lastIndexOf(":") + 1);
    cursor.close();
    cursor = context.getContentResolver().query(android.provider.MediaStore.Images.Media.EXTERNAL_CONTENT_URI, null, MediaStore.Images.Media._ID + " = ? ", new String[]{image_id}, null);
    cursor.moveToFirst();
    String path = cursor.getString(cursor.getColumnIndex(MediaStore.Images.Media.DATA));
    cursor.close();
    upLoadImageOrLogo(path);
}